Questions tagged [continuity]

Intuitively, a continuous function is one where small changes of input result in correspondingly small changes of output. Use this tag for questions involving this concept. As there are many mathematical formalizations of continuity, please also use an appropriate subject tag such as (real-analysis) or (general-topology)

Analytic Definition: Let $(X, d_X)$ and $(Y, d_Y)$ be metric spaces. A map $f : X \to Y$ is said to be continuous at $x_0$ if for every $\varepsilon > 0$, there is $\delta > 0$ such that $d_Y(f(x_0), f(x)) < \delta$ whenever $d_X(x_0, x) < \varepsilon$. A map $f : X \to Y$ is said to be continuous if it is continuous at $x_0$ for all $x_0 \in X$.

Topological Definition: Let $(X,\mathcal T_X)$ and $(Y, \mathcal T_Y)$ be topological spaces. A map $f : X \to Y$ is said to be continuous if $U \in \mathcal T_Y$ implies that $f^{-1}(U) \in \mathcal T_X$.

In the case of metric spaces, the metric induces a topology, and the two notions of continuity coincide. Note that multiple metrics can induce the same topology, and that not all topologies are metrizable (can be generated from some metric).

Continuity is a sufficient condition for the intermediate value theorem. It is also a necessary condition for the extreme value theorem, as well as differentiability.

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Can we talk about the continuity/discontinuity of a function at a point which is not in its domain?

Let us say that I have a function $ f(x)=\tan(x)$ we say that this function is continuous in its domain. If I have a simple function like $$ f(x)=\frac{1}{(x-1)(x-2)} $$ Can we really talk about its continuity/discontinuity at $x=1$ or at…
anubhav
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Continuous map $\mathbb{R}^n\rightarrow\mathbb{R}^n$

When we say some map $\phi=(\phi_1,\ldots,\phi_n)$ is a continuous map $\mathbb{R}^n\rightarrow\mathbb{R}^n$ we really mean that each component $\phi_i$ is continuous as a function $\mathbb{R}^n\rightarrow\mathbb{R}$ or do we mean something else?…
luka5z
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Continuous on every continuous path vs Continuous

Suppose $F:\mathbb{R}^2\rightarrow\mathbb{R}$ is such that for all continuous paths $g:[0,1]\rightarrow\mathbb{R}^2$, $F(g(t))$ is continuous. Is F continuous?
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Find all functions which satisfy: $f(x+y) - xy\ge f(x) +f(y)$ and $ f(x) \ge 1-\cos(x)$ for all $x,y\in \mathbb{R}$

Let $f:\mathbb R\rightarrow \mathbb R$ be a continuous function. Find all functions which satisfy: $$f(x+y) - xy\ge f(x) +f(y)$$ And $$ f(x) \ge 1-\cos(x) \quad \text{for any x,y real numbers}$$ I found out $f(0)=0$ and $f(x) \geq \frac{x^2}2$ but…
Jack
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Continuity of removing odd decimals

Let $x = 0.x_1x_2x_3\cdots$ be the unique decimal representation of $x$ not containing a string $999\cdots$. Let $f(x)\in (0,1)$ be $0.x_2x_4\cdots$. Where is $f$ discontinuous? I haven't been able to find any point and it seems to me that…
mtheorylord
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Show $F:C[0,1] \rightarrow C[0,1]$ defined by $F(f) = g \circ f$ is continuous.

Define $F:C[0,1] \rightarrow C[0,1]$ by $F(f) = g \circ f$, where $g:\Bbb R \rightarrow \Bbb R$ is continuous. I am struggling to show that F is continuous. We use the supremum norm: $$ ||f|| = sup_{x\in[0,1]}|f(x)| $$ Let U be an open set in…
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Where is $x^x$ continuous?

The idea of continuity of a function is something I come across quite regularly, but I've never really understood it well. I'm trying to fix that by looking at some interesting functions. What happens continuity wise for $x<0$ in this…
Bamboo
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How to prove that $\frac{x}{1+x}$ is continuous at x=1?

This is what I've done: $$\left|\frac{x}{1+x} - \frac{1}{1+1}\right| = \left|\frac{x-1}{2+2x}\right| = \left|x-1\right|\frac{1}{\left|2+2x\right|} < \epsilon $$ How should I find the lower bound $\left|2+2x\right|$? Do I need to introduce another…
lsy
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Can a function be continuous at only one point in its domain and discontinuous everywhere else

Can you please explain if this is possible or not? Does there exist a function that is continuous at only one point in its domain?
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Method checking to show function is discontinuous at x=0

Let $f:[0, \pi] \rightarrow \mathbb{R}$ be defined by $f(0)=0$ and $f(x)=x \sin \frac{1}{x}-\frac{1}{x} \cos \frac{1}{x}$ for $x \neq 0$. Is $f$ continuous ? my method was that x $\sin \frac{1}{x}$ has limit value as zero as x tends to zero . So we…
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Discontinuity of $\sin(\frac{1}{x})$

I’ve heard and read in many books that the function $$\sin\left(\frac{1}{x}\right)$$ is discontinuous at $x=0$ since as $x$ tends to zero the function ‘oscillates’ rapidly that is , for numbers very close to each other the number takes valued such…
Aditi
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$|f(x)-f(y)|\le g(x-y)$, is $f$ continous when $g$ is

$g$ is a continous function on $\mathbb{R}$ and $g(0)=0$, $f$ satisfies $|f(x)-f(y)|\le g(x-y)$, I need to show $f$ is continous. well I tried like this: $|f(x)-f(0)|\le g(x), |f(0)-f(y)|\le g(-y)$, $|f(x)-f(y)|=|f(x)-f(0)+f(0)-f(y)|\le…
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How to show that $\max(f,g) =(f+g+|f-g|)/2$?

How to show that $$ \max(f,g) = \frac{f+g+|f-g|}{2} $$
Klara
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Prove that $f \circ g$ is a uniformly continuous function.

Asuume that $f:\mathbb{R}\rightarrow \mathbb{R}$ continuous function and $g:\mathbb{R}\rightarrow \mathbb{R}$ uniformly continuous function and $g$ bounded. I have to prove that $f\circ g$ is uniformly continuous function. I tried the following: $f$…
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Continuous image of dense set is also dense.

Let $f : X \to Y$ is continuous and $E \subset X$ is dense set. Then I want to show that $f(E)$ is also dense in $f(X)$ My approach is like this : Let $y \in f(X)\setminus f(E)$, then $\exists x \in X\setminus E $ such that $f(x) = y$. Then I can…
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