Questions tagged [divisibility]

This tag is for questions about divisibility, that is, determining when one thing is a multiple of another thing.

If $a$ and $b$ are integers, $a$ divides $b$ if $b=ca$ for some integer $c$. This is denoted $a\mid b$. It is usually studied in introductory courses in number theory, so add if appropriate.

A common notation used for the phrase "$a$ divides $b$" is $a|b$. It is also common to negate the notation by adding a slash like this: "$c$ does not divide $d$" written as $c\nmid d$. Note that the order is important: for example, $2|4$ but "$4\nmid 2$".

This notion can be generalized to any ring. The definition is the same: For two elements $a$ and $b$ of a commutative ring $R$, $a$ divides $b$ if $ac=b$ for some $c$ in $R$.

Divisibility in commutative rings corresponds exactly to containment the poset of principal ideals. That is, $a$ divides $b$ if and only if $aR\subseteq bR$. For commutative rings like principal ideal rings, this means that divisibility mirrors exactly the poset of all ideals of the ring.

The topics appropriate for this tag include, for example:

  • Questions about the relation $\mid$.
  • Questions about the GCD and LCM.

There are divisibility rule that is a shorthand way of determining whether a given integer is divisible by a fixed divisor without performing the division, usually by examining its digits.

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simple problem on divides

If 6 divides x and 8 divides x how do you deduce 24 divides x
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Divison by Zero

I have seen multiple answers on the web, but I can't get my mind around why division by zero outputs an error and not zero. Can anyone explain this in laymen's terms?
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Count the the number of elements in a set, exactly divisible by 2 out of 3 numbers

I need a hint to solve the following problem, in a way that a 10yr old child can understand. On a blackboard, all whole numbers from 1 to 2006 were written. John underlined all numbers divisible by 2, Adam underlined all numbers divisible by 3 and…
Yorgos
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Divisibility and finding the remainder

If $11n$ leaves a remainder of 6 when divided by 7, what is the remainder when $5n$ is divided 7?
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why is $6$ divided by $1245=207.5$ ?instead of $207$ remainder $3$?

Help, $\frac{6}{1245}= 207.5$? I did long division to get my answer. But when I calculate it myself I end up with $207$ remainder $3$ ,how does that translate into $.5$?
greg
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How to find $\frac{a+b+c}x$?

$ab$ and $bc$ are two digit numbers. if $ab*x=2 $ and $bc*x=3$ then find $\frac{a+b+c}x$. (* is multiplication) It looks simple but I couldnt go further. $$17b=2(15a-c)\iff b\mid2 \quad and\quad 17\mid (15a-c)$$ a=4 b=6 and c=9 suffice this. Is…
St3114
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For prime $p$, show that $p\mid a^n\Rightarrow p\mid a$

I already try to solve this with divisibility rule $p = ka, a^n$ = $ka*ka$ as much as $n$ times $a^n≡a (mod n)$, then $p^n=ka*ka$ therefore $p^n= a^n$ be $^n√p^n|^n√a^n$ which $p|a$ but im not sure how right am i or wrong
Rahayu
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(Dis)prove $\,a\mid b\,\Rightarrow\, a+b\mid b+c$

Can someone help me here? I'm completed stuck in this simple problem. Let a, b, c $\in \mathbb{N} $, check if the statement below is true or false: if   a|b then (a+b) | (b+c) Any tips? What i've done so far: If a|b, then b=a.c To prove that…
Hesoyam
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How to prove $p | a^2 \implies p | a$?

How to prove $p | a^2 \implies p | a$? Given that $a,p \in \mathbb{Z}$.
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Find all the integers $n$ with $22\mid n^2+n-2$

Find all the integers $n$ with $22\mid n^2+n-2$ I have tried gcd but I have no idea how to solve this Thank you :)
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The problem of ten divided by three

Possible Duplicate: Does .99999… = 1? I was thinking about this the other day... if 10/3 = 3.33333... (series) why doesn't 3.333... * 3 = 10 it can never be 10 it's always almost 10 or 9.9999... (infinity) I have read about this but then no one…
Val
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If $mn+1$ is a multiple of $24$, prove that $m+n$ is also a multiple of 24.

Please use UK pre-uni methods only (at least at first). Thank you.
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Prove that $(x^3 - x)(2x^2 + 5x - 3)$ is divisible by $5$ without using induction

I've factorised the equation to $x(x+1)(x-1)(2x-1)(x+3)$ and I notice it has $3$ consecutive numbers, a missing one and then the next consecutive number not sure how to use this to prove the required divisibility.
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Division by zero after removing factor.

I know that anything divided by zero is undefined and I understand why. However, I have just discovered this sum, and it confused me greatly. Could anyone explain what is going on…
kettboy
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