Questions tagged [metric-spaces]

Metric spaces are sets on which a metric is defined. A metric is a generalization of the concept of "distance" in the Euclidean sense. Metric spaces arise as a special case of the more general notion of a topological space. For questions about Riemannian metrics use the tag (riemannian-geometry) instead.

A function $d: M\times M\to \mathbb R$ is called a metric if for all $x,y,z \in M$ we have

  1. $d(x,y)=0\iff x=y$
  2. $d(x,y)\geq 0$
  3. $d(x,y)=d(y,x)$
  4. $d(x,y)+d(y,z)\geq d(x,z)$.

It is a generalisation of "distance". A metric space is now defined as an ordered pair $(M,d)$, where $M$ is a set and $d:M\times M\to R$ is a metric.

An $\varepsilon$-neighbourhood of $x$ is defined as the set $$B_\epsilon(x):=\{y\in M\mid d(x,y)<\varepsilon\}.$$ $B_\varepsilon(x)$ is commonly also known as the open ball of radius $\varepsilon$ around $x$. All open balls form a base for a topology on $M$. Although all metric spaces are topological spaces, the converse is generally not true.

Some different types of metric space include

  1. Complete metric spaces (every Cauchy sequence converges)

  2. Bounded metric spaces (every metric is bounded by a finite value)

  3. Compact metric spaces (every sequence has a convergent subsequence)

  4. Locally compact metric spaces (every point has a compact neighbourhood)

  5. Separable metric spaces (it possesses a countable dense subset).

15788 questions
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Contact point VS boundary point

What is the difference between a contact point and a boundary point on a metric space ? In topology and mathematics in general, the boundary of a subset S of a topological space X is the set of points which can be approached both from S and from the…
Jim Art
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All metrics on set of size 2

I was trying to determine all metrics possible on a set $X$ when size of $X$ equals two. It is clear that the discrete metric is one possible metric. But is the only requirement that the metric assign different positive real number to $d(x,y)$ and…
Just Me
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Can you help me clean up this proof that a point and a disjoint closed set of a metric space can be "separated" by open sets.

The question is, "Let $X$ be a metric space, prove the following: any point and a disjoint closed set in $X$ can be separated by open sets, in the following sense that if $x$ is a point and $F$ is a closed set which does not contain $x$, then…
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Prove that *every* subset of a metric space $M$ can be written as the intersection of open sets.

Prove that every subset of a metric space $M$ can be written as the intersection of open sets. My attempt: If $A\subset M$ is open, $A$ can be written as $A\cap M$, which is the intersection of 2 open sets. If $A\subset M$ is closed, it can…
Siddhartha
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Closed subset of $\mathbb{R}^n$ and frontier

Let $F$ be a closed subset of $\mathbb{R}^n$. Show that there exists $X \subset \mathbb{R}^n$ such that $\partial X = F$ (Frontier of $X$ is equal to $F$). Is this fact is true in general, i.e., for an arbitrary metric space $M$?
Cgomes
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Is $(X,d)$ a metric space?

$X = C_{[a,b]}^1$, $d(f,g) = \displaystyle\max_{x \in [a,b]} |f'(x) - g'(x)| + |f(a) - g(a)|$. Is $(X,d)$ a metric space? My attempt: These conditions $d(f,g) \geq 0$, $d(f,g) = 0$, $d(f,g) = d(g,f)$ are trivial We condider the last condition for a…
Minh
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Is it possible to characterise a metric space by its diameter function?

This relates to an earlier conjecture that was shown false. Question: is it possible to characterize a metric space by its diameter function? Here are my thoughts so far. Assume a diameter function that is non-negative, and which satisfies…
goblin GONE
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Closed balls in metric space with trivial metric

The problem is this: let two balls closed be in the metric space $(\Bbb{R},d)$ with the trivial metric, show that if the two balls intersect, then one is included in the other. I conclude that both balls are equal, and therefore one is included in…
Lala XD
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does this function fail to be a metric because the triangle inequality does not hold?

given the function $d:\{0,1\}^\Bbb N \times \{0,1\}^\Bbb N \rightarrow \Bbb R_0^+ $ $d(a,b):= \begin{Bmatrix} 0 &if&a=b\\\frac{1}{min\{k\in\Bbb N|a_k\neq b_k\}} & if & a\ne b \end{Bmatrix}$ Now we are given in the definition of d that d(a,b)=0 iff…
excalibirr
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Is this the correct way to show this function is a metric?

Is this the correct way to prove that this is metric function ? let $d_1:\Bbb Z \times \Bbb Z \rightarrow \Bbb R^+_0$ $d(m,n):=|m-n|^3$ i. $d(x,y)\geq 0$ with equality iff x=y $|m-n|\geq0$ because it is an absolute value if $m \neq n$ $|m-n|>0$ if…
excalibirr
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How to prove triangle inequality for the metric $d(x,y)=\frac{2|x-y|}{\sqrt{\left(1+|x|^2\right)}+\sqrt{\left(1+|y|^2\right)}}$

How to prove triangle inequality for the metric $$d(x,y)=\frac{2|x-y|}{\sqrt{1+|x|^2}+\sqrt{1+|y|^2}},$$ for all $x,y\in \mathbb{C}?$
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$A, B$ be two subsets of a metric space such that $\bar A \cap \bar B = \emptyset$, then prove that $\partial(A\cup B)=\partial A \cup \partial B$

To prove the above-mentioned statement, I am just able to show $\partial(A\cup B)\subseteq \partial A \cup \partial B$ in the following manner $\partial A \cup \partial B=$$(\bar A \backslash A^\circ)\cup (\bar B \backslash B^\circ)=(\bar A \cup…
MathBS
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Show that $(cl(A))'=A'$ where $A\subseteq E$, $(E, d)$ is a metric space and $d$ is the metric function.

I am trying to prove that $(cl(A))'=A'$ in a metric space $(E, d)$ where $d$ is the metric function. I'll explain my notation. If $A\subseteq E$, $x\in E$ is an accumulation point of $A$ if and only if for every open set $S\subseteq E$ (containing…
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Disjoint union of proper metric spaces

A proper metric space is one in which closed balls are compact. Given a countably infinite collection of proper metric spaces, can their disjoint union be equipped with a proper metric?
cyc
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Metric spaces (closed set/infimum)

Let $A \subset \mathbb{R^n}$ be a closed subset and $x \in \mathbb{R^n}$. How to prove that a point $p \in A$ exists such that $d_2(p,x)=\inf\limits_{q \in A}d_2(q,x)$? I tried to focus upon the case that $A$ is a bounded set and compact. I used: $q…
Humertun
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