Questions tagged [improper-integrals]

Questions involving improper integrals, defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

An improper integral is defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

Specifically, an improper integral is a limit of the form:

$$\lim_{b\to \infty} \int_{a}^{b} f(x) \ dx \,,\ \lim_{a \to -\infty} \int_{a}^{b} f(x) \ dx$$ or of the form $$\lim_{c \to b^{-}} \int_{a}^{c} f(x) \ dx \,,\ \lim_{c \to a^{+}} \int_{c}^{b} f(x) \ dx$$

in which one takes a limit in one or the other (or sometimes both) endpoints.

Often, we can compute values for improper integrals, even when the function cannot be integrated in the conventional sense (as a Riemann integral, for instance), because of a singularity in the function or because one of the bounds of integration is infinite.

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Prove that $\int_{1}^{\infty} \cos(x)\cdot \frac{\sqrt{\ln(x)}\cdot x}{(x^2 + \sqrt[3]{\ln(x)})\cdot (x+5)}\,dx$ converges absolutely.

I'm attempting to prove that $\int_{1}^{\infty} \cos(x)\cdot \frac{\sqrt{\ln(x)}\cdot x}{(x^2 + \sqrt[3]{\ln(x)})\cdot (x+5)}\,dx$ converges absolutely. I've tried using the comparison test a few times, but only ended up with diverging…
Chen Mor
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How do you solve the integral $\int_{0}^{\infty}\frac{x^2 \ln x}{e^x-1} \ \mathrm d x$

Can you please help me in the step-by-step calculation of this improper intergal? $$\int_{0}^{\infty}\frac{x^2 \ln x}{e^x-1} \ \mathrm d x$$ I can solve a similar integral where I replaced $\ln(x)$ with $x$. So the integral…
user965064
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Integrating $\int_{-\infty}^{+\infty}{\frac{\sin(ax)\sinh(bx)}{(c+\cosh(bx))^2}dx}$

I want to integrate this expression : $$I = \int_{-\infty}^{+\infty}{\frac{\sin(ax)\sinh(bx)}{(c+\cosh(bx))^2}dx}$$ where $a>0$, $b>0$ and $c<0$
Mike
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Determine divergence of $\frac{x^3}{ e^x}$ over [0 $\infty$)

$$\int_{0}^{\infty} \frac{x^3}{e^x}\mathrm{d}x $$ The function is checked to converge in the interval $ ( x= 0,1), $ but how can we check whether it diverges for the full interval?
mahes
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How to solve $ \lim_{R \rightarrow \infty} \int_{-R}^{R} \frac{x}{1+x^3}$

$$ \lim_{R \rightarrow \infty} \int_{-R}^{R} \frac{x}{1+x^3} \ dx$$ It is allowed to use Taylor series if that helps in any way.
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Find the values of a>0 for which the improper integral $\int_{0}^{\infty}\frac{\sin x}{x^{a}} $ converges .

Find the values of $a>0$ for which the improper integral $$\int_{0}^{\infty}\frac{\sin x}{x^{a}}dx$$ converges. Will the Taylor series expansion of $\sin$ be a better method than testing the integral?
sejy
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Help in this improper integral

$\int_0^\infty\ln(\frac{1+x}{1-x}) \frac{dx}{x}$ can this integral be done by power series If yes I hope a full solution I dont need to use by parts
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