Questions tagged [cardinals]

This tag is for questions about cardinals and related topics such as cardinal arithmetics, regular cardinals and cofinality. Do not confuse with [large-cardinals] which is a technical concept about strong axioms of infinity.

Cardinality is a notion of size for sets, usually denoted by $|A|$ as the "cardinality of $A$". With finite sets the cardinality is simply the number of elements which are members of a set.

Dealing with infinite sets we can measure them in different ways. Cardinal numbers are very natural in the sense that they do not require extra structure (such as relations and operations defined on the set to be preserved).

In formal terms, suppose $f\colon A\to B$ (i.e. $f$ is a function whose domain is $A$ and its range is a subset of $B$).

We say that $f$ is injective if $f(a)=f(b)$ implies $a=b$; we say $f$ is surjective if its range is all $B$, namely for any $b\in B$ there is $a\in A$ such that $f(a)=b$.

If $f$ is both surjective and injective we say that $f$ is a bijection from $A$ to $B$. The inverse of a bijection is also a bijection.

Now we can define an equivalence relation on sets, $A\sim B$ if and only if there is some $f\colon A\to B$ which is a bijection.

Assuming the Axiom of Choice, we have that every set can be well ordered, and therefore there is a least ordinal which is equivalent to $A$, so we can assign it as a canonical representative for the equivalence class, usually denoted by $\aleph_\alpha$ where $\alpha$ is an ordinal, or as general Greek letters such as $\kappa,\lambda$.

Before defining the $\aleph$ numbers we need to define initial ordinals. Let $\alpha$ be an ordinal, if there is no $\beta<\alpha$ and $f\colon\alpha\to\beta$ which is a bijection, then $\alpha$ is called an initial ordinal.

The $\aleph$ numbers are defined by transfinite induction as:

  1. $\aleph_0 = |\omega| = \omega$ (note that $\omega$ is an initial ordinal),
  2. $\aleph_{\alpha+1} = \aleph_\alpha^+$ (where the $\cdot^+$ means the smallest initial ordinal above the one defined for $\aleph_\alpha$)
  3. If $\beta$ is a limit ordinal, then $\displaystyle\aleph_\beta = \bigcup_{\delta<\beta}\aleph_\delta$ (It is easy to verify that the union of initial ordinals is an initial ordinal).

The confinality of an $\aleph$ number is the minimal cardinality of a set which is unbounded in the initial ordinal matching the $\aleph$ number.

A cardinal is called regular if its cofinality is itself, otherwise it is called singular.

Example: $\aleph_0$ is regular, because for a set to be unbounded below $\omega$ it cannot be finite.

$\aleph_1$ is also regular, every ordinal below $\omega_1$ is countable, and the union of countably many countable ordinals is just countable - which is still below $\aleph_1$.

Example: $\aleph_\omega$ is singular, recall $\displaystyle\aleph_\omega=\bigcup_{n<\omega}\aleph_n$. Therefore the set $\{\omega_n\mid n<\omega\}$ (the collection of initial ordinals whose cardinality is less than $\aleph_\omega$) is unbounded, and its cardinality is merely countable.

The question whether or not there exists $\aleph_\delta$ such that $\delta$ is a limit ordinal, but $\aleph_\delta$ is regular is unprovable in ZFC. It is known that it is consistent that there are none, but unknown that it is inconsistent that there are. Cardinals with this property are called Large cardinals and are used for consistency proofs.


In the absence of choice we can no longer have canonical representatives for the equivalence classes, and things become tricky. The class of cardinals can still be defined, however in a slightly different way - usually Scott's trick.

However, to show how things can break down it is consistent with ZF that there is no choice function on the equivalence classes (i.e. you cannot have canonical representatives).

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Bijection between $ (0,1) ^ n $ and $ (0,1) $.

