Questions tagged [bernoulli-numbers]

Questions on Bernoulli numbers, a special sequence of rational numbers that arise as the coefficients in the power series expansions of certain elementary functions.

The $n$th Bernoulli number $B_n$ is frequently defined in terms of a generating function:

$$\frac x{1-e^{-x}}=\sum\limits_{n = 0}^\infty B_n\frac{x^n}{n!}$$

The first few Bernoulli numbers are

\begin{align*} B_0 &=1 \\ B_1 &=\frac12 \\ B_2 &=\frac16 \\ B_3 &=0 \\ B_4 &=-\frac1{30} \\ B_5 &=0 \end{align*}

All Bernoulli numbers with $n$ odd, except for $B_1$, are zero.

Alternatively, the $n$th Bernoulli number is the constant coefficient in the $n$th Bernoulli polynomial $B_n(x)$, which can be defined in terms of a generating function as well:

$$\frac{te^{-xt}}{1-e^{-t}} = \sum_{k=0}^\infty B_n(x)\frac{t^n}{t!}$$

The Bernoulli numbers have deep connections to number theory, and frequently rise in combinatorics and asymptotic estimates of functions, as well.

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If a $\epsilon$ ℤ, show $a(a^m-1)B_m$ $\epsilon$ ℤ for all $m>0$

For all $m=2k+1$, $k=1,2,...$, $a(a^m-1)B_m=0$ $\epsilon$ ℤ since $B_m=0$. However, I'm not really sure how to proceed for $B_{2k}.$
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Proof of Bernoulli trials

I am studying Grinstead and Snell "Introduction to probability", but I am stuck at the proof of the Bernulli trials. I understood that (n,j) can be the number of j-size subsets (whatever the order) of n-size sets, but how is it that it is also the…
Antonello
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bernuoulli random variable possibility

Last season Ryan hit a homerun in about $7\%$ of his bats. Suppose we model at bat as the outcome of Bernoulli random variable. In a typical week, Ryan takes $25$ at bats. consider the following gamble. In a given week you have to pay your friend…
lee
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Link bernoulli numbers and bernoulli polynomials

I got a little question regarding the Bernoulli polynomials/numbers. Basically, I want to show that $$B_n(0) = -\frac{B_n(2\pi i)^n}{n!}$$ Where $B_n(x)$ the $n$-th Bernoulli polynomial and $B_n$ the $n$-th Bernoulli number). I have gotten quite…
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Is there a closed-form of $\sum_{n=0}^{\infty }\frac{|B_n|}{n!}=??$

Is there a closed-form of $$\sum_{n=0}^{\infty }\frac{|B_n|}{n!}=??$$ where $B_n$ Bernoulli number Thanks
user189855
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