Questions tagged [limits]

Questions on the evaluation and properties of limits in the sense of analysis and related fields. For limits in the sense of category theory, use the tag “limits-colimits” instead.

In mathematics, a limit is the value that a function or sequence "approaches" as the input or index approaches some value. Limits are essential to (and mathematical analysis in general) and are used to define continuity, derivatives, and integrals.

The formal $\varepsilon$-$\delta$ definition of a finite limit at a point $a\in \mathbb{R}$ is:

$$\Big(\lim_{x\rightarrow a} f(x) = L \Big)\iff \Big(\forall \varepsilon >0\, \exists \delta > 0: \forall x\in D\quad 0<\vert x-a\vert <\delta \implies \vert f(x)-L\vert <\varepsilon \Big).$$

The concept of a limit of a sequence is further generalized to the concept of a limit of a topological net, and is closely related to the concepts of limit and direct limit in category theory.

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Limit of $\sin 2^n$

I am trying to show that $$\lim_{n\to \infty}\sin 2^n$$ diverges for $n \in \mathbb N$ I could show that assuming the limit converges, say to $L$ then $$L=\lim_{n\to \infty}\sin 2^{n+1}$$ $$=2\lim_{n\to \infty}\sin 2^n\lim_{n\to \infty}\cos…
user406323
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Find a limit, no Taylor formula

How to find this limit: $$ \lim_{x \to +\infty} \left[ (x+a)^{1+{1\over x}}-x^{1+{1\over x+a}}\right] $$ We know L'Hopital's rule, but don't know Taylor's formula.
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$\lim_{x\rightarrow 0}\frac{1-\cos a_{1}x \cdot \cos a_{2}x\cdot \cos a_{3}x\cdot \cdot \cdot \cdot \cdot \cos a_{n}x}{x^2}$

$\displaystyle \lim_{x\rightarrow 0}\frac{1-\cos a_{1}x \cdot \cos a_{2}x\cdot \cos a_{3}x\cdot \cdot \cdot \cdot \cdot \cos a_{n}x}{x^2}$ without D l hospital rule and series expansion. i have solved it series expansion of $\cos x$ but want be able…
DXT
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Limits at infinity by rationalizing

I am trying to evaluate this limit for an assignment. $$\lim_{x \to \infty} \sqrt{x^2-6x +1}-x$$ I have tried to rationalize the function: $$=\lim_{x \to \infty} \frac{(\sqrt{x^2-6x +1}-x)(\sqrt{x^2-6x +1}+x)}{\sqrt{x^2-6x +1}+x}$$ $$=\lim_{x \to…
Flux
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Evaluation of $\lim_{n\rightarrow \infty}\binom{2n}{n}^{\frac{1}{n}}$

Evaluation of $$\lim_{n\rightarrow \infty}\binom{2n}{n}^{\frac{1}{n}}$$ without using Limit as a sum and stirling Approximation. $\bf{My\; Try:}$ Using $$\binom{2n}{n} = \sum^{n}_{r=0}\binom{n}{r}^2$$ Using $\bf{Cauchy\; Schwarz}$…
juantheron
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$\lim_{x\to 0}\left[1^{\frac{1}{\sin^2 x}}+2^{\frac{1}{\sin^2 x}}+3^{\frac{1}{\sin^2 x}}+\cdots + n^{\frac{1}{\sin^2 x}}\right]^{\sin^2x}$

$$\lim_{x\to 0}\left[1^{\frac{1}{\sin^2x}}+2^{\frac{1}{\sin^2x}}+3^{\frac{1}{\sin^2x}}+\cdots + n^{\frac{1}{\sin^2x}}\right]^{\sin^2x}$$ Limit is of form $(\infty)^{0} $ $$\lim_{x\to 0}e^{\sin^2x\log{…
Aakash Kumar
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Showing that $\lim_{x \to 1} \left(\frac{23}{1-x^{23}}-\frac{11}{1-x^{11}} \right)=6$

How does one evaluate the following limit? $$\lim_{x \to 1} \left(\frac{23}{1-x^{23}}-\frac{11}{1-x^{11}} \right)$$ The answer is $6$. How does one justify this answer? Edit: So it really was just combine the fraction and use L'hopital's rule twice…
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When evaluating a limit by making a change of variable, how does the sign (+/-) change?

Say I have $$\lim_{x \rightarrow 4} f(x)=\frac{\sqrt{x}-2}{\sqrt{x^3}-8}.$$ My homework paper says to do a change of variable for $u=\sqrt{x}.$ If I do that, I get $$\lim_{u^2 \rightarrow 4} f(x)=\frac{u-2}{\sqrt{u^6}-8},$$ and from there we…
Jack Pan
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Find the limit $\lim_{x \to 1} \left(\frac{p}{1-x^p} - \frac{q}{1-x^q}\right) $ $p ,q >0$

I Know series expansion and L'Hospital's rule . But here both of them are not of any help.
raj
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Is it allowed to "ignore" $\lim$ in this case?

I have to prove $\lim_{x\to0}(1+x)^{1/x}=e$. Now I would like to perform the following operations: $$\lim_{x\to0}(1+x)^{1/x}=e$$$$\lim_{x\to0}\ln(1+x)^{1/x}=1$$$$\lim_{x\to0}\frac{\ln(1+x)}x=1$$ And then using L'Hôpital's rule …
355durch113
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How to solve this limit problem?-$\lim_{n\to \infty}\ \left(\frac{\ n!}{(mn)^n}\right)^{\frac{1}{n}}$

I need to find the value of- $$\lim_{n\to \infty}\ \left(\frac{\ n!}{(mn)^n}\right)^{\frac{1}{n}}$$ where $m {\in} R$ I don't know how to even start. Would someone explain it step by step, also which type of indeterminate form is this? Is there a…
user323082
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Finding limit of $\lim_{x\to 0^+}⁡\{[(1+x)^{1/x}]/e\}^{1/x}$

This is a question given in our weekly test. $$f = \lim_{x\to 0^+}⁡\{[(1+x)^{1/x}]/e\}^{1/x}.$$ Find the value of $f$. I tried to use 1^ infinity form but I didn't get it. So anybody please help me.
sai saandeep
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Is this limit indeterminate or $e^2$ or what?

What is the answer to this: $$ \lim_{x\to ∞} \left({2x+3\over 2x-1}\right)^x $$ My calculator says this is $ e^2 $ but the only answer I can get to is $ 1^\infty $, which is indeterminate.
user265554
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Limit of the form $\infty - \infty$

Consider: $$\lim_{x \to \infty} \left(x - \ln(e^x + e^{-x})\right)$$ I wasn't sure how to treat the $\infty - \infty$ property. Can I exponentiate the function to get $$e^x - (e^x + e^{-x}) = \frac{1}{e^x}$$ $$\lim_{x \to \infty} \frac{1}{e^x} =…
stariz77
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How to compute $\lim\limits_{x \to 0} \left(\frac{e^{x^2} -1}{x^2}\right)^\frac{1}{x^2}$?

I have a problem with this limit, I don't know what method to use. I have no idea how to compute it. Can you explain the method and the steps used? Thanks $$\lim\limits_{x \to 0} \left(\frac{e^{x^2} -1}{x^2}\right)^\frac{1}{x^2}$$ Note: In a…
user12
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