Suppose that you have a Markov chain with state space $E$ containing $0$. Assume that $$ p_{00}^{(2n)}=\binom{2n}{n}\left(\frac{1}{2}\right)^{2n-1}~~~\text{ and }~~~p_{00}^{(2n-1)}=0~~~\text{ for }n\in\mathbb{N}. $$ Is $0$ transient, positive recurrent or null recurrent?
Here https://math.stackexchange.com/questions/1019912/is-0-transient-positive-recurrent-or-null-recurrent
I already showed that $0$ is recurrent.
Now it remains to show whether $0$ is positive or null recurrent.
Therefore I have to show whether $$ \mathbb{E}_0(t(0))<\infty\text{ or }=\infty. $$
Here $t(0)$ denotes the first returning time of $0$.
How do I do this?
It is $$ \mathbb{E}_0(t(0))=\sum_{n\geq 1} 2n\mathbb{P}_0(t(0)=2n). $$
I am not sure how to compute $\mathbb{P}_0(t(0)=2n)$. I think it is $$ \mathbb{P}_0(t(0)=2n)=\frac{1}{4} (1-p_{00}^{2(n-1)}), $$ because it means starting in 0 one does not return to 0 within $2(n-1)$ steps and then going back to $0$ in 2 steps.
Is that right?
And if yes, how can I comoute the series then?