Questions tagged [conic-sections]

For questions about circles, ellipses, hyperbolas, and parabolas. These curves are the result of intersecting a cone with a plane.

A conic section is a smooth planar curve that is the result of intersecting a cone with a plane. There are commonly four conic sections: circles, ellipses, parabolas, and hyperbolas.

We can construct these conic sections analytically. The solutions to the equation $x^2+y^2=z^2$ give us a cone in three-dimensional space. An plane in three-dimensional space that goes through a point $p=(x_0,y_0,z_0)$ and has normal vector $\langle a,b,c \rangle$ is given by the equation

$$a(x-x_0)+b(y-y_0)+c(z-z_0)=0\,.$$

Finding the common solutions to the equation of the cone and equation of the plane for various choices of $p$ and normal vector will—after a change in coordinates to write them as planar curves—lead you to the (potentially) familiar equations

  • Circle: $x^2+y^2 = r^2$
  • Ellipse: $ax^2 + b y^2 = r^2$, where $a,b>0$
  • Parabola: $ax^2 +by = r^2$, where $a\neq 0$
  • Hyperbola: $ax^2 - by^2 = r^2$, where $a,b>0$

There are also geometric constructions of the conic sections. For example, a circle is the set of all points that are a fixed distance from a given points. An ellipse is the set of all points .... The construction of Dandelin spheres (see Wikipedia) unifies the analytic and geometric constructions of conic sections.

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shadow cast by a circle

A point source emits light at a circular disc (thickness negligible), and a shadow is left on a wall (XY plane) behind and parallel to the disc. The Z component of distance between the point source and the disc is 'a' units. The Z component of…
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Roots of parabola

I have a parabola with the equation $y = x^2 + 6x + 7$ and I am trying to calculate the $x$-intercept points. Here is my working so far... let $y = 0$, $x^2 + 6x + 7 = 0$ $x(x + 6) = -7$ After this I have no idea where to go next. Any help is…
Neddy
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Joachimsthals Notations and tangents of conic at a point

I was going through Cut-the-Knot's "Joachimsthal's Notations" page discussing Joachimsthal's indice method of studying conics. The conic can be represented in a following way: $$ s_{ij} = Ax_i x_j + B(x_i y_j + x_j y_i) + C y_i y_j + F(x_i + x_j)…
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How to find the required equation for a family of curves?

The question given is: Tangents are drawn from two points $(x_1,y_1)$ and $(x_2,y_2)$ to $xy=c^2$. The conic passing through the two points and through the four points of contact will be a circle, then $(A)\quad x_1x_2=y_1y_2\\(B)\quad…
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Why no angle is involved in parametric equation of parabola?

Why only in parametric equation of parabola, angle is not involved unlike parametric equation in ellipse and hyperbola, angle is involved. Thank you. [edit]: In parametric equation of parabola $y^2=4ax$, any coordinate on the parabola is taken as…
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Determine the Angle of an point in an Ellipse

I would like to know how to determine at which angle a point lies in an ellipse. Suppose I have an ellipse with semimajor and semiminor of 10 and 5 (see illustration). and suppose the point (8,3) lies in the ellipse , how can i find its angle from…
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Two concentric ellipses be such that the foci of one lie on the other ellipse

If two concentric ellipses be such that the foci of one be on the other and their major axes are equal. Let $e_1$ and $e_2$ be their eccentricities, then prove that the angle between their axes is given by $\cos…
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Pair of tangents from point $(2\sqrt2,1)$ to hyperbola $\frac{x^2}{a^2} -\frac{y^2}{b^2} = 1$

From a point $(2\sqrt2,1)$ a pair of tangents are drawn to $$\frac{x^2}{a^2} -\frac{y^2}{b^2} = 1$$ which intersect the coordinate axes in concyclic points. If one of the tangents is inclined at an angle of $\arctan\frac{1}{\sqrt{2}}$ with the…
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Find the equation of straight line which passes through the intersection of the lines $x-2y-5=0$ and $7x+y=50$....

Find the equation of straight line which passes through the intersection of the lines $x-2y-5=0$ and $7x+y=50$ and divides the circumference of the circle $x^2+y^2=100$ into arcs of ratio 2:1 The point of intersection of the two lines was found to…
Aditya
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Is it always possible to draw an ellipse given any two points and the center?

I have 2 points and I want to draw an ellipse that passes through those points. I also have the center of the ellipse. My question is: is it always possible to draw such an ellipse? $\frac{(x-c_x)^2}{a^2} + \frac{(y-c_y)^2}{b^2} = 1$ When trying…
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If the line $x+y-1=0$ is a tangent to a parabola with focus (1,2) at A and intersects the directrix at B and tangent...

If the line $x+y-1=0$ is a tangent to a parabola with focus (1,2) at A and intersects the directrix at B and tangent at vertex C respectively, then find the value of AC.BC First of, they have given absolutely no infomation regarding the parabola,…
Aditya
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From points on the straight line $3x-4y+12=0$, tangents are drawn to the circle $x^2+y^2=4$.

Then the chord of contact passes through a fixed point. Find the slope of chord of the circle having this fixed point as it’s midpoint. Let the tangents be drawn from the point (h,k) $$3h-4k+12=0$$ The chord of contact is…
Aditya
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Find pair of line equations passing origin and points of intersection of $lx+my+n=0$ and $y^2=4ax$

$y^2=4ax$ will be a parabola and will intersect the given line at two points. To be honest, that’s all I could figure out. I tried using $x=y^2/4a$ and substituting in the given equation, but the process was impossibly long. What is the proper…
Aditya
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Do both these ellipses satisfy the same conditions?

I was solving a problem that asked for the equation of the ellipse with the following properties: vertex at $(-10,5)$, focus at $(-2,5)$, eccentricity $\frac{1}{2}$. I think I found two such ellipses, but since the book only lists one. I want to…
ivan
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Are conic sections obtained from a cone or a double cone?

According to Wikipedia, In mathematics, a conic section (or simply conic) is a curve obtained as the intersection of the surface of a cone with a plane. However most of the images actually show a double cone instead of a cone and it makes sense to…
MCL
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