Questions tagged [complex-analysis]

For questions mainly about theory of complex analytic/holomorphic functions of one complex variable. Use [tag:complex-numbers] instead for questions about complex numbers. Use [tag:several-complex-variables] instead for questions about holomorphic functions of more than one complex variables.

Complex analysis is a branch of mathematical analysis that investigates functions of one or several complex variables. Typical topics include Cauchy's integral formula, singularities, poles, holomorphic and meromorphic functions, Laurent and Taylor series, maximum modulus principle, isolated zeros principle, etc.

Independent variable and dependent variable of complex functions are both complex numbers, and may be separated into real (denoted by $\Re$) and imaginary parts (denoted by $\Im$) : $z = x +iy$ and $w = f(z) =u(x,y)+iv(x,y)$ where $x, y \in \mathbb{R}$, $u(x,y)$ and $v(x,y)$ being real-valued functions.

A fundamental result of complex analysis is the Cauchy-Riemann equations, which give the conditions for a function to have a complex derivative, which is a complex generalization of the (real) derivative. If the complex derivative is defined at each point in an open connected subset of $\mathbb C$, the function is called analytic, or holomorphic. If the complex derivative is defined at each point in $\mathbb C$, the function is called entire.

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Maximum Modulus path

Consider any entire, non constant function $f:\Bbb C\to \Bbb C$. Choose any $z\in\Bbb C$ and define $m(r)\in\overline D(z,r)$, for any $r\ge 0$, with this property: $$|f(m(r))|\ge|f(w)|\;\forall w\in \overline D(z,r)$$ I'm aware that this definition…
ajotatxe
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Complex integral on a smooth curve contained in an open set

Thm 5.19 (exactly) says: Let $\gamma\colon[a,b]\rightarrow \mathbb{C}$ be piecewise smooth. Let $F$ be a complex function defined on an open set containing $\gamma^*$, and suppose that $F'(z)$ exists and is continuous at each point of $\gamma^*$.…
Jeff
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Problem in exercise of Complex Analysis

I have a Complex Analysis exam in 2 days. The last exam had, among other exercises, the following: Let $f$ be a function holomorphic in $\mathbb{D}\smallsetminus\{0\}$ that does not have a removable singularity ad the origin. What kind of…
MickG
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Help me prove the identity $\overline{f(0)} = \frac{1}{2\pi}\int_0^{2\pi}\frac{e^{i\phi}}{e^{i \phi}-z}\overline{f(e^{i\phi})}d\phi$

Let f be an analytic function defined in an open set containing the closed unit disk and let z in ℂ be fixed. I've simplified a more complicated expression down to this identity, and as implausible as it looks, after some numerical checking it does…
Set
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How do I prove that for any two points in $\mathbb{C}$, there exists a $C^1$-curve adjoining them?

Let $G$ be an open-connected subset of $\mathbb{C}$. Let $a,b$ be two distinct points in $G$. How do I prove that there exists a $C^1$-curve $\alpha:[0,1]\rightarrow G$ such that $\alpha(0)=a$ and $\alpha(1)=b$? Here's how I tried: I have proven…
Rubertos
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$f$ continuous on $\overline{D} \setminus \{1\}$, holomorphic and bounded on $D$. Then $f$ attains its supremum on the boundary

Let $D$ be the unit disc, $f$ continuous on $\overline{D} \setminus \{1\}$, holomorphic and bounded on $D$. The problem is to show that for all $z \in D$, $$|f(z)| \leq \sup\limits_{|\zeta| = 1, \zeta \neq 1} |f(\zeta)|$$ I'm stuck. Here are two…
D_S
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Is there an analytic function $f$ on $\mathbb{C}\setminus[-1,1]$ that satisfies $e^{f(z)}=\frac{z+1}{z-1}$?

I'm having trouble proving or disproving this question. I kind of expect that there is no such function since the definition of the logarithm of a function $\phi$ that is analytic on a simply connected open set $U$…
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Complex integral revision, this is just Cauchy's Theorem right?

(a) Give the definition of $e^z$ for a complex number $z = x+iy$ (2 marks) (b) Use the Cauchy-Riemann equations to prove that $f\colon \mathbb C \to \mathbb C$, $f(z) = e^{2z+i}$ is differentiable at every point of $\mathbb C$, and that $f'(z) =…
Jim_CS
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Analytic functions in a punctured disk

Let $f$ be continuous in the open disk $\{z:|z|<1\}$. If $f$ is analytic in $\{z:0<|z|<1\}$, ie: analytic in the punctured unit disk, then $f$ is analytic $\{z:|z|<1\}$. How does one relate the continuity of the function to the analyticness of the…
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Is there a proof show that : $\cos(z)$ and $\sin(z)$ are images of unbounded functions?

if we knew that :cos and sin are bounded function $\mathbb{R}$ for any real number $x$ . let $z $ be a complex variable , Is there a proof show that : $\cos(z)$ and $\sin(z)$ are images of unbounded functions ? Any kind of help is appreciated.
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Non Existence of a proper holomorphic map from the punctured unit disc to an Annulus

Show that there is no proper holomorphic map from the punctured unit disc to an annulus $A_r=\{z \in \mathbb C:1 <|z| < r \}$. Def:A map $f: X \to Y$ is called proper if $f^{-1}(K)$ is compact for every compact set $K$ in Y. please give some…
Arpit Kansal
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Is entire function a polynomial?

Let $f:\mathbb{C}\to \mathbb{C}$ be an entire function, and suppose that for every $z\in \mathbb{C}$ there exists $n_z\in \mathbb{N}$ such that $f^{(n_z)}(z)=0$. Is $f$ necessarily a polynomial?
Marco Flores
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A consequence of Schwarz lemma

Suppose that for some $\epsilon>0$ the function $f$ is holomorphic on $B(0,1+\epsilon)$ such that $f(a) = 0$ and $|f(z)|\leq1$ if $|z| \leq 1$. Prove for $|z| \leq 1$: $$|f(z)|\leq \left|\frac{z-a}{1-\overline{a}z}\right|.$$ I tried using the…
Kees Til
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$f_n\to f$ iff for each closed rectifiable curve $f_n (z) \to f (z)$ uniformly for $z$ in the trace of the curve

I'd like to know if the following exercise is correct. I'm not completely sure about the last point but also I don't know what more I'd say. I really appreciate corrections or any suggestion you can provide. Let $f, f_1 , f_2 ,\ldots$ be elements…
Jose Antonio
  • 7,154
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Don't understand proof of minimum modulus principle

Minimum modulus principle: If $f$ is a non-constant holomorphic function a bounded region $G$ and continuous on $\bar{G}$, then either $f$ has a zero in $G$ or $|f|$ assumes its minimum value on $\partial G$. 1) Why does $f$ has to be continuous…
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