Questions tagged [algebraic-groups]

For questions about groups which have additional structure as algebraic varieties (the vanishing sets of collections of polynomials) which is compatible with their group structure. These include both linear algebraic groups as well as abelian varieties.

Consider using with the (group-theory) tag.

This tag is for questions about algebraic groups. There are two main types of algebraic groups: linear algebraic groups and abelian varieties. The prototypical example of a linear algebraic group is $\mathrm{GL}_n$, the group of $n\times n$ matrices. The prototypical example of an abelian variety is an elliptic curve, which is the set of solutions to an equation $y^2 = x^3 + Ax + B$.

Over a field $k$, an algebraic group consists of (i) an underlying set $G$ defined as an algebraic subset of either affine space $G \subset \mathbb{A}^n_k$ (in the case of linear algebraic groups) or projective space $G \subset \mathbb{P}^n_k$ (in the case of abelian varieties) and (ii) a group operation called multiplication, which is a polynomial function $m\colon G \times G \to G$ satisfying axioms of associativity, invertibility, and identity. The set $G$ is referred to as an algebraic variety, and it is endowed with the Zariski topology, which is defined as the coarsest topology such that all subsets $Z$, which are cut out by the vanishing of a collection of polynomials, are closed. These closed subsets $Z \subset G$ are also algebraic varieties, called sub-varieties. If $Z$ is closed under the restriction of the multiplication map, i.e. if $m(Z \times Z) \subset Z$, then $Z$ also inherits a group structure and is called an algebraic subgroup of $G$.

Note that here we have not required a variety to be irreducible, which is a condition used by some authors. We have also not required $k$ to be algebraically closed, as some authors do.

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symplectic groups are always split?

Let $F$ be a number field or a non-archimedean local field of characteristic $0$ or $p$ or archimedean field. Let $G$ be a symplectic group defined over $F$. I am wondering whether $G$ is always split. If it is not, it depends on the field $F$?
user29422
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Torus and dual torus

In the setting of algebraic/reductive group, there is a notion of dual group (defined from the dual root system). Is there an explicit way to see it, or to describe it? For instance if $T \simeq k^\times \times k^\times \subset G = GL(2)$, as…
Wirdspan
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Non-split algebraic group can be split at some local places?

Let me take an example for special orthogonal subgroup $SO(3)$. Let $F$ be a number field and $\alpha,\beta \in F^{\times}$ such that $x^2+\alpha y^2+ \beta z^2$ does not represent $0$. Let $J$ be a $3 \times 3$ diagonal matrix who diagonal entries…
Andrew
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Algebraic subgroups $ H $ of $ G $ such that $ H(k) = G(k) $

The following theorem can be found in Milne's book on algebraic groups (Theorem 1.45) and in his online course notes (Proposition 1.31): Theorem: Let $G$ be an algebraic group (= algebraic group scheme, not necessarily affine) over a field $ k $ and…
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Identity component and rational point over algebraically closed field

For an algebraic group $G$ over $\mathbb{C}$ (in general, an algebraically closed field with character $0$), let the identity component of G be denoted by $G_{0}$. I wonder whether the rational point of $G_0$ equals the identity component of $G$'s…
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closed connected nilpotent subgroup of solvable linear algebraic group

I am struggling with solving the following exercise in T.A springer's linear algebraic groups. I should add that in the context of the exercise $G$ is connected and solvable.
roy yanai
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In a solvable algebraic group all maximal tori are conjugate to each other

I want to prove the following statement: All maximal tori in a solvable algebraic group are conjugate to each other. I use the following facts: Theorem. Let $G$ be an irreducible solvable algebraic group and $T$ a torus complementary to its…
LinAlgMan
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generators for the multiplicative characters of a linear algebraic group

Let $G\leq \mathrm{GL}_n(\mathbb{C})$ be a linear algebraic group. Assume we know its defining ideal $$\mathcal{I}(G)=\langle f_\alpha \mid \alpha \in S\rangle \subseteq \mathbb{C}[x_{i,j}, 1/\mathrm{det}\mid 1\leq i,j\leq n]$$ for some finite set…
Daniel
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Verifying that $\operatorname{Res}_{E/F} \mathbb G_a$ is a split unipotent group

Let $G$ be a unipotent connected linear algebraic group over a field $F$. Then $G$ is called split if there is a series of closed subgroup schemes $1 = G_0 \subset G_1 \subset \cdots \subset G_t =G$ with each $G_i$ normal in $G_{i+1}$ and…
D_S
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Why the projection map to the semisimple part is a morphism for algebraic groups?

From Springer, Linear Algebraic Groups, first page of Chapter 3. Let $G$ be a commuative algebraic group. If we regard $G$ as a closed subgroup of $GL_{n}$, then we can identify its semisimple part $G_{s}$ and unipotent part $G_{u}$ with subgroups…
Bombyx mori
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Component Groups of Reductive Groups

Suppose $G$ is a reductive group that is not necessarily connected and $Z \subset G$ is a central subgroup. Suppose $G^0$ is the identity component of $G$. Is it true that $G/G^0Z= \pi_0(G/Z)$? I can see there is a surjection $G \twoheadrightarrow…
Alexander
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quotient of algebraic groups in Springer's book

In Springer's 'Linear Algebraic Groups', he proves that if $G$ is a linear (=affine) algebraic group and $H$ is a closed normal subgroup of $G$, then $G/H$ has a linear algebraic group structure with the usual group structure. But I think there's…
Seewoo Lee
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Open Subgroups of Affine algebraic groups

I saw this in a paper that I've been reading and I've been trying to figure out if this is true or not. Let $G(F)$ be a affine, simple, connected, adjoint, algebraic group over a local field endowed with the topology induced by the local field. …
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Are adjoint quotients of connected reductive groups of adjoint type?

Suppose we have a connected reductive group $G$, and consider the adjoint quotient $G^{ad}=G/Z(G)$. Is $G^{ad}$ a group of adjoint type? I'm having difficulty coming up with a counterexample.
A Nonny
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Meaning of linearization of an action

What means the following expression: Every action of an affine algebraic group on an affine algebraic variety can be linearized.
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