Questions tagged [limits]

Questions on the evaluation and properties of limits in the sense of analysis and related fields. For limits in the sense of category theory, use the tag “limits-colimits” instead.

In mathematics, a limit is the value that a function or sequence "approaches" as the input or index approaches some value. Limits are essential to (and mathematical analysis in general) and are used to define continuity, derivatives, and integrals.

The formal $\varepsilon$-$\delta$ definition of a finite limit at a point $a\in \mathbb{R}$ is:

$$\Big(\lim_{x\rightarrow a} f(x) = L \Big)\iff \Big(\forall \varepsilon >0\, \exists \delta > 0: \forall x\in D\quad 0<\vert x-a\vert <\delta \implies \vert f(x)-L\vert <\varepsilon \Big).$$

The concept of a limit of a sequence is further generalized to the concept of a limit of a topological net, and is closely related to the concepts of limit and direct limit in category theory.

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Doubts on $ \lim_{x \rightarrow 0 } (1+\sin x) ^{\frac{1}{x}}$ .

What is the limit of the following expression : $$\lim_{x \rightarrow 0 } (1+\sin x) ^{\frac{1}{x}}$$ I tried doing the following : $$\lim_{x \rightarrow 0 } (1+\sin x) ^{{\frac{1}{\sin x}}{\frac{\sin x }{x}}}$$ Now I know the formula $\lim_{x…
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What is the solution for $\lim\limits_{x\to\infty}\frac{a^x-1}{x}$, when $a > 1$?

I'm exercising on a book and I'm stuck at the following task: compute the $\lim\limits_{x\to\infty}\frac{a^x-1}{x}$, when $a > 1$. As I can see, when $x\to-\infty$, the numerator tends to $-1$ and denominator tends to $-\infty$, so the whole…
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Compute $\lim_{x\to 0^{+}}x^{x^{x}}=?$

Problem: find $\lim_{x\to 0^{+}}x^{x^{x}}$. Solution: $$\lim_{x\to 0^+}x^{x^{x}}=\lim_{x\to 0^+}e^{x^{x}\ln x}=\lim_{x\to 0^+}e^{e^{\ln x^{x}}\ln x}=\lim_{x\to 0^+}e^{e^{x\ln x}\ln x}$$ Now what should I do?
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How to solve $\lim_{x\to1}=\frac{x^2+x-2}{1-\sqrt{x}}$?

let $f(x)=\dfrac{x^2+x-2}{1-\sqrt{x}}$ How do I solve this limit? $$\lim_{x\to1}f(x)$$ I can replace the function with its content $$\lim_{x\to1}\dfrac{x^2+x-2}{1-\sqrt{x}}$$ Then rationalizing the…
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Prove $\lim_{n \to \infty}\frac{\ln (n+1)}{(n+1)(\ln^2 (n+1)-\ln^2 n)}=\frac{1}{2}$

Problem Prove $$\lim_{n \to \infty}\frac{\ln (n+1)}{(n+1)[\ln^2 (n+1)-\ln^2 n]}=\frac{1}{2},$$where $n=1,2,\cdots.$ My Proof Consider the function $f(x)=\ln^2 x.$ Notice that $f'(x)=2\cdot \dfrac{\ln x}{x}.$ By Lagrange's Mean Value Theorem, we…
mengdie1982
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Value of the limit $\lim_{x \to 0} \frac{\sin(\frac{1}{x})}{\sin(\frac{1}{x})}$

What is the value of the limit: $$\lim_{x \to 0} \frac{\sin(\frac{1}{x})}{\sin(\frac{1}{x})}$$ I think the answer should be $1$, but one I overheard one of my teachers saying that it is actually undefined.
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Is a function continuous at the point where it ends abruptly?

Is a function continuous at the point where it ends abruptly? A function $f(x)$ to said to be continuous at a point $a$ iff: 1) $f(a)$ is defined, 2)$\lim\limits_{x \to a} f(x)$ exists, and 3)$\lim\limits_{x \to a} f(x)=f(a)$ At point…
Soumee
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Limit of a function whose values depend on $x$ being odd or even

I couldn't find an answer through google or here, so i hope this isn't a duplicate. Let $f(x)$ be given by: $$ f(x) = \begin{cases} x & : x=2n\\ 1/x & : x=2n+1 \end{cases} $$ Find $\lim_{x \to \infty} f(x).$ The limit is different…
nt.bas
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How to solve this limit when direct substitution fails. Why do this work?

Say I am trying to solve this limit: $\lim_{x \to 1} \frac{x^2-1}{x-1}$ I know the answer is 2 because: $\lim_{x \to 1} \frac{x^2-1}{x-1} = $ $\lim_{x \to 1} \frac{(x+1)(x-1)}{x-1} = $ $\lim_{x \to 1} x+1 = $ But on a high level, what is going on…
Jwan622
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Proving $\lim_{n\to \infty}\frac{n^\alpha}{2^n}=0, \alpha>1$

I'm attempting to prove a basic limit: $$\lim_{n\to \infty}\frac{n^\alpha}{2^n}=0, \alpha>1$$ (It seems like this should be here somewhere already, but I wasn't able to found it through search, I possibly need help with my searching skills?…
Dahn
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Sufficient conditions to ensure the limit is zero

Let $a_n$ be a sequence, $S_n=\sum_{k=1}^n a_k$. (1) If $S_n$ is bounded, $\lim_{n\to\infty}(a_{n+1}-a_n)=0$, show $\lim_{n\to\infty}a_n=0$. (2). If $\lim_{n\to\infty}\frac{S_n}{n}=0$, $\lim_{n\to\infty} (a_{n+1}-a_n)=0$, can we show…
xldd
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How to calculate the limit: $\lim_{n\to\infty}\sum_{k=1}^n\big(\frac{k}{n}\big)^n$

How to calculate the following limit?$$\lim\limits_{n\to\infty}\sum\limits_{k=1}^n\left(\frac{k}{n}\right)^n$$ It is easy to seem the limit's existence. But I don't know how to calculate its value.
Eastsun
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Finding the limit of a 2-dimensional function

How can I prove that $\displaystyle{\lim_{(x, y) \to (0, 0)} \frac{x^3 - y^3}{x^2 + y^2}}=0$? The method I've been taught is the pinching one, where you compare the absolute value of the function to greater limits that are known to equal zero, but…
kevmo314
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$ \lim_{x \to \infty } ( \sqrt[3]{4 x^{a} + x^{2} } - \sqrt[3]{ x^{a} + x^{2} } )^{x-[x]} $

fine limit : $$ \lim_{x \to \infty } ( \sqrt[3]{4 x^{a} + x^{2} } - \sqrt[3]{ x^{a} + x^{2} } )^{x-[x]} $$ such that : $$ a \in (0,2)$$ and : $[x]: \ \ $ floor function My Try : $$f(x):=( \sqrt[3]{4 x^{a} + x^{2} } - \sqrt[3]{ x^{a} + x^{2} }…
Almot1960
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limit of $ \lim_{x \rightarrow 1} \frac{ f_{n} (x)- f_{n-1} (x)}{ (1-x)^{n} }=? $

Let $$ f_{n} (x)= x^{ x^{\scriptstyle\cdot^{\scriptstyle\cdot^{\scriptstyle\cdot^{\scriptstyle x}}}}}$$ Then $$ \lim_{x \rightarrow 1} \frac{ f_{n} (x)- f_{n-1} (x)}{ (1-x)^{n} }={?} $$ My try: \begin{align} \lim_{x \rightarrow 1}…
Almot1960
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