Questions tagged [limits]

Questions on the evaluation and properties of limits in the sense of analysis and related fields. For limits in the sense of category theory, use the tag “limits-colimits” instead.

In mathematics, a limit is the value that a function or sequence "approaches" as the input or index approaches some value. Limits are essential to (and mathematical analysis in general) and are used to define continuity, derivatives, and integrals.

The formal $\varepsilon$-$\delta$ definition of a finite limit at a point $a\in \mathbb{R}$ is:

$$\Big(\lim_{x\rightarrow a} f(x) = L \Big)\iff \Big(\forall \varepsilon >0\, \exists \delta > 0: \forall x\in D\quad 0<\vert x-a\vert <\delta \implies \vert f(x)-L\vert <\varepsilon \Big).$$

The concept of a limit of a sequence is further generalized to the concept of a limit of a topological net, and is closely related to the concepts of limit and direct limit in category theory.

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How to find $\lim_{x \to 0}\frac{\cos(ax)-\cos(bx) \cos(cx)}{\sin(bx) \sin(cx)}$

How to find $$\lim_\limits{x \to 0}\frac{\cos (ax)-\cos (bx) \cos(cx)}{\sin(bx) \sin(cx)}$$ I tried using L Hospital's rule but its not working!Help please!
user220382
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About negligible terms in a limit

When is it valid to deal with a term as a "negligible" one in a limit? I am asking this question because I usually do not take limits very seriously, and I can do a lot of "illegal" moves just to evaluate and get back to the important thing. This…
user230734
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Proof of limit of $x^3\ln x$ as $x$ goes to 0

I am trying to find an $\epsilon$-$\delta$ proof of \begin{equation*} \lim_{x \to 0^{+}} x^3\ln x=0 \end{equation*} Is there a way to construct such a $\delta$ and not find it by educated guessing?
Emmet
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$ \lim_{x\rightarrow 0^{+}}\frac{\sin ^{2}x\tan x-x^{3}}{x^{7}}=\frac{1}{15} $

Can someone show me how is possible to prove that \begin{equation*} \lim_{x\rightarrow 0^{+}}\frac{\sin ^{2}x\tan x-x^{3}}{x^{7}}=\frac{1}{15} \end{equation*} but without Taylor series. One can use L'Hospital rule if necessary. I was not able.
Idris Addou
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A limit involving nested trigonometric functions and logarithms

Evaulate $$ L = \lim_{x \to 0} \frac{1-\cos(\sin x)+\ln(\cos x)}{x^4}. $$ I can solve it using Maclaurin series, but I'm trying to figure out a way to the solution without using it. L'Hopital would probably work but needs to be applied 4 times,…
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How to find the limit of this seq.?

Please help me to solve this limit: $$ \lim _{n\to \infty }\left(\frac{1}{n^2}\sqrt[n^2]{e}+\frac{2}{n^2}\sqrt[n^2]{e^4}+\frac{3}{n^2}\sqrt[n^2]{e^9}+...+\frac{n}{n^2}\sqrt[n^2]{e^{n^2}}\right) $$ Thank you
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Find the value of the given limit.

The value of $\lim_{x\to \infty} (x+2) \tan^{-1} (x+2) - x\tan^{-1} x $ is $\dots$ a) $\frac{\pi}{2} $ $\qquad \qquad \qquad$ b) Doesn't exist $\qquad \qquad \qquad$ c) $\frac{\pi}{4}$ $\qquad \qquad$ d)None of the above. Now, this is an objective…
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Limit $\lim_{x \to0^-}\ln x$

Can i ask for the limit as $x$ approaches $\lim_{x \to 0-}\ln x$? Please explain. Its because since the limit of a function only exists if the lim as $x$ approaches some number $n$ from both the positive and negative side is the same, im not sure…
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Compute $\lim \limits_{x\to\infty} (\frac{x-2}{x+2})^x$

Compute $$\lim \limits_{x\to\infty} (\frac{x-2}{x+2})^x$$ I did $$\lim_{x\to\infty} (\frac{x-2}{x+2})^x = \lim_{x\to\infty} \exp(x\cdot \ln(\frac{x-2}{x+2})) = \exp( \lim_{x\to\infty} x\cdot \ln(\frac{x-2}{x+2}))$$ But how do I continue? The hint…
Jiew Meng
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Limits and exponentials

Asked to find $\lim_{n\to\infty}a_n$ where $$a_n = \left(1+\dfrac1{n^2}\right)^n$$ I know that the limit = 1, and can get to this by saying $\ln a_n=n\ln\left(1+\dfrac1{n^2}\right)$ and going from there. My question is: would it also be enough to…
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Why does this converge to $\|x\|$

Take $h_n(x) = x^{1+ \frac{1}{2n-1}}$ on the set $[-1,1]$ Then if we take $\lim_{n \to \infty} h_n(x)$ shouldn't this converge to $x$ seeing as $$\lim_{n \to \infty} h_n(x) = x \lim_{n \to \infty} x^{\frac{1}{2n-1}} = x?$$
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The limit $\lim_{n\to \infty}\frac{T_n(n)}{e^n}$ where $T_n(x)$ is the Taylor polynomial of $e^x$

From working on a problem I was lead to consider the function $\frac{T_n(n)}{e^n}$ where $T_n(x)$ is the $n$'th order Taylor polynomial of $e^x$. Numerical evidence suggest that $$\lim_{n\to \infty} \frac{T_n(n)}{e^n} \equiv\lim_{n\to \infty}…
Winther
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Limits: dividing by the highest power does not work in this case

I believe to solve expressions like: $$\lim_{x\to \infty} (2x^2 + 1)$$ we need to divide each term in the numerator and denominator by the highest power. In the previous case, the highest power is $x^2$, so we get $$\lim_{x \to \infty} \left(2 +…
Jiew Meng
  • 4,593
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$ \lim_{x \to \infty} (\frac {x+1}{x+2})^x $

For the limit $ \lim_{x \to \infty} (\frac {x+1}{x+2})^x $ could you split it up into the fraction $ \lim_{x \to \infty} (1 - \frac{1}{x+2})^x$ and apply the standard limit $ \lim_{x\to+\infty} \left(1+\frac{k}{x}\right)^x=e^k $ or would you have to…
Pyrons
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Calculating the limit: $\lim \limits_{x \to 0}$ $\frac{\ln(\frac{\sin x}{x})}{x^2}. $

How do I calculate $$\lim \limits_{x \to 0} \dfrac{\ln\left(\dfrac{\sin x}{x}\right)}{x^2}\text{?}$$ I thought about using L'Hôpital's rule, applying on "$\frac00$," but then I thought about $\frac{\sin x}{x}$ which is inside the $\ln$: it's not…