Questions tagged [analytic-functions]

For questions about analytic functions, which are real or complex functions locally given by a convergent power series.

An analytic function is a function that is locally given by a convergent power series. There exist both real analytic functions and complex analytic functions, categories that are similar in some ways, but different in others. Functions of each type are infinitely differentiable, but complex analytic functions exhibit properties that do not hold generally for real analytic functions. Besides, not all infinitely differentiable real function are analytic; for instance the fonction $f\colon\mathbb{R}\longrightarrow\mathbb{R}$ defined by $f(x)=\exp\left(-\frac1{x^2}\right)$ if $x\neq0$ and such that $f(0)=0$ is infinitely differentiable, but not analytic. On the other hand, every differentiable function from an open non-empty subset of $\mathbb C$ into $\mathbb C$ is analytic.

A function is analytic if and only if its Taylor series about $x_0$ converges to the function in some neighborhood for every $x_0$ in its domain.

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function with range ${\mathbb{C}\backslash (-\infty,o]}$

let f be an analytic function defined on $D=\{z\in{\mathbb{C}:\vert{z}\vert \lt1}\} $ such that the range of $f$ is contained in the set $\mathbb{C}\setminus (-\infty,0]$ is $f$ is conformal mapping? I know that analytic function is conformal at any…
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Non Analytic Functions Re z

Show that each function below is non-analytic by identifying two independent directions, along which the rates of change of the function are different: (a) Re z I don't fully understand this solution. Can anyone offer any other explanations that…
nixluke
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Showing $\frac{1}{z^3+z}$ to be analytic

$f(z)$ is analytic if $u_x = v_y$ and $u_y = -v_x$ where $u(z)$ and $v(z)$ are the real and complex part, respectively, of $f(z)$. However, $\frac{1}{z^3+z} = \frac{1}{(x+iy)^3+x+iy}$ doesn't seem to have a simple composition of a real and a complex…
Frank Vel
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Is the series $f(a)=\sum_{k} c_k a^{ib_k}$ an analytic function

Is the series $f(a)=\sum_{k} c_k a^{ib_k}$ an analytic function of $a\in \mathbb{R},a>0$ when $b_k\in \mathbb{R}, c_k\in \mathbb{C}$ is given as the parameter. Since $a^{ib_k}=\exp(ib_k\log(a))$, it is easy to see that $a^{ib_k}$ is analytic. But…
fractal
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