Questions tagged [fourier-series]

A Fourier series is a decomposition of a periodic function as a linear combination of sines and cosines, or complex exponentials.

If $f$ is a periodic function with period $2\pi$, a Fourier series for $f$ is an expansion of the form $$ f(x) = \frac{a_0} 2 + \sum_{n = 1}^\infty a_n \cos nx + \sum_{n = 1}^\infty b_n \sin nx .$$

This decomposition is useful for solving partial differential equations, and it has important applications in the study of waves.

If $f$ is continuously differentiable, a theorem of Dirichlet states that a Fourier expansion exists where the infinite sums converge uniformly to $f$. Under the weaker assumption that $f \in L^2[0,2\pi]$, there exists a Fourier expansion where the infinite sums converge to $f$ in the $L^2$ sense.

The sines and cosines appearing in the Fourier expansion form an orthogonal basis for $L^2[0,2\pi]$. Therefore, a simple way of evaluating the $a_n$ and $b_n$ coefficients is by orthogonal projection, $$ a_n = \frac 1 \pi \int_0^{2\pi} f(x) \cos nx\ \mathrm dx, \ \ \ \ \ \ \ \ \ b_n = \frac 1 \pi \int_0^{2\pi} f(x) \sin nx\ \mathrm dx.$$

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Why the need to integrate to get the Fourier series coefficients?

In the derivation (image below) of getting the Fourier series coefficients, $e^{-jlw_0}t$ is integrated with $x(t)$ over a $[t_0,t_0+T]$ interval to isolate the $a_k$th coefficient. But why the need to integrate at all? Why can't we replace the…
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What is meant by the Fourier sine series?

The wording of the following problem confuses me: Find the Fourier sine series for $f(x)=x$, on $0\leq x
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Fourier series, why do we choose $x=\frac{1}{2}$

Im struggling with a Fourier series and would like some help. $f(x) = x-x^2$ has the Fourier series $\frac{1}{6} - \sum_{n=1}^{\infty} \frac{1}{n^2 \pi^2} \cos(2n \pi x)$ and i want to calculate $\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n^2}$ Why do we…
uoiu
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Is there an easy way to see why any periodic function can be written as a sum $ \sum_{n=1}^\infty c_n e^{inx} $

Somehow taylor series make sense to me but I can not clearly see why any periodic function can be written as a sum of trigonometric series or complex exponentials. Whenever I see 'explanations' of Fourier series it is just said that it is…
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Coefficients of series equation

Is there a way to compute the coefficients $a_k$ in series of the form $\sum\limits_{k=1}^{\infty}a_k \sin(ka) = b$ and $\sum\limits_{k=1}^{\infty}a_k \sin(ka) k = b$ for fixed constants $a,b\in\mathbb{R}$? I thought about Fourier series of course…
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Trigonometric Fourier series of absolute cosine

I am having trouble finding the trigonometric Fourier series of $|cos(\pi*t/2)|$ where $1\leq t<3$. I understand that since its an even function all $b_n$ will be zero. The limit is throwing me off. Please guide me on how to approach this problem.…
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Is this Fourier series calculation right?

I'm working on a course problem, Calculate the Fourier series of the periodic function $f(t)$ with fundamental period $T=4$ defined on $[-2,2)$ by $$f(t)= \begin{cases}1-|t|&-1\leq t\leq1 \\0&\text{otherwise.}\end{cases}$$ I get $$\text{even…
mjc
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Determine the function to which the Fourier series converges for $f(x)=x$

Determine the function to which the Fourier series converges for $f(x)$ given the following $$f(x)=x,~~~~~-\pi
Unknown
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Why half of $A_0$ in Fourier series

If a function $f(x)$ is defined in $[-L,L]$, then Fourier series is defined as $$f(x)=\frac{A_0}{2}+\sum_{n=1}^{\infty}[A_n \cos (n\pi x/L)+ B_n \sin (n \pi x/L)],$$ where $$A_n=L^{-1}\int_{-L}^{L} f(x) \cos (n\pi x/L)~ dx,\quad…
MathDona
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How to expand an odd function into a series of cosines?

(Editing my original post, also, already noticed this post) Given for example the odd function $f(x)=x$ defined in the interval $[-\pi,\pi]$. I would like to expand this function into a cosine series. Is it possible to somehow expand $f$ into a…
Dr. John
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Fourier series - is it possible to expand an odd function into a cosine series?

(Already noticed this post) Given for example the odd function $f(x)=x$ defined in the interval $[-\pi,\pi]$. I would like to expand this function into a cosine series. Is it possible to somehow expand $f$ into a function symmetric with respect to…
Dr. John
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Fourier series of $\frac{1-r^2}{1-2r\cos x+r^2}$ when $|r|<1$

How can I calculate the Fourier series of $\frac{1-r^2}{1-2r\cos x+r^2}$ when $|r|<1$? I know the answer is $1+\sum_{n=1}^{\infty}2r^n\cos nx$, but is there any way to solve the problem in the realm of real numbers? Thank you for your help.
carol
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Is this infinite series a Fourier series?

I have what looks like a Fourier series but I don't quite understand how (or if) it is possible to recover a function from this. $$e^{3i\pi/2}+2e^{3i\pi/2}+3e^{3i\pi/2}+4e^{3i\pi/2}+5e^{3i\pi/2}+\cdots$$ Any ideas? If changes to this series are…
aldorath
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a_n coeffisent in fourier. like function

i want to find the fourier transform of this function: and since it is an like function the b_n is zero. And also since it the function is like i thought i could only take the integral from 0 to pi and multiple it by 2, but then i get the wrong a_0…
Lisa
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Fourier series. different answer than the answer sheet

Im trying to find the fourier series of this function And i get the coeffesients just like the solutionsheet: $$a_0=\frac{\pi^2}{12}$$ $$a_n = -\frac{2}{n^2} , n =even$$ $$b_n = \frac{4}{\pi n^3}, n=odd$$ but when i put this in the fourier series…
Lisa
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