Let $ z \in (0,1) ^ n $. We can express this "$ z $" as a $ n $ -tuple of real numbers $ z = (z_1, z_2, \ldots ,z_n) $, where each $ z_i $ will have its infinite decimal expansion. We can write: $\begin{align*}z_1&=0,z_{11}z_{12} \ldots z_{1n}…
James A.
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Proving cardinal inequality

How does one show that $\prod_{n < \omega}\aleph_n \leq \aleph^{\aleph_0}_{\omega}$?
user391447
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Is the cardinality of set $A$ + $A^c$ greater than $A^c$?

I'm working on a problem that involves the cardinality of a set and its complement. Basically, we have a set $A$ and its complement $A^c$ and I want to know if the conjecture $|A \cup A^c| > |A^c|$ or $|A \cup A^c| \geq |A^c|$ is true. A formal…
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How to tell which set is larger.

If I am given two infinite sets A and B which do not have a bijection between them I know that one set would be larger than the other . But, how could I tell which set is larger? What additional properties would I need to know about the sets to tell…
Ryan Cole
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Show that the following pairs of sets have the same cardinality by giving explicit bijections between them

Show that the following pairs of sets have the same cardinality by giving explicit bijections between them: (a) $M_{2×2}(\mathbb C)$ and $\mathbb R$8 (b) $(0,1)$ and $(−1,+\infty)$ (c) The sets $\{z\in\mathbb C \mid 0<|z|<1,\…
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Cardinal of an open interval

Lets say there is an open interval (a,b) where a,b are real numbers. Is it true that (a,b) has cardinality equal to real numbers?
Jus
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Prove that $ \mathbb{R}$ and the interval [0,1 ] have the same cardinality.

I'm having troubles with a question. Prove that $\mathbb{R}$ and the interval [0,1] have the same cardinality. Can you help me, please? Thank you in advance!
E.D.
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I dont understand this sets question

Let $A = \{\{0\}\}$ and $B = \{0\}$. Which of the following statements are true and which are false? Justify each of your answers. $|A| = |B|$ (10 marks) $A \cap B = \emptyset $ (10 marks) $A \cap \mathcal{P}(B) = \emptyset $ (10…
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Comparing the sizes of countable infinite sets

Possible Duplicate: Cardinality != Density? The theory: For the infinite set of natural numbers Aleph-naught indicates it's cardinality, and therefor any other set that is countable (using natural numbers) must then also have the same…
slashmais
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prove: the cardinality of an countably infinite set S to the power of n is the same as the cardinality of the natural numbers

Hii i need to prove that the cardinality of an countably infinite set S to the power of n is the same as the cardinality of the natural numbers. n is a element of the natural numbers.
malii
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Why is the cardinality of irrationals greater than of rationals?

If the rationals are dense in the rationals, meaning there is a rational between every 2 irrationals, then there is essentially a rational number for every irrational. If there is aleph irrationals, why isnt there aleph rationals if there exists a…
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Find the cardinality of the following set?

If I have a set A with |A| = n then what would be the cardinality of the following set? { | ∈ (A), |X| ≤ 1} What I understand is that this is the set of all X such that it is part of the power set of A and cardinality is less than or equal to 1.…
E. Ron
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Cardinal number of a set

What is the cardinal number of the following set and how do you prove it? $$ \left \{ f:\mathbb{N}\rightarrow \left \{ 0,1 \right \} :\left|f^{-1}[\left \{ 1\right \}]\right|=\left|f^{-1}[{\left \{ 0 \right \}}]\right| \right \} $$
Ofek
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Constructing a bijective function

How can I explicitly construct a bijective function from [0,∞) to (0,∞)? I see that [0,∞) – N = (0,∞) – Z+, but what do I do next? Also, can anyone show me how to do this by explicitly constructing a bijective function from [0,1] to [0,1) and…
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Cardinality of sets inequality

Suppose A,B,C,D are sets with $|A|=|C|, |B|=|D|$. I need to prove/disprove: $$|A^B| \leq |P(C\times D)|$$ I know $|P(C\times D)|= 2^{|C\times D|}$, but I'm not sure what to do with the left side. Help please :)
Itay4
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