Questions tagged [abstract-algebra]

For questions about monoids, groups, rings, modules, fields, vector spaces, algebras over fields, various types of lattices, and other such algebraic objects. Associate with related tags like [group-theory], [ring-theory], [modules], etc. as necessary to clarify which topic of abstract algebra is most related to your question and help other users when searching.

Abstract algebra is the study of algebraic objects, i.e. sets endowed with one or more operations on the elements of those sets. In particular, the study of abstract algebra considers the algebraic structures and properties of which such operations induce. It can be considered as the generalization of the study of the algebraic structure of the integers and real numbers (arithmetic), or the study of matrices and vector spaces (linear algebra).

Some algebraic objects are monoids, groups, rings, fields, vector spaces, modules, algebras, and categories, among many other less prominent objects.

Examples

  1. The set of non-negative integers $\mathbb{N} = \{0,1,2,3,\dotsc\}$ is a monoid under the operation $+$.

  2. The integers $\mathbb{Z} = \{\dotsc,-1,0,1,\dotsc\}$ under the binary operation of $+$ form a group.

  3. Furthermore, $\mathbb{Z}$ has the structure of a ring when you consider it as being equipped with both addition and multiplication.

  4. The real numbers $\mathbb{R}$ with their usual addition and multiplication form a field.

  5. The set of $n\times n$ matrices with entries in $\mathbb{R}$ with matrix addition and multiplication form a ring.

  6. The set of $1\times n$ vectors over the real numbers, with vector addition, and multiplication by elements of the $n\times n$ real matrices on the right are an example of a module for the ring of matrices.

In addition to studying the objects themselves, abstract algebra considers homomorphisms between the objects and various constructions and tools, which are useful for studying the objects.

85022 questions
8
votes
3 answers

the Gaussian integers are isomorphic to $\mathbb{Z}[x]/(x^2+1)$

I am trying to prove that $\mathbb{Z}[i]\cong \mathbb{Z}[x]/(x^2+1)$. My initial plan was to use the first isomorphism theorem. I showed that there is a map $\phi: \mathbb{Z}[x] \rightarrow \mathbb{Z}[i]$, given by $\phi(f)=f(i).$ This map is onto…
kslote1
  • 302
8
votes
2 answers

binary operation and closure property

Many authors define group as a non empty set with the binary operation $*$ with the following 4 properties: closure, associative, identity, inverse. My question is that it is obvious that a set with a binary operation is always closed, then why…
8
votes
2 answers

Why is factorization in the localization of a UFD actually unique?

I was reading Arturo Magidin's answer here, which states that the localization of a UFD over a multiplicative subset not containing $0$ is still a UFD. It makes sense that a factorization into units and irreducibles exists, but I don't see…
Kally
  • 903
8
votes
2 answers

The only group automorphisms of the additive group of real numbers that are also order isomorphisms are multiplication by positive real numbers

I am looking for a proof of the fact that if $f:\mathbb{R}\to \mathbb{R}$ is a group automorphism of $(\mathbb{R},+)$ that also preserves order, then there exists a positive real number $c$ s.t. $f(x)=cx$ for all $x\in \mathbb{R}$. If anyone can…
BMI
  • 535
8
votes
1 answer

Galois group of $f(x) = x^5 + x - 1$ over $\mathbb{Q}$

I'm trying to compute the Galois group of the quintic polynomial $f(x) = x^5 + x - 1$. I first decomposed $f(x)$ into irreducible factors $f(x) = g(x)h(x)$ where $g(x) = x^2 - x + 1$ and $h(x) = x^3 + x^2 - 1$. I denoted by $K_g$, $K_h$ the…
8
votes
3 answers

Automorphism from $\Bbb Q$ to $\Bbb Q$

Any automorphism of the group $\Bbb Q$ under addition is of the form $x\to qx$ for some $q\in \Bbb Q$. I don't know how to proceed in this. Even if i say that $1\to q$, I can't claim that $x\to qx$ since $\Bbb Q$ is not cyclic.
tattwamasi amrutam
  • 12,802
  • 5
  • 38
  • 73
8
votes
2 answers

Can two structures be embeddable in each other, but not isomorphic?

I was reading about isomorphisms and homomorphisms on general structures, and first came across the definition of an injective homomorphism, or an embedding. This made me curious, is it possible for two structures $A$ and $B$ to be embeddable in…
yunone
  • 22,333
8
votes
4 answers

Is there a name for the fact that an automorphism of a finite set produces periodical trajectories?

Let S be a finite set. f a bijection over S. If p is a point of S, I call "trajectory" of p the list ($f^0(p)$, $f^1(p)$, $f^2(p)$, $f^3(p)$... etc). It appears obvious to me that under such conditions any trajectory would be periodical. Is that…
8
votes
1 answer

Invariant Basis Number

How can we show that $R$ has IBN if either of the following conditions hold: All finitely generated subrings $S$ of $R$ have IBN, or $R$ has a subring $S$ with IBN such that $R$ is a finitely generated free $S$-module. Thanks.
gda
  • 361
8
votes
6 answers

Let $\mathbb{F}$ be a field and $R=\mathbb{F}[x]$, the polynomial ring over $\mathbb{F}$. Is the ideal $(x^2-1)$ maximal in $R$?

Let $\mathbb{F}$ be a field and $R=\mathbb{F}[x]$, the polynomial ring over $\mathbb{F}$. Is the ideal $(x^2-1)$ maximal in $R$? Does the answer depend upon $\mathbb{F}$? I think of this isomorphism $\mathbb{F}[x]/(x^2-1) \cong \mathbb{F}[i]$ where…
Idonknow
  • 15,643
8
votes
0 answers

Fields involving NaN

Motivation NaN as a value exists in IEEE floating-point numbers. Since every operation involving NaN has NaN as the outcome, IEEE floating-point numbers are not fields. I want to define a new algebraic structure so NaN could be…
Dannyu NDos
  • 2,029
8
votes
4 answers

Prove that $a^p = e$ in any non-cyclic group of order $p^2$

Hey all, I have an abstract algebra exam coming up and I am unsure of how to do this proof. Suppose $G$ is a non-cyclic group of order $p^2$, where $p$ is prime. Prove that $a^p = e$ ($e$ is the identity of the group) for each $a \in G$. Any help…
user9808
8
votes
3 answers

Do the positive rationals under multiplication contain a subgroup of finite index?

Do the positive rationals under multiplication contain a subgroup of finite index? Similar questions usually rely the fact a subgroup is divisible, however, this is not the case in this question. I have a feeling that the answer should be "no",…
user9479
8
votes
2 answers

Example of factorization in a polynomial ring which is not an UFD

I'm looking for a particular example of a polynomial ring $A[x]$, with $A$ integral domain, which is not an UFD. An easy example is $\mathbb{Z}[\sqrt{-5}][x]$, here $6 x^2 = (2x)(3x) = ((1+\sqrt{-5})x)((1-\sqrt{-5})x)$. I would like to find a ring…
8
votes
2 answers

What is the difference between an inner product space and an Algebra over a field?

From what I’ve gathered an algebra over a field is a vector space equipped with a bilinear form, and an inner product space is the same but that bilinear form satisfies certain extra axioms (symmetric, nondegenerate, etc.) . Is every inner product…