How can we find out the number of positive integer pairs with product less than a specific value. Can someone help me with this.
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This seems awfully similar to this question. However, it seems that that question has been put on hold. – robjohn Apr 05 '14 at 10:23
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I know one way. Let $a$ and $b$ be two positive numbers. Now let $max(a,b)=b$ so $ab<b^2$. Let $b^2=c$. Now $ab<c$.
Suppose we got a positive number $A$ and we wish two find two positive numbers $\alpha$ and $\beta$ s.t. $\alpha \beta < A$. Then from the first paragraph it is clear that the one sufficient but not necessary condition is that
max($\alpha$,$\beta$)<$\sqrt{A}$.
Let me again clarify that max($\alpha$,$\beta$)<$\sqrt{A}$ is not a necessary condition, but it is a sufficient condition.
user103816
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1This is not correct. Let $A=16$. You say that $\max{\alpha,\beta}<\sqrt{A}$. However, what about $\alpha=2$, $\beta=8$? $8>\sqrt{16}$. – abalter Jun 13 '14 at 21:13
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Hi @abalter , thankyou for pointing out the mistake. I've clarified it. If it is ok now then tell me. – user103816 Jun 14 '14 at 06:41
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