Questions tagged [functional-equations]

The term "functional equation" is used for problems where the goal is to find all functions satisfying the given equation and possibly other conditions. Solving the equation means finding all functions satisfying the equation. For basic questions about functions use more suitable tags like (functions) or (elementary-set-theory).

The term "functional equation" is used for problems where the goal is to find all functions satisfying the given equation(s) and possibly other conditions; e.g., the goal can be to find all continuous solutions. Solving the equation means finding all functions satisfying the given equation(s) and any additional conditions.This is different from the more common use of the word "equation", where the solutions are numbers. It is also different from the more common use of the word "functional", referring to a mapping from a space into the reals or complexes. For basic questions about functions use more suitable tags like or .

A common technique used in solving functional equations is finding some properties of satisfying functions by substituting variables for certain values in the equation. Proving properties of satisfying functions is also helpful - finding that a function is injective, surjective, involutive, and so on, is often a key step in finding all possible solutions. Other techniques such as exploiting symmetry, considering fixed points, and even using certain properties of domains (e.g. well-ordering) sometimes help.

Some well-known functional equations are:

More information can be found at Wikipedia.

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How to solve this functional equation: $f(x^2) = f(x) f^{-1}(x)$?

We know that the equation admits the particular solutions: $f(x) = x$, $f(x) = x - 1$ and $f(x) = \frac{1}{x}$ But how to get these results? The method of guessing a function and substituting it into the equation is very limited and we found no…
JaberMac
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Find even function $f:\mathbb{R}\to\mathbb{R}$ such that $f(x)+f(x-2) = x^2-2x+1$ for all $x\in\mathbb{R}$.

Find $f:\mathbb{R}\to\mathbb{R}$ such that $f(x)+f(x-2) = x^2-2x+1$ for all $x\in\mathbb{R}$, given that $f$ is is an even function. I have tried putting $$x = x+2$$ and also $$x=-x$$but that gives the same thing, I don't know I am unable to make…
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Help Finding Rigorous Proof: Polynomial $p(x+c) = p(x) + c$

Question: Find all polynomials $p(x)$ so that $p(x+c) = p(x) + c$. My original thought was that the function forms an arithmatic sequence with all $x$ that are multiples of $c$, but I can't find a way to make my proof that the polynomial must be…
Celwelf
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Find all $f(x)$ s.t. $f(x)f(x-1/2)=x$

I've tried many different things myself, but I can't find any exact function that seems to follow this path. First, I tried thinking that $f(1)$ would most likely also be 1, so then $f(1)f(1/2)=1$, which narrows it down to a function where…
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Find $f(7)$ given $f(x)f(y)=f(x+y)+f(x-y)$ and $f(1)=3$

Let $f:\Bbb R\to\Bbb R$ such that $f(1)=3$ and $f$ satisfies the functional equation $$f(x)f(y) = f(x+y) + f(x-y)$$ Find the value of $f(7)$. Attempt: If $x=1$ and $y=0$, we find $$f(1) f(0) = 2f(1) \implies f(0) = 2$$ If we fix $y=1$, we get the…
user170231
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Tricky functional equation: $f\!\left(\frac{2-p+p^2}{4-2p}\right) - f(p/2)= f\!\left(\frac{(1-p)(2+p)}{2-p}\right) - f(1-p)$

I have (expect there exists) a function $f: (0,1) \to \mathbb R$ for which the following relationship holds: $$ f\left(\frac{2-p+p^2}{4-2p}\right) - f(p/2) =f\left(\frac{(1-p)(2+p)}{2-p}\right) - f(1-p), $$ for all $p\in(0,1)$. (Possibly there is a…
Thomas Ahle
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Functions satisfying the below functional equations

Find all functions from $f :\mathbb{R} \rightarrow \mathbb{R}$ such that it satisfies $|f(x)| = |x|$ , $f(f(-y))= -f(y)$ and $f(f(x))= f(x)$ $\forall$ $x,y \in \mathbb{R}$ . What I did was: say $f(x) = x \forall x \in \mathbb R$ then it satisfies…
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Solving Functional Equations

How would I go about solving $f(r+1) - f(r) = r^3$? I know the answer is $f(r) = c + \frac{1}{4}r^2(r-1)^2$, but I have no idea what method can be used to solve it. I have another functional equations problem that I hopefully will be able to solve…
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Why doesn't solving this functional equation in this way work?

