Questions tagged [conic-sections]

For questions about circles, ellipses, hyperbolas, and parabolas. These curves are the result of intersecting a cone with a plane.

A conic section is a smooth planar curve that is the result of intersecting a cone with a plane. There are commonly four conic sections: circles, ellipses, parabolas, and hyperbolas.

We can construct these conic sections analytically. The solutions to the equation $x^2+y^2=z^2$ give us a cone in three-dimensional space. An plane in three-dimensional space that goes through a point $p=(x_0,y_0,z_0)$ and has normal vector $\langle a,b,c \rangle$ is given by the equation

$$a(x-x_0)+b(y-y_0)+c(z-z_0)=0\,.$$

Finding the common solutions to the equation of the cone and equation of the plane for various choices of $p$ and normal vector will—after a change in coordinates to write them as planar curves—lead you to the (potentially) familiar equations

  • Circle: $x^2+y^2 = r^2$
  • Ellipse: $ax^2 + b y^2 = r^2$, where $a,b>0$
  • Parabola: $ax^2 +by = r^2$, where $a\neq 0$
  • Hyperbola: $ax^2 - by^2 = r^2$, where $a,b>0$

There are also geometric constructions of the conic sections. For example, a circle is the set of all points that are a fixed distance from a given points. An ellipse is the set of all points .... The construction of Dandelin spheres (see Wikipedia) unifies the analytic and geometric constructions of conic sections.

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Finding tangent's equation that touchs parabola at $(4, 4)$

$y^2 = 4x$ is equation of a parabola. What is the equation of the tangent which touchs parabola at $(4,4)$ ? I don't know how to solve it, please help. (Excuse my bad grammer. Hope you understand what I mean)
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Prove that only one normal to the parabola $y^2=4(x-11)$ passes through the focus $(12,0)$

question on the title, thanks!! I think it has to do with the normal gradient equation, which i believe is $y-y^*=-\frac y2(x-x^*)$ I have no clue what to do next. :(
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Focus And Vertex Of An Inclined Parabola

How to find focus,vertex,directrix of a parabola like $x^2+y^2+2xy-6x-2y+3=0$. Well i know how to find those for any parabola of form $y^2=4ax$ but im just not being able to figure out a way to convert the given equation to this form. Help Please.
user220382
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Is it possible to find the equation of parabola with these givens?

If I have a parabola as seen below, and I know Vmax, Vi, and the area, 'd' under the curve from x = n to x = t, is it possible to find the equation of the parabola? Or do I need more information? n and t are not known. I've been trying this for a…
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Equation of an ellipse after reflection

Give the equation of the ellipse $x^2+2y^2-6x+16y+9=0$ after reflection in the line $y=-x$. I completed the square and obtained $$\frac{(x-3)^2}{32}+\frac{(y+4)^2}{16}=1$$ Now I changed $y$ and $x$ and then replaced $x$ with $-x$ to obtain…
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How to find the tangent to a conic?

I have this question. Find the equation of the tangent to the line $y^2=x$ at the point $(16,-4)$. I have tried to use both methods to work it out. 1) Substitute $y=mx+c$ into $y^2=x$ and find a quadratic in terms of $x$ then set the discriminant…
Sean B
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Alternative proof of the reflection property

I'd like to prove the reflection property for the hyperbola. That is, that S'PS is bisected by the tangent at P. Suppose the tangent intersects the x axis at T. The usual method would be to use the sine rule on triangles S'PT and SPT, then to use…
Trogdor
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Finding equation for diagonal ellipse given foci and eccentricity

Problem: Find the equation for the ellipse that has foci $$F_1 = (0, 0)$$ $$F_2 = (1,1)$$ and eccentricity $$\varepsilon = \frac12.$$ Hint: Use a rotation that moves the foci to the x-axis. My attempt: I by rotating the ellipse by $-\pi/4$, the…
Alec
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Conic Sections and Foci of Ellipses

We're just learning about ellipses and conics, and I'm a bit confused with ellipses, parabolas, circles, and hyperbolas, so a little help with this sample problem would be great. In which of the following equations would the ellipse have foci on the…
user202767
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Tangents of Rectangular hyperbola

P,Q,R are points on a rectangular hyperbola, and PQ perpendicular to PR. Prove that the tangent at P is perpendicular to QR.
Pratyush
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How so I put these in Standard form? Circle, Ellipse or Hyperbola?

I need help putting these into standard form so I can graph them. Also need help figuring out which ones are which: $$25x^2-16y^2-150x+64y-239=0$$ $$9x^2+4y^2+54x-64y+301=0$$ $$x^2+y^2-6x+8y+3=0$$
thxll
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Ellipse and rectangle

An ellipse, whose equation is ${x^2\over9} + {y^2\over4} = 1$, is inscribed within a rectangle whose sides are parallel with the coordinate axes. Another ellipse is circumscribing the rectangle and passes through the point (0, 4). I am asked to find…
Gummy bears
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The focal chord that cuts the parabola $ x^2 = -6y$ at $(6, -6)$ cuts the parabola again at $X$

The focal chord that cuts the parabola $x^2 = -6y$ at $(6, -6)$ cuts the parabola again at $X$. Find the coordinates of $X$. I have been going insane someone please help me :(
Emerie
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Arc length of parabola between two points

Well lets take a parabola of the equation $y = f(x)$ where $f(x)$ is obviously a $2^{nd}$ degree function. Now lets take two points at $x=a$ and $x=b$ . So can anyone please help me to find that curved arc length between the points $a$ and…
NeilRoy
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An equation of a tangent to the parabola $y^2=8x$ is $y=x+2$. the point on this line from which the other tangent

Problem : An equation of a tangent to the parabola $y^2=8x$ is $y=x+2$. the point on this line from which the other tangent to the parabola is perpendicular to the given tangent is given by ... Solution : Slope at any point on the parabola from…
Sachin
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