Questions tagged [functional-equations]

The term "functional equation" is used for problems where the goal is to find all functions satisfying the given equation and possibly other conditions. Solving the equation means finding all functions satisfying the equation. For basic questions about functions use more suitable tags like (functions) or (elementary-set-theory).

The term "functional equation" is used for problems where the goal is to find all functions satisfying the given equation(s) and possibly other conditions; e.g., the goal can be to find all continuous solutions. Solving the equation means finding all functions satisfying the given equation(s) and any additional conditions.This is different from the more common use of the word "equation", where the solutions are numbers. It is also different from the more common use of the word "functional", referring to a mapping from a space into the reals or complexes. For basic questions about functions use more suitable tags like or .

A common technique used in solving functional equations is finding some properties of satisfying functions by substituting variables for certain values in the equation. Proving properties of satisfying functions is also helpful - finding that a function is injective, surjective, involutive, and so on, is often a key step in finding all possible solutions. Other techniques such as exploiting symmetry, considering fixed points, and even using certain properties of domains (e.g. well-ordering) sometimes help.

Some well-known functional equations are:

More information can be found at Wikipedia.

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A non-zero function satisfying $g(x+y) = g(x)g(y)$ must be positive everywhere

Let $g: \mathbf R \to \mathbf R$ be a function which is not identically zero and which satisfies the equation $$ g(x+y)=g(x)g(y) \quad\text{for all } x,y \in \mathbf{R}. $$ Show that $g(x)\gt0$ for all $x \in \mathbf{R}$.
Sikhanyiso
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Are there any solutions to $2g(x+y)-g(x-y) =2g(x)g(y)$ with $g(0) \ne 0$?

Are there any solutions to $2g(x+y)-g(x-y) =2g(x)g(y)$ with $g(0) \ne 0$? This came up (by replacing $e^x$ with $g(x)$) in an attempt to generalize this: Solving functional equation gives incorrect function I have easily shown that $g(x) =…
marty cohen
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Solve the system of functional equations.

Find all functions $f: \mathbb{R} \to \mathbb{R}$ such that \begin{cases} f(x(1+f(x)))=f(x)^2,\\ f(x(1-f(x)))=f(x) f(-x),\\ f(x(-1+f(-x)))=f(x)f(-x). \end{cases} I have found only that for nontrivial $f$ must be $f(0)=1$ and have no more ideas.
Leox
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Determine function such that $f\left(\sqrt{x_1^2+(f(x_1))^2}\right) = f\left(\sqrt{x_2^2+(f(x_2))^2}\right)$ for every $x_1,x_2$.

Determine a numerical no constant function $f$ such that for all $x_1$, $x_2$ in its domaine of definition, the equality $$f\left(\sqrt{x_1^2+(f(x_1))^2}\right) = f\left(\sqrt{x_2^2+(f(x_2))^2}\right)$$ is verified. Can you give some special…
Piquito
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Functional equation $f(f(y))+f(x-y)=f(xf(y)-x)$

Find all functions $f$ defined on the real and takes real values ​​such that $$f(f(y))+f(x-y)=f(xf(y)-x)$$ for all $x,y\in \mathbb{R} $ My approach: Let be x=y=o, so $f(f(0))+f(0)=f(0) \to f(f(0))=0$. Now, defining $y=f(0),x=0$, we have…
pablocn_
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Pexerized D'alembert functional equation $f(x+y)+g(x−y)=\lambda f(x)g(y)$

Let $\lambda$ be a nonzero real constant. Find all functions $f,g: \mathbb R \to \mathbb R$ that satisfy the functional equation $f(x+y)+g(x−y)=\lambda f(x)g(y)$. I try this : Let $y=0$ in the equation to get $f(x)+g(x)=\lambda f(x)g(0)$ Here we…
sofie
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Solutions of $f : \Bbb Q^*_+ \to \Bbb Q$ such as $f(\tfrac1x)=f(x)$ and $f(x) = (1+\tfrac1x)f(x-1)$ for all $x$

This is an extension to : Functions $f: \Bbb Q_{+} \to \Bbb Z$ such that $f(\frac{1}{x}) = f(x)$ and $(x+1)f(x-1)= xf(x)$ What can be said about functions $f : \Bbb Q^*_+ \to \Bbb Q$ such as $f(\tfrac1x)=f(x)$ and $f(x) = (1+\tfrac1x)f(x-1)$ for all…
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Iterative (functional) roots of integer functions (functions on $\mathbb{Z}$)

A function $g:A\to A$ is called a $k$-th iterative root of another function $f:A\to A$ ($A$ an arbitrary set and $k\in\mathbb{N}$) iff $f=g^k$, where $g^k(x)=g\circ g\circ\ldots\circ g(x)=g(g(\ldots g(x)\ldots))$ means $k$-fold iterative application…
Mario
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A problem on solving functional equations

If $f(x),\forall x\in\mathbb{R}$ is continous and differentiable, and satisfies: $f(x_1+x_2)+f(x_1-x_2)=2f(x_1)f(x_2),\forall x_1,x_2\in\mathbb{R}$ $f\left(1\right)=\dfrac{3}{2}$ How to prove: $$f(x)=2^{-x-1}…
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What is the formula and the name of the mathematical-phenomenon seen at the ending of "Around the World in Eighty Days"?

Spoiler in brief for those who don't know the ending yet: At the end, Phileas Fogg alongside with his companions realize that they have arrived back to London a day earlier than expected due fact the party did travel eastward. Each time they crossed…
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Determine all functions (functional equation)

Determine all functions $f : \mathbb{R} \to \mathbb{R}$ that satisfy the functional equation $$f(x + y) + f(z) = f(x) + f(y + z)$$ for all $x, y, z \in \mathbb{R}$.
molk
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Functions that hasn't any root

we say that a function like $f:X \to X$ has root if exists a function like $g:X\to X$ that for every $x \in X$: $$f(x) = g(g(x))$$ what is a necessary and sufficient condition for $f$ that it has a root. for example the below function hasn't any…
user120269
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When can we take that $f(1)=1$?

I have been doing some functional equations and in some of them they just say " WLOG let $f(1)=1$ ", but I don't get why they can do that... Can someone please help me? I can't find the example of $f(1)=1$ but here is one where they take…
CryoDrakon
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Commutivity of second functional derivatives

In multivariable calculus we learn that partial derivatives are commutative: i.e. $\partial _{xy}F=\partial_{yx}F$ When dealing with multiple functional derivatives this doesn't seem to be the case. Consider the simple functional equation:…
Seenathin
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Solve the functional equation $4f(x)=f(2x)$

Solve the functional equation $4f(x)=f(2x)$. As for now I know that one solution is $f(x)=cx^2$, where c is a constant value.
CryoDrakon
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