Questions tagged [exact-sequence]

A sequence of morphisms where the image of one is the kernel of the next. It is a useful thing to examine in the study of abstract algebra and homological algebra. Use this tag if your question is about the general theory of exact sequences, not just because an exact sequence appears in it. For sequences of numbers use the tag (sequences-and-series) instead.

An exact sequence in a category a sequence of of morphisms in that category

$$ \dotsb \xrightarrow{\;\;\varphi_{i-1}\;\;} X_i\xrightarrow{\;\;\varphi_{i}\;\;} X_{i+1}\xrightarrow{\;\;\varphi_{i+1}\;\;} \dotsb $$

such that the image of $\varphi_j$ is equal to the kernel of $\varphi_{j+1}$ for any $j$. Any (long) exact sequence can be decomposed in a reasonable way into short exact sequences, so these are more often the objects that we examine. A short exact sequence is a sequence

$$ 0 \to B \xrightarrow{\;\;\varphi\;\;} C \xrightarrow{\;\;\psi\;\;} A \to 0 $$

Such that $\mathrm{Im}(\varphi) = \mathrm{Ker}(\psi)$, $\varphi$ is an monomorphism, and $\psi$ is an epimorphism. The object $C$ is referred to as an extension of $A$ by $B$. Exact sequences are major objects of study in the broader areas of abstract algebra and homological algebra.

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Proof that a short exact sequence does not split

Consider the short exact sequence of $C^\ast$-algebras $$ 0 \rightarrow C_0(0,1)\overset{\imath }{\rightarrow} C[0,1] \overset{\psi}{\rightarrow} \mathbb C \oplus \mathbb C \to 0, $$ where $\imath: C_0(0,1) \to C[0,1]$ is the inclusion and $\psi(f)…
user 242964
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Equivalence statement about split sequences

Prove that if $0 \to A \to B \to C \to 0$ is an exact sequence, with $f:A \to B$ and $g: B \to C$, all $R$-modules with $B = f(A) \oplus D$ for some $R$-module $D$, then there exists an $R$ homomorphism from $C$ to $B$ such that $gg' = Id_C$. Here…
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"trivial" exact sequence

Let $A=B=C=\{0\}$. Is $A\stackrel{f}\to B\stackrel{g}\to C$ a splitting exact sequence? We have $Im(f)=ker(g)$ and there is an $h:C\to B$ such that $g\circ h=id_C$ so it should yield a splitting exact sequence but it's so trivial I don't know…
Buh
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Split exact sequences.

Edit: The setting is some abelian category. The splitting lemma says that the following conditions are equivalent for a short exact sequence $$0\rightarrow A\rightarrow B\rightarrow C\rightarrow 0$$ The left arrow has a left inverse The right arrow…
user153312
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What exactly is a split of an exact sequence?

I read through Wikipedia and tons of questions of MSE, but I still can't grasp the concept of a split of a short exact sequence. Apparently by definition a sequence $$0\rightarrow A\overset f \rightarrow B\overset g\rightarrow C \rightarrow…
355durch113
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