Questions tagged [functional-equations]

The term "functional equation" is used for problems where the goal is to find all functions satisfying the given equation and possibly other conditions. Solving the equation means finding all functions satisfying the equation. For basic questions about functions use more suitable tags like (functions) or (elementary-set-theory).

The term "functional equation" is used for problems where the goal is to find all functions satisfying the given equation(s) and possibly other conditions; e.g., the goal can be to find all continuous solutions. Solving the equation means finding all functions satisfying the given equation(s) and any additional conditions.This is different from the more common use of the word "equation", where the solutions are numbers. It is also different from the more common use of the word "functional", referring to a mapping from a space into the reals or complexes. For basic questions about functions use more suitable tags like or .

A common technique used in solving functional equations is finding some properties of satisfying functions by substituting variables for certain values in the equation. Proving properties of satisfying functions is also helpful - finding that a function is injective, surjective, involutive, and so on, is often a key step in finding all possible solutions. Other techniques such as exploiting symmetry, considering fixed points, and even using certain properties of domains (e.g. well-ordering) sometimes help.

Some well-known functional equations are:

More information can be found at Wikipedia.

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Find all function $f$ such that $f(yf(\frac{x}{y}))=xf(\frac{f(y)}{x})$

$f$ also has to satisfy several conditions: $f: [0; +\infty) \rightarrow [0; +\infty)$ $f(x) \ge x$ and $f(x) \ge 1$ $f$ is strictly increasing These conditions may not be used (this is not a problem from a MO), and I only care about all the…
gbnam8
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An increasing function $f: \mathbb{N}_+\to \mathbb{R}$ s.t. $f(xy)=f(x)+f(y)$ for all $x,y\in \mathbb{N}_+$.

We know that if a function $f:\mathbb{N}_+\to \mathbb{R}$ where $\mathbb{N}_+=\{1,2,\dots,\}$ satisfies $f(xy)=f(x)+f(y)$ for all $x,y\in\mathbb{N}_+$, then $f$ need NOT be of the form $a\log_b x$. For example, we arbitrarily assign a real number…
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TMO2022 question 5

Find all functions $f:\mathbb{R}\times\mathbb{R}\rightarrow\mathbb{R}$ that satisfied the functional equation $\displaystyle f\left(\frac{x+y+z}{3},\frac{a+b+c}{3}\right)=f(x,a)f(y,b)f(z,c)$ for every real number $x,y,z,a,b,c$ that $az+bx+cy\neq…
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Why not $e=2$? (result from a functional equation)

I'd like to know what I've done wrong when I tried to solve the functional equation below for any domain and codomain where $f$ exists and its derivate as…
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How to solve $2f(x+y) = f(x-y)f(x)$ for $f: \mathbb{R} \rightarrow \mathbb{R}$

The original question was to find $f:\mathbb{R} \rightarrow (0, \infty)$, which is fairly simple, as just plugging $y=0$ leaves us with $$f(x)[f(x)-2] = 0$$ and therefore, $f(x) = 0$ or $f(x) = 2$ for all the possible values of $x$. What I realized…
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All solutions for $f(g(x))=g(f(x))$ on $f$

This problem is a general case for Is the identity function the only solution for $f(a^x)=a^{f(x)}$? This functional equation $f(g(x))=g(f(x))$, $f,g$ invertible, get $f$ over where $x$ is, for example $f(e^x)=e^{f(x)}$,…
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Functional equation problem: $ f ( x ) + \frac 1 { x + 1 } = f ( x + 1 ) $

I've been trying to find a function that satisfies this to solve a separate problem, but I'm finding it difficult and no polynomial seems to work. $$ f ( x ) + \frac 1 { x + 1 } = f ( x + 1 ) $$
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Method of obtaining solution to functional equation: $f(x+1)-f(x)=\sin(x)$

Wolfram Alpha's solution to the problem $f(x+1)-f(x)=\sin(x)$ is: $f(x) = c_1 - \frac{\sin(x)}2 + \cot(\frac12) \sin^2(\frac{x}{2})$, but they don't provide a step-by-step solution. How could you prove this result? Context: I was trying to find the…
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Find $f: \mathbb{R} \to \mathbb{R}$ which satisfies $f(f(x)+xf(y))=x+yf(x).$

Find $f: \mathbb{R} \to \mathbb{R}$ which satisfies $f(f(x)+xf(y))=x+yf(x).$ My attempt: \begin{align} P(0, y): \; & f(f(0))=yf(0)=0. \\ \Rightarrow \; & f(0)=0. \\ \ \\ P(x, 0): \; & f(f(x))=x. \\ \ \\ f(P(x, y)): \; & f(x)+xf(y)=f(x+yf(x)).…
RDK
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How to go about finding a function that satisfies $f(x)=-f(x-1)^{2}+2^{2^{x-3}}f(x-1)+2^{2^{x-2}}$ (Or determining if such a function exists)

I don't necessarily need an answer to this particular case, but in general I have no idea how to solve this kind of problem or even how to Google for such a method. If it helps for this particular problem, the context in which this expression came…
Rilazy
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Find all functions s.t.$f(x^2-y^2)=xf(x)-yf(y)$

Find all functions such that $\forall x,y\in \mathbb R$ $$f(x^2-y^2)=xf(x)-yf(y)$$ It’s obvious that $f(0)=0$, and by setting $x=0$ then $y=0$, we get $$\cases{f(x^2)=xf(x) \\ f(-y^2)=-yf(x)=-f(y^2)}$$ Hence $$f(x^2-y^2)=f(x^2)-f(y^2)$$ My guess is…
PNT
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Delay Functional Equation: $f(t) - f(t-\tau) = u(t)$

Up front, I do not have any background in functional equations. Maybe this is an easy problem, maybe it is an impossible problem; I do not know. I am trying to solve the following equation for $f(t)$: \begin{equation} f(t) - f(t-\tau) =…
Michael M
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Finding all $f:\mathbb{R} \to \mathbb{R}$ such that $f(xf(x)+2y)=f(x^2)+f(y)+x+y-1$

$$ f:\mathbb{R} \to \mathbb{R}, f(xf(x)+2y)=f(x^2)+f(y)+x+y-1 $$ Those are my attempt. $$ P(0, y): f(2y) = f(0)+f(y)+y-1 \\ y=0; \ f(0)=2f(0)-1 \implies f(0)=1. \\ \ \\ P(x, 0): f(xf(x))=f(x^2)+x \\ x=1; \ f(f(1))=f(1)-1.\\ \ \\ P(1, f(1)):…
RDK
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Find the continuous function that satisfies $f(x+1) + 3x^2 + 5x = f(2x+1), \forall x \in \mathbb{R}$

Find the continuous function that satisfies $$f(x+1) + 3x^2 + 5x = f(2x+1), \forall x \in \mathbb{R}$$ The only hint I have is that this can be solved by making both sides have a pattern, and turn it into a "iconic" function, and then calculate its…
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Find all functions $f:\mathbb{R} \to \mathbb{R},$ which are continuous in $\mathbb{R}$ and satisfy $f(x-y)f(y-z)f(z-x)+27=0.$

Find all functions $f:\mathbb{R} \to \mathbb{R},$ which are continuous in $\mathbb{R}$ and satisfy $$f(x-y)f(y-z)f(z-x)+27=0.$$ My attempt at the solution: Let $x=y=z\Rightarrow f^3 (0)=-27 \Rightarrow f(0)=-3.$ Let $z=y$ then $f(x-y) f(y-x) f(0)…
NKellira
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