Questions tagged [logarithms]

Questions related to real and complex logarithms.

The logarithm is generally defined to be an inverse function for the exponential. If $x > 0$ is a real number and $b > 0$, $b \ne 1$, then the base-$b$ logarithm is defined by

$$\log_b(x) = y \iff b^y = x$$

The most commonly used bases are base $10$ and $2$ (which frequently arises in computer science), and particularly base $e$. The natural logarithm $\ln$ is defined to be $\log_e$.

Alternatively, the natural logarithm can be defined to be a primitive of the function $$f(t) = \frac{1}{t}$$ subject to the condition that $\ln{1} = 0$.

In the study of complex numbers, the solutions $a$ of $e^{a} = z$ are called complex logarithms. This uniquely specifies the modulus of $a$, but not its argument; as such, we define the principal logarithm $\operatorname{Log}(re^{i\theta}) = \ln{r} + i \theta$, with the restriction $-\pi < \theta \le \pi$ (or alternatively, $0 \le \theta < 2\pi$). This leads to a branch cut, or discontinuity - alternatively, the complex logarithm can be viewed as a multi-valued function.

Reference: Logarithm.

This tag often goes along with .

10168 questions
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Multiplying two logarithms (Solved)

I was wondering how one would multiply two logarithms together? Say, for example, that I had: $$\log x·\log 2x < 0$$ How would one solve this? And if it weren't possible, what would its domain be? Thank you! (I've uselessly tried to sum the logs…
Alex
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Product of logarithms, prove this identity.

Is it hard to prove this identity: $$2 \log (a) \log (b)=\log(a b)^2-\log(a)^2-\log(b)^2$$ for $a>1$ and $b>1$?
Mats Granvik
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Solving $8n^2=64 n\log(n)$

I am trying to solve: $$8n^2=64 n\log(n)$$ I factored out $8n$ and was left with $$n = 8 \log n$$ but I do not know how to proceed from here, I checked the solution on Wolfram Alpha, and they were able to simplify it down to: which is…
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Antilog of -1.6132 using anti-log tables

I have different answers for antilog(-1.6132) using antilog tables and the calculator. Using this site as reference https://byjus.com/maths/antilog-table/. Mantissa: 6132 Characteristic: -1 Corresponding value against mantissa (using antilog…
Imtiaz
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Solving for $x$ in $3^{2x+1} = 3^x + 24$

I'm having trouble solving this equation step by step: $$3^{2x+1} = 3^x + 24$$ I've tried to take the log of both sides but then I am stuck with the right hand side being $\log(3^x + 24)$. I've found the answer to '$x$' by trial and error but cannot…
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Solving a logarithmic equation $\log_2 (2^x-1)+x=\log_4 (144)$

I need to solve this: $$\log_2 (2^x-1)+x=\log_4 (144)$$ I can work out that $x=\log_2 (2^x)$ and $\log_4 (144)=log_2(12)$ but I'm stuck after that.
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Clarify why all logarithms differ by a constant

One of the rules of logarithms that I've been taught is: $\log_b(x)$ is equivalent to $\dfrac{\log_k(x)}{\log_k(b)}$. Recently I've also seen another rule that says: $\log_b(x)$ is equivalent to $\log_b(k)\log_k(x)$. Are these equivalent (perhaps…
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Solving the exponential equation: $3 \cdot 2^{2x+2} - 35 \cdot 6^x + 2 \cdot 9^{x+1} = 0$

I have this exponential equation that I don't know how to solve: $3 \cdot 2^{2x+2} - 35 \cdot 6^x + 2 \cdot 9^{x+1} = 0$ with $x \in \mathbb{R}$ I tried to factor out a term, but it does not help. Also, I noticed that: $2 \cdot 9^{x+1} = 2 \cdot…
rubik
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Proof of logarithm power change

I am not too sure how to explain this in words. So the question is proofing that $a ^{\log_bc} = c ^{\log_b a}$ So far what I have done was: I cannot think of anything else, I mean if I do the same for $c ^{\log_b a}$, I would be getting $\log_b…
Sarp Kaya
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Sum of Logarithm Arguments

This is a very simple question I suspect but I just cannot seem to nail it... I have values for $X,Y,Z $, where $X =\log (x)$, $Y = \log (y)$ and $Z = \log (z)$ and I need to calculate $x + y + z$, well actually $\log(x + y + z)$ would suffice. Is…
Jon
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Show that there exists an integer that is a power of 5 with the first 4 digits being 2018.

I know the problem can be expressed in the following way. Let $a,b \in \mathbb{Z}^+$ such that $2018\:\times\:10^b < 5^a < 2019\:\times\:10^b$ Taking logs, I get $b + \log 2018 < a \log 5< b + \log 2019$. Not quite sure how else to proceed though.
Haikal Yeo
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Solving equation $\log_y(\log_y(x))= \log_n(x)$ for $n$

I'm just wondering, if I log a constant twice with the same base $y$, $$\log_y(\log_y(x))= \log_n(x)$$ Can it be equivalent to logging the same constant with base $n$? If yes, what is variable $n$ equivalent to?
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Sort those 3 logarithmic values without using calculator

I found this problem interesting, namely we are given three values: $$\log_{1/3}{27}, \log_{1/5}{4}, \log_{1/2}{5}$$ We want to sort those values without using calculator. So I decided to work on them a little bit before comparing anything. Here is…
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Is there a half log function?

Is there a half log function $f(x)$ such that $f ( f(x) ) = \ln x$ (or $\log x$ with any base). More generally, is there partial logarithmic function to perform $0.5, 0.3, \pi$ etc of a log function? Thank you.
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Prove that $5/2 < e < 3$?

Prove that $$\dfrac{5}{2} < e < 3$$ By the definition of $\log$ and $\exp$, $$1 = \log(e) = \int_1^e \dfrac{1}{t} dt$$ where $e = \exp(1)$. So given that $e$ is unknown, how could I prove this problem? I think I'm missing some important…
roxrook
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