Questions tagged [limits]

Questions on the evaluation and properties of limits in the sense of analysis and related fields. For limits in the sense of category theory, use the tag “limits-colimits” instead.

In mathematics, a limit is the value that a function or sequence "approaches" as the input or index approaches some value. Limits are essential to (and mathematical analysis in general) and are used to define continuity, derivatives, and integrals.

The formal $\varepsilon$-$\delta$ definition of a finite limit at a point $a\in \mathbb{R}$ is:

$$\Big(\lim_{x\rightarrow a} f(x) = L \Big)\iff \Big(\forall \varepsilon >0\, \exists \delta > 0: \forall x\in D\quad 0<\vert x-a\vert <\delta \implies \vert f(x)-L\vert <\varepsilon \Big).$$

The concept of a limit of a sequence is further generalized to the concept of a limit of a topological net, and is closely related to the concepts of limit and direct limit in category theory.

43700 questions
3
votes
4 answers

What is the limit of $\lim_{x \to \infty}\sqrt[x]{2^x+3^x+4^x}$

I would like to ask for some help regarding the limit below $$\lim_{x \to \infty}\sqrt[x]{2^x+3^x+4^x}$$ Am i supposed to use the Squeeze theorem?
Aleks
  • 33
3
votes
4 answers

$\lim_{n\to \infty}\left(1 - \frac {1}{n^2}\right)^n =?$

Can you give any idea regarding the evaluation of the following limit? $\lim_{n\to \infty}\left(1 - \frac {1}{n^2}\right)^n$ We know that $\lim_{n\to \infty}\left(1 - \frac {1}{n}\right)^n = e^{-1}$, but how do I use that here?
3
votes
5 answers

How do I prove that $\lim_{n\to\infty} n\sqrt{2-2\cos(\frac{2\pi}{n})}=2\pi$

I have to prove that $$ \lim_{n\to\infty} n\sqrt{2-2\cos\left(\frac{2\pi}{n}\right)}=2\pi $$ It's geometrically obvious since it is the limit of the $n$-gons inside a unit circle. But how do I prove it?
3
votes
2 answers

How find this limit $\lim_{n\to \infty} \left(\frac{(2n)!}{2^n\cdot n!}\right)^{\frac{1}{n}}\cdot \cdots$

Find this limit $$\lim_{n\to\infty}\left(\dfrac{(2n)!}{2^n\cdot n!}\right)^{\frac{1}{n}}\left(\tan{\left(\dfrac{\pi\sqrt[n+1]{(n+1)!}}{4\sqrt[n]{n!}}\right)}-1\right)$$ I know we must use this…
math110
  • 93,304
3
votes
2 answers

Limit in which terms involve n

Limit n goes to infinity $\frac{1}{n}+\frac{1}{n+1}+......+\frac{1}{n+2n}$. Well the answer came out log[3].. but i dont know how.? I am trying for MCA. please don't tell complete answer just a hint would be useful
Amit
  • 300
3
votes
1 answer

How to show $\lim_{n\to \infty}\sqrt{n}^n (1 - (1 - 1/(\sqrt{n}^n))^{2^n})/2^n = 1$?

How can you show the following? $$\lim_{n\to \infty}\frac{\sqrt{n}^n \left(1 - \left(1 - \frac{1}{\sqrt{n}^n}\right)^{2^n} \right)}{2^n} = 1$$ It certainly seems to be true numerically when I plot it.
user35671
3
votes
2 answers

Can anyone help to get rid of this infinity-infinity?

How does one get rid of the infinities arising here? $$\lim_{x\to\infty}\left(\frac{\ln|x-1|}3-\frac{\ln|x+2|}3\right)$$ I really have no idea how to handle such natural logarithms.
Georg
  • 39
  • 1
3
votes
3 answers

Evaluate the limit $\lim\limits_{x\to0+}\left(\frac{3^x+5^x}{2}\right)^{\frac1x}$

Evaluate $$ \displaystyle\lim_{x\to0+}\left(\frac{3^x+5^x}{2}\right)^{\displaystyle\frac{1}{x}} $$ And actually I have my answer and just need someone to verify this for me since I haven't done something like this for a long time. First, to deal…
codeedoc
  • 655
3
votes
2 answers

Limit of $\sqrt[x]{1+\sin x}$ with $x$ approaching to $0$

Could anyone explain to me how to calculate the limit $\lim_{x\to0} \sqrt[x]{1+\sin x}$? I am pretty sure that the answer is $e$, but how do I arrive at that? I tried to calculate one-sided limits playing with the Squeeze Theorem: in a neighbourhood…
a student
  • 63
  • 2
3
votes
3 answers

Limits of Indeterminate Quotient: $\lim\limits_{x \to 0^+} \frac{\ln(e^x - 1)}{\ln(x)}$ and $\lim\limits_{x \to -1}(\frac1{x+1} - \frac3{x^3+1})$

I was preparing for my exam and found myself struggling with finding limits of indeterminate quotient. $$\lim\limits_{x \to 0^+} \dfrac{\ln(e^x - 1)}{\ln(x)}$$ I have tried using L'Hopital's Rule to reduce it to: $\lim\limits_{x \to 0^+}…
KillerKidz
  • 317
  • 2
  • 12
3
votes
3 answers

How do I solve this infinite limit?

I have this limit: $$ \lim_{x\to\infty}\frac{x^3+\cos x+e^{-2x}}{x^2\sqrt{x^2+1}} $$ I tried to solve it by this: $$ \lim_{x\to\infty}\frac{x^3+\cos x+e^{-2x}}{x^2\sqrt{x^2+1}} = \lim_{x\to\infty}\frac{\frac{x^3}{x^3}+\frac{\cos…
3
votes
2 answers

proving limit evaluates to infinity

I have the following question.. \begin{align*} f(n) &= n^{\sqrt{n}}\\ g(n) &= 2^{an},\quad \text{where $a > 1$} \end{align*} Evaluate the limit of $f(n)/g(n)$ as $n \to \infty$ I can intuitively see this has to be $0$, since $2^{an}$ grows much…
3
votes
4 answers

What is $x \times \sqrt x$

Does $x \times \sqrt x = x$? I thought it was correct because sqrt is the opposite of multiplying by a number, so I figured by multiplying by a number it would balance out and be that number normally, but when I tried it with my Python calculator…
3
votes
3 answers

Help me with this limit

$$ \lim_{x\to0} {{xe^x \over e^x-1}-1 \over x}$$ I know it should equal ${1 \over 2}$ because when i calculate with number like $0.0001$ the limit $\approx {1 \over 2}$ but i can't prove it.
3
votes
2 answers

Strategy for tackling the $\lim_{n\to+\infty}\frac{(-1)^nn}{(1+n)^n}$

What strategy should I use to calculate this limit? Can I avoid using Hopital? $$\lim_{n\to+\infty}\frac{(-1)^nn}{(1+n)^n}$$ Thank you in advance.
Charlie
  • 1,492