Questions tagged [abstract-algebra]

For questions about monoids, groups, rings, modules, fields, vector spaces, algebras over fields, various types of lattices, and other such algebraic objects. Associate with related tags like [group-theory], [ring-theory], [modules], etc. as necessary to clarify which topic of abstract algebra is most related to your question and help other users when searching.

Abstract algebra is the study of algebraic objects, i.e. sets endowed with one or more operations on the elements of those sets. In particular, the study of abstract algebra considers the algebraic structures and properties of which such operations induce. It can be considered as the generalization of the study of the algebraic structure of the integers and real numbers (arithmetic), or the study of matrices and vector spaces (linear algebra).

Some algebraic objects are monoids, groups, rings, fields, vector spaces, modules, algebras, and categories, among many other less prominent objects.

Examples

  1. The set of non-negative integers $\mathbb{N} = \{0,1,2,3,\dotsc\}$ is a monoid under the operation $+$.

  2. The integers $\mathbb{Z} = \{\dotsc,-1,0,1,\dotsc\}$ under the binary operation of $+$ form a group.

  3. Furthermore, $\mathbb{Z}$ has the structure of a ring when you consider it as being equipped with both addition and multiplication.

  4. The real numbers $\mathbb{R}$ with their usual addition and multiplication form a field.

  5. The set of $n\times n$ matrices with entries in $\mathbb{R}$ with matrix addition and multiplication form a ring.

  6. The set of $1\times n$ vectors over the real numbers, with vector addition, and multiplication by elements of the $n\times n$ real matrices on the right are an example of a module for the ring of matrices.

In addition to studying the objects themselves, abstract algebra considers homomorphisms between the objects and various constructions and tools, which are useful for studying the objects.

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What is the use of representation ring

In the representation theory, the representation ring is defined and some results can be expressed with the representation ring R(G). What is the benefit of having this extra definition and what insights can it provide?
sak
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What is the characteristic of a ring that does not contain an identity element?

Does a ring without an identity element even have a characteristic?
Jenny
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Difference between rings and modules

So, by definitions, it says that a module is when an abelian group is acted on by a ring. I understand the requirements of a ring, but not what a module is. For example, my teacher gave a module example Mnxn(nxn matrix)XV ->V. I interpret this as…
cakey
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Number of elements of group with specific order

Consider the group $(G,\cdot)$ where $$G=\left\{\left(\begin{matrix}1&a\\0&b\end{matrix}\right):a,b\in\mathbb{R}, b\neq0\right\}.$$ How many members of $G$ have order 2? My Attemt A member $M$ of $G$ will have order two iff $M^2=I$. I.e.…
Zugzwang14
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Abstract Algebra Cosets and Lagrange's Theorem

Suppose that $H$ is a subgroup of $S_4$ and that $H$ contains $(12)$ and $(234)$. Prove that $H = S_4$. Since $(234) \in H$ and $(12) \in H$, this means $(234)(12) \in H$ to get $(1342) \in H$, and the orders of the three cycle and the four cycle is…
KGTW
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A question about prime elements in integral domains

I have to show the following: Let $p \in R\setminus\{0\}$ then: $p$ is prime element in $R$ if and only if $(p)$ is a prime ideal in $R$. I have real problems doing so. I tried the following: $\Rightarrow$ let $p$ be a prime element in $R$, then we…
sxd
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Find the homogeneous polynomials whose set of values is closed under multiplication

Let $f(x_1,x_2,\dotsc,x_n)$ be a homogeneous polynomial. Let $$S=\{f(a_1,a_2,\dotsc,a_n)\mid a_1,a_2,\dotsc,a_n \in\Bbb Z\}.$$ If $S$ satisfies the following condition: for all $m,n\in S$, we have $mn\in S$. Can we determine all the homogeneous…
ziang chen
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No constant polynomials are irreducible?

No constant polynomials are irreducible? What does it mean? Is it because constant polynomials are units?
user88310
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How to check a set of ring is a subring?

To check a subset of a given ring is a subring, is it enough to check that the subset is closed under induced operations(multiplication and addition) or do I also need to show that it contains 0 and additive inverses of each element?
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Isomorphism between quotient rings of $\mathbb{Z}[x,y]$

I need to find the condition on $m,n\in\mathbb{Z}^+$ under which the following ring isomorphism holds: $$ \mathbb{Z}[x,y]/(x^2-y^n)\cong\mathbb{Z}[x,y]/(x^2-y^m). $$ My strategy is to first find a…
hxhxhx88
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Main use of tensor, symmetric and exterior algebras outside differential geometry?

So I've seen these defined when constructing differential forms and in the construction of integration of manifolds. However, these seem to be a standard subject in most graduate algebra books, yet, I've never seen them applied anywhere else than in…
user75789
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Non-commutative vector space

A field acting on an abelian group is called a vector space. Is there a name for a field acting on a non-abelian group? What I mean is a group $G$ a field $F$, and an operation $F \times G \to G$, $(a, x) \mapsto x^a$ such that: $x^0 = e$ $x^1 =…
Aleks
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Is it true that $a+bi$ is prime in $\mathbb{Z}[i]$ if and only if $a^2+b^2$ is prime in $\mathbb{Z}$?

Is it true that $a+bi$ is prime in $\mathbb{Z}[i]$ if and only if $a^2+b^2$ is prime in $\mathbb{Z}$? How can I prove this? Can anybody help me please?
habuji
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Does $f(x) \in \mathbb{Z}[x] \ $ have the same roots as $f(x) \in \mathbb{F}_p[x] \quad $?

Does $f(x)\in\mathbb{Z}[x]\ $ have the same roots of $f(x)\in\mathbb{F}_p[x] \quad$? Do the roots of a polynomial change when the coefficients of the polynomial are considered as elements of one ring or another? Would the answer to this change if…
badatmath
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What familiar group is G isomorphic to?

Let $G$ be the quotient $F_2/\langle a^4,b^4,aba^{-1}b^{-1} \rangle.$ a) What is a simplified form of $ab^8a^5b^{10}$? b) What is a normal form for the elements of $G$? c) What familiar group is G isomorphic to? My attempt: The quotient…
dxdydz
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