I'd like to find a function such that $f(x+y) = f(x)^2f(y)^2.$ Yes I realize initial conditions should be specified, but I don't have that luxury, I'm just looking for any function at all and then set the constant in the family of solutions…
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$f(f(n))+f(n+1)=n+2$, where $n \in \mathbb N^*_+$

Does there exist a function $ f:\mathbb{N}_+^* \to \mathbb{N}_+^*$ such that$ f(f(n))+f(n+1)=n+2$, $\forall n\in\mathbb{N}_+^*$ ? What I found is that $f(1)=1$ because We have $f(n)\leq n$ Suppose $f(1)=a>1$ For $n=1 f(a)+f(2)=3$ So $f(a)=1 $ For…
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Find all $f$ which satisfies the condition: $f:\mathbb{R} \to \mathbb{R}, f(f(x+y)-f(x-y))=xy$

$$ f:\mathbb{R} \to \mathbb{R}, f(f(x+y)-f(x-y))=xy $$ $$ P(x, 0): f(0)=0 \\ P(0, y): f(f(y)-f(-y))=-y^2\\ P(x, x): f(f(2x))=x^2 \\ P(x, -x): f(-f(2x))=-x^2 \\ P(-x, x): f(-f(-2x))=-x^2 \\ P(-x, -x): f(f(-2x))=x^2 \\ $$ I don't have an idea of the…
RDK
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Find all functions $f: \mathbb{N}^*\to \mathbb{Z}$ satisfies $f(x+|f(y)|)=x+f(y), \forall x, y\in\mathbb{N}^*$

Find all functions $f: \mathbb{N}^*\to \mathbb{Z}$ satisfies $$f(x+|f(y)|)=x+f(y), \forall x, y\in\mathbb{N}^*$$ My current progress: For $f(y)\geq 0$, it's obvious that $f(x)=x$ satisfies. For $f(y)<0$, then $f(x-f(y))=x+f(y)$. Because of the…
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Finding all functions $f:\mathbb R\to\mathbb R$ that satisfy $f\left(f(x)-y^2\right)=f\left(x^2\right)+y^2f(y)-2f(xy)$, $\forall x\in\mathbb R$

Find all functions $ f : \mathbb R \to \mathbb R $ that satisfy $$ f \left( f ( x ) - y ^ 2 \right) = f \left( x ^ 2 \right) + y ^ 2 f ( y ) - 2 f ( x y ) \text , \ \forall x \in \mathbb R \text . $$ Till now, I have proven that it's an even…
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Finding all solutions to the functional equation $-\frac{1}{2}f(t,x) = f(2t, -x)$

I'm trying to find the class of differential equations $\frac{\mathrm dx}{\mathrm dt} = f(t,x)$ with $f$ continuous that are invariant under the change of variables $s=2t$ and $y=-x$. I have come up with this functional…
Ricardo
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Functional equation: $f:\mathbb R\to\mathbb R$ and $g:]0,\infty[\to\mathbb R$ such that $f(\ln x+\alpha\ln y)=g(\sqrt x)+g(\sqrt y)\quad\forall x,y>0$

Let $ \alpha \ne \pm 1 $ be a real number. Find all functions $ f : \mathbb R \to \mathbb R $ and $ g : ] 0 , \infty [ \to \mathbb R $ such that $$ f ( \ln x + \alpha \ln y ) = g ( \sqrt x ) + g( \sqrt y ) \quad \forall x , y > 0 \text . $$ My…
D.md
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