Questions tagged [limits]

Questions on the evaluation and properties of limits in the sense of analysis and related fields. For limits in the sense of category theory, use the tag “limits-colimits” instead.

In mathematics, a limit is the value that a function or sequence "approaches" as the input or index approaches some value. Limits are essential to (and mathematical analysis in general) and are used to define continuity, derivatives, and integrals.

The formal $\varepsilon$-$\delta$ definition of a finite limit at a point $a\in \mathbb{R}$ is:

$$\Big(\lim_{x\rightarrow a} f(x) = L \Big)\iff \Big(\forall \varepsilon >0\, \exists \delta > 0: \forall x\in D\quad 0<\vert x-a\vert <\delta \implies \vert f(x)-L\vert <\varepsilon \Big).$$

The concept of a limit of a sequence is further generalized to the concept of a limit of a topological net, and is closely related to the concepts of limit and direct limit in category theory.

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Calculate the following limit: $\lim\limits_{x \to 0^+}\!\big((1+x)^x-1\big)^x $

This limit is from a college admission exam in Cluj, Romania. I've tried writing the limit as $\,e^{g\cdot\ln f}$, so $\,e^{\lim\limits_{x \to 0^+}x\cdot\ln\left((1+x)^x-1\right)}$, but then I have no idea how to write $(1+x)^x$.
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For finding limit of $ \displaystyle\lim_{x\to0} \dfrac{e^{1/x} - 1}{e^{1/x} +1}$ , why L'Hospital rule is not working?

So for evaluating limit of $\displaystyle\lim_{x\to0} \frac{e^{1/x} - 1}{e^{1/x} +1 } $ I used De l'Hospital rule, as conditions are being satisfied, a) $f(x),g(x)\to \infty $ b) both are differential And upon using L'Hospital rule I get…
Manu Sm
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How to find the limit to an undefined point (asymptotic)

I am wondering about: $$ \lim_{x \rightarrow -1} \frac{x+1}{ \sqrt{x+5}-2 } $$ which seems to be an asymptotic function with each side of its corresponding graph approaching negative or positive infinity at the value of -1. Solved by WolframAlpha,…
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Request an explain for a limit

$$\lim_{x\to 0+}\exp\left(\frac{\ln \left( \frac{\ln(1+\tan 4x)}{4x} \right)}{\tan x}\right)=\lim_{x\to 0+}\exp\left(\frac{ \frac{\ln(1+\tan 4x)}{4x} -1}{x}\right)$$ Can anybody explain above equation? I can't understand right hand side of the…
deepblue
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Find out limit of the following question

let, $f(x) =x^\frac{1}{3}$ be a diffrentiable function on $ (0, \infty).$ Given that $$\frac{f(3+h) -f(3)}{h}=f'(3+\theta(h)h)$$ Then find out $\lim_{h\to 0+} \theta(h) =? $ Since, $f$ is diffrentiable at $3$ , I think limit must be $0$ as it tends…
Nope
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Find n given that $\lim\limits_{x\rightarrow0} \frac{1-\sqrt{\cos2x}.\sqrt[3]{\cos3x}.\sqrt[4]{\cos4x}...\sqrt[n]{\cos{nx}}}{x^2} = 10$

I'm trying to solve this rather interesting problem. We have been given that $\lim\limits_{x\rightarrow0} \frac{1-\sqrt{\cos2x}.\sqrt[3]{\cos3x}.\sqrt[4]{\cos4x}...\sqrt[n]{\cos{nx}}}{x^2}$ = 10 and we are required to find n. This is the…
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Evaluating $\lim\limits_{x\rightarrow0} \frac{e^{-\frac{x^2}{2}}-\cos x}{x^3\sin x}$

I'm trying to evaluate $$\lim\limits_{x\rightarrow0} \frac{e^{-\frac{x^2}{2}}-\cos x}{x^3\sin x}.$$ I can see the $\frac{0}{0}$ form, so I'll use L'Hôpital's rule. However, I'll eliminate the sine function in the denominator by multiplying the…
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Studying $\lim_{x \rightarrow 0^+} \frac{xe^{-2x^2}-\sin(x)+\beta x^3}{x^{\alpha}\cos(x^2)}$

Study the following limit with $\alpha$ and $\beta$ parameters: $$\lim_{x \rightarrow 0^+} \frac{xe^{-2x^2}-\sin(x)+\beta x^3}{x^{\alpha}\cos(x^2)}$$ My attempt: $$\frac{xe^{-2x^2}-\sin(x)+\beta x^3}{x^{\alpha}\cos(x^2)} \;\sim_{0}\;…
asv
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Limits of Sequences

I'm having trouble calculating this limit directly : $$\lim_{n\to\infty}\frac{(2n+1)(2n+3)\cdots(4n+1)}{(2n)(2n+2)\cdots(4n)}$$ It can be calculated using the inventory method and the result…
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Find $\lim_{x \to \infty} x^{(2-\sin(\frac{2}{x}))}(x\sin(\frac{2}{x})-2)$ with L'Hospital's Rule

I try to find $\lim_{x \to \infty} x^{(2-\sin(\frac{2}{x}))}(x\sin(\frac{2}{x})-2)$ with L'Hospital's Rule but get stuck. Here is my attempt. Let substitute $y = \dfrac{1}{x}$ \begin{align*} \lim_{x \to \infty}…
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Proving $\lim _{x \to \infty }\frac{1 - 2x^2}{x^2 + 3}\ = -2$

I solved it using the definition of limit to the $\left|\frac{-7}{x^2 +3}\right| < \varepsilon$ Then $\varepsilon > \frac{7}{x + 3} > \frac{7}{x^2 +3}$ Then $x > \frac{7}{\varepsilon} - 3$ But my teacher said this was wrong and I have to fix it…
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Two different answers to $\lim_{x \to -\infty} \frac{8x^2-2x^3+1}{6x^2+13x+4}$

Let us evaluate $$\lim_{x \to -\infty} \frac{8x^2-2x^3+1}{6x^2+13x+4}$$ Dividing the numerator and denominator by $x^3$ we will be left with $$\lim_{x \to -\infty} \frac{\frac{8}{x}-2+\frac{1}{x^3}}{\frac{6}{x}+\frac{13}{x^2}+\frac{4}{x^3}}$$ and…
madness
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Evaluating limits without the usage of graph

$\lim_{x \to 1} {\frac{x^3-1}{x^2-1}}$ Is there a way to evaluate this limit when $x$ Approaches 1 without using a graph? From graph, its easy to see, that as its $\frac{3}{2}$ but how do we simplify and break the fraction down because if I…
user307640
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How to prove $\lim_{x\to1} \log(x)=0$ in a fair way?

I am trying to prove the following limit with the definition: $$\lim_{x\to1} \log(x)=0$$ That is - I must prove that for all $\epsilon>0$, there exists $\delta >0$ such that: $$ 0<|x-1|< \delta \implies |\log x - 0|< \epsilon$$ So - my trouble is to…
Red Banana
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Let $a$ be an integer such that $\lim_{x \to 7}\frac{18-[1-x]}{[x-3a]}$ exists. What should be $a$?

Problem. Let $a$ be an integer such that $$ \lim_{x \to 7}\frac{18-[1-x]}{[x-3a]} $$ exists where $[t]$ is the greatest integer function. What should be that value of $a$? My approach was divided in three steps: Directly put $x=7$. That gave me…
VMnM7
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