Questions tagged [binomial-coefficients]

For questions involving the coefficients involved in the binomial theorem. $ \binom{n}{k}$ counts the subsets of size $k$ of a set of size $n$.

The binomial coefficient $\binom{n}{k}$ can be defined in several equivalent ways for $n$ and $k$ non-negative integers:

  1. The number of subsets of size $k$ of a set of size $n$.
  2. Element $k$ of row $n$ in Pascal's triangle (counting the first element or row as $0$).
  3. $\dfrac{n!}{k!(n-k)!}$
  4. The coefficient of $x^k$ in $(1+x)^n$.

The binomial theorem says that $$(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$$ using the convention that $0^0=1$.

Binomial coefficients can be extended for arbitrary complex $\alpha$ through the formula: $$\binom{\alpha}{k}=\frac{\alpha(\alpha-1)(\alpha-2)\dots(\alpha-k+1)}{k(k-1)(k-2)\dots1}$$

7695 questions
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What does this symbol mean in this equation?

I am reading up on n-choose-k problems (Binomial Coefficients). Wikipedia gives a multiplicative solution that is more efficient: I've taken a few calculus courses, and it reminds me of how you would use the summation symbol ∑, but it also kind…
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Prove identity based on binomial theorem

$\displaystyle \sum_{r=0}^{n-1} {2n-1 \choose r} = 2^{2n-2} $ Perhaps it can be proved by using sum of all combinations from r=0 to r=n is 2 to the power of n.
Wang Kah Lun
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refactoring binomial with negative power

I am reading Calculus Made Easy where in Chapter IV: $$(x+dx)^{-2}$$ Is refactored as: $$x^{-2}\left(1+\frac{dx}x\right)^{-2}$$ Could someone give me an insight into this refactoring? I can see from this question Negative Exponents in Binomial…
Welford
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The sum of the product of two binomial coefficients

This is really phsycics related question with mathematics behind it. In my physics book there's the following relation: $$\sum\binom{x_a+y_a-1}{x_a}\binom{x_b+y_b-1}{x_b}=\binom{x_a+x_b+y_a+y_b-1}{x_a+x_b}$$ For $x_a+x_b=c$ with $c$ some constant.…
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The distribution of sum of two binomials with complement success probabilities

It is well-known that if $X$ and $Y$ are independent binomial random variables with parameters $(n_1,p)$ and $(n_2,p)$ respectively, $Z = X+Y$ has a binomial distribution with with parameters $(n_1+n_2,p)$. I was wondering if $Y$ is binomial with…
MikeL
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Maximum term of (a + b) ^ n

I would like a demonstration of the fact below. Being given real numbers a and b (nonzero) and a positive integer n, the order p, that occupies the maximum term (in absolute value) of the development of power (a+b)^ n, according to decreasing…
Paulo Argolo
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Alternative proofs:

I have worked about a result and want to know if there are better ways of proving the following: $$N^M - (N-1)^M$$ $$=\binom{N}{1}(N-1)^{M-1} + \binom{N}{2} (N-1)^{M-2} + \binom{N}{3} (N-1)^{M-3} + \cdots +\binom{N}{M}(N-1)^{M-M}.$$
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binomial calculation method

I want solve this probability: For $p= 0.4$ $q=0.8$ $n= 20$ $1-P(5 = 0,2531$ Is calculation method right? And is there a way to solve this in a hand calculator…
corium
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Binomial coefficient equivalence

Can someone explain to me why these 2 formulas are equivalent: $${n \choose k} = {n \choose n-k}$$
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Binomial Identity/Coefficient Question

So I know that the coefficient of $[x^n]$ is computed by using: $\left( \sum_{j=0}^n a_j b_{n-j} \right)$ = $[x^n]A(x)B(x)$ How is this formula used to make computations, for example, how do I compute: $[x^7](1+x)^{20}$ ?
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Reducing ${n\choose k} - {n\choose k-1}$

I'm writing computer program which on some point has to compute following formula: $${n\choose k} - {n\choose k-1}$$ Because I have following limits: $$n \le 4000, \space k \le\frac{n}{2}$$ computing it straightforward using factorial would involve…
Kostek
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Two team playoff question, homework help

I am working through my college text book (mathmatical statistics freund/walpole) trying to refresh my stat skills. Its been a couple years... I would sure appreciate any pointers on an exercise question that has me stumped... In a two -team playoff…
greg
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Problem with binomial coefficients

I have a problem with the binomial coefficient $\binom{5}{7}$. I know that the solution is zero, but I have problems to reproduce that: ${\displaystyle…
svenwltr
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Expanding Equation with Binomial Theorem

How do I expand this equation: $(1+t+t^2)^5$ I formed the equation into a binomial equation this way: $(1+t+t^2)^5=\sum \binom{5}{r_1}\binom{5-r_1}{r_2}t^{r_2}t^{2r_1}$ But I cannot remember how to continue from here to solve for the $r_1$ and $r_2$…
xenon
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${1\over{n+1}} {2n \choose n} = {2n \choose n} - {2n \choose n-1}$

I need to prove that $${1\over{n+1}} {2n \choose n} = {2n \choose n} - {2n \choose n-1}$$ I started by writing out all the terms using the formula ${n!\over{k!(n-k)!}}$ but I can't make the two sides equal. Thanks for any help.
user110441