Questions tagged [abelian-groups]

For questions about abelian groups, including the basic theory of abelian groups as a topic in elementary group theory as well as more advanced topics (classification, structure theory, theory of $\mathbb{Z}$-modules as related to modules over other rings, homological algebra of abelian groups, etc.). Consider also using the tag (group-theory) or (modules) depending on the perspective of your question.

An abelian or commutative group is a group $(G,*)$ in which all elements commute: $$\forall a,b\in G\,\,, a*b=b*a\,.$$ Usually the product is denoted by $+$ in an abelian group, and the identity of the group by $0$. Abelian groups are also known as modules over the ring $\mathbb{Z}$ of integers.

Examples include the integers $\mathbb{Z}$ under addition, as well as the rationals $\mathbb{Q}$ under addition. In fact, every cyclic group is an abelian group. Non-examples include $S_3$, the symmetry group on three elements, as well as $\mathrm{SO}(3)$, the rotations in three dimensions.

The fundamental theorem of abelian groups says that all finite abelian groups are direct products of cyclic groups, themselves abelian.

3991 questions
2
votes
0 answers

Is there a name for this kind of subgroup?

Let $G$ be an abelian group, $H\subset G$ a subgroup such that if $nx\in H$ for $n\in \bf{Z}$ and $x\in G$ then $x\in H$. Is there a name for subgroups of abelian groups $H$ with this property?
2
votes
1 answer

Can the group homomorphism $\mathbb{Z} \to \mathbb{Z}/2\mathbb{Z}$ be extended to $\mathbb{Q}$?

We have the canonical projection $\pi:\mathbb{Z} \to \mathbb{Z}/2\mathbb{Z}$, which is a group homomorphism. The most natural way I can think of to try extending this to a group homomorphism $\phi:\mathbb{Q} \to \mathbb{Z}/2\mathbb{Z}$ would be to…
2
votes
1 answer

creating a basis of a subgroup using the basis of an overgroup

Let's say we have torsion-free abelian group $G$ of rank $r$, so it has a basis $A = \left\{ g_1,...,g_r \right\}$. Let's also assume there is a subgroup $H$ of $G$ of the same rank $r$, so it has a basis $B = \left\{ h_1,...,h_r \right\}$. I would…
James
  • 749
  • 4
  • 12
2
votes
3 answers

Suppose $G$ Abelian and $f:G\rightarrow \Bbb Z$ is surjective with kernel K. Show $G \cong H + K$ where $H \cong \Bbb Z$

Suppose $G$ abelian and $f:G\rightarrow \mathbb Z$ is surjective with kernel $K$. Show that $G$ has a subgroup $H$ such that $H \cong \mathbb{Z}$ Show that $G \cong H\bigoplus K$ To get started: There exists $g \epsilon G$ such that…
KUSH
  • 364
  • 2
  • 11
2
votes
2 answers

The number of abelian groups up to isomophism of order $6^5$

The number of abelian groups up to isomophism of order $6^5$ is $a)\ 5\\ b)\ 7\\ c)\ 49\\ d)\ 65$
2
votes
2 answers

About sets of generators of $\mathbb Q$ as $\mathbb Z$-module

Let $G$ be the quotient group $\mathbb Q/\mathbb Z$. It is easy to show the following: If $\mathcal C$ is a set of generators of $G$ (as $\mathbb Z$-module) and $x\in\mathcal C$, then $\mathcal C\setminus\{x\}$ also generates $G$. In fact, let…
2
votes
1 answer

Is every abelian group a product of cyclic groups?

This lecture notes from John Jones https://www2.warwick.ac.uk/fac/sci/maths/people/staff/vincent/cohomology.pdf state that abelian groups are a product of cyclic groups (page 9). We know that this is true if the group is finite or finitely…
2
votes
0 answers

Finding a property for $G/Z(G)$ where $G$ is a nonabelian group

If $G$ is non-abelian group and $Z(G)$ is it's center, what is the least property for $G$ such that $\frac{G}{Z(G)}$ is abelian?
2
votes
1 answer

When is the quotient of two lattices in ${\mathbb Z}^2$ cyclic?

In this question, by a lattice I mean a full-rank subgroup of the group ${\mathbb Z}^2$. What I would like to know is: Can one give a comprehensible description of those lattices $\Lambda\subset{\mathbb Z}^2$ for which the quotient group ${\mathbb…
W-t-P
  • 4,629
1
vote
1 answer

Show that it is torsion

I am trying to solve the following exercise Let $G$ be an abelian group, and let $S\subset G$ be a subgroup. If $H$ is maximal with $H\cap S=\{0\}$, prove that $G/(H+S)$ is torsion. My attempt: I assume that there is nonzero $x\in G$ with…
YYF
  • 2,917
1
vote
4 answers

Subset of elements of a given order in a group

I'm almost certain this is true (I have even given a proof) but I keep getting this strange feeling that something is not quite right so I will ask... Let $G$ be an abelian group and let $r$ be a positive integer. Then set of elements of order $r$…
1
vote
1 answer

Does there exist an abelian group that can be made into $\mathbb{Q}$-module in more than one way?

Let $X$ and $Y$ denote $\mathbb{Z}$-modules. Then if $X$ and $Y$ have equal underlying abelian groups, we may deduce that $X=Y$. Is this still true if we replace $\mathbb{Z}$ with $\mathbb{Q}$? Equivalently, does there exist an abelian group that…
goblin GONE
  • 67,744
1
vote
0 answers

Normal abelian subgroup of a solvable group

Possible Duplicate: A Nontrivial Subgroup of a Solvable Group How to find a normal abelian subgroup in a solvable group? Could someone help me with this proof? Let $G$ be a solvable group and $H$ a nontrivial normal subgroup of $G$. Then $H$…
stacy
  • 159
1
vote
2 answers

Cosets and Lagrange's Theorem

This question is under the topic of Cosets and lagrange theorem. Now Is it true that if $G$ is a group that contains a subgroup $H_1$ of order $n$ and a subgroup $H_2$ of order $k$, then $G$ must contain a subgroup of order $nk$? Really need an…
1
vote
1 answer

Confused by proof of Abelian group whose order divisible by prime has element divisible by prime.

I have a problem understanding the assumptions for the proof of this theorem Theorem: If $A$ is abelian with order $a$ divisible by prime $p$, then $A$ has an element of order $p$. The proof goes as follows: Obviously true if $|A|=p$. We may…
Gnugs
  • 11