Questions tagged [bounded-variation]

For questions about functions $f$ defined on an interval $[a,b]$ such that there exists a constant $M>0$, such that if $a=x_0<x_1<\ldots<x_n=b$, $n\in\mathbb N^*$, then we have $\sum_{k=1}^n|f(x_k)-f(x_{k-1})|\leq M$.

This concept can be generalized to infinite intervals, requiring that the constant is uniform.

Let $[a,b]$ be a closed interval. A function $f\colon [a,b]\to \mathbb R$ is said to be of bounded variation if $$\sup_{n\in\mathbb N_{>0}}\sup_{a=x_0\lt x_1\lt\ldots\lt x_n=b}\sum_{j=1}^n|f(x_j)-f(x_{j-1})|<\infty.$$ We denote by $TV(f):=\sup_{n\in\mathbb N_{>0}}\sup_{a=x_0\lt x_1\lt\ldots\lt x_n=b}\sum_{j=1}^n|f(x_j)-f(x_{j-1})|$ the total variation of $f$, and we can endow the vector space of functions of bounded variation with the norm $\lVert f\rVert_{BV}:=TV(f)+|f(a)|$.

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Please explain to me the following.

1)How does the graph of a funtion of bounded variation behave. 2)Why a bounded function is not always a function of bounded variation.Please explain graphically. 3)What purpose does bounded variation serve.I mean why they are defined. Sorry if the…
Rayees Ahmad
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Multiplication of absolutely continuous function and function of bounded variation

Is the product of an absolutely continuous function $f$ and a continuous function of bounded variation $g$ on $[0,1]$ for which $f(0)=0$ and $g(0)=0$, absolutely continuous?
Zeinab
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Alternate definition on bounded variation

If $g:[a,b]\to \mathbb{R}$ the $g$ is of bounded variation iff $$TV(g,[a,b])=\sup\sum_{i=1}^n |g(t_i)-g(t_{i-1})|<\infty$$ where the supremum is taken over all partitions $a=t_0
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