Questions tagged [metric-spaces]

Metric spaces are sets on which a metric is defined. A metric is a generalization of the concept of "distance" in the Euclidean sense. Metric spaces arise as a special case of the more general notion of a topological space. For questions about Riemannian metrics use the tag (riemannian-geometry) instead.

A function $d: M\times M\to \mathbb R$ is called a metric if for all $x,y,z \in M$ we have

  1. $d(x,y)=0\iff x=y$
  2. $d(x,y)\geq 0$
  3. $d(x,y)=d(y,x)$
  4. $d(x,y)+d(y,z)\geq d(x,z)$.

It is a generalisation of "distance". A metric space is now defined as an ordered pair $(M,d)$, where $M$ is a set and $d:M\times M\to R$ is a metric.

An $\varepsilon$-neighbourhood of $x$ is defined as the set $$B_\epsilon(x):=\{y\in M\mid d(x,y)<\varepsilon\}.$$ $B_\varepsilon(x)$ is commonly also known as the open ball of radius $\varepsilon$ around $x$. All open balls form a base for a topology on $M$. Although all metric spaces are topological spaces, the converse is generally not true.

Some different types of metric space include

  1. Complete metric spaces (every Cauchy sequence converges)

  2. Bounded metric spaces (every metric is bounded by a finite value)

  3. Compact metric spaces (every sequence has a convergent subsequence)

  4. Locally compact metric spaces (every point has a compact neighbourhood)

  5. Separable metric spaces (it possesses a countable dense subset).

15788 questions
1
vote
1 answer

Proving that if $d(x, a) < \varepsilon$ for every $a \in A$, then $d(x, b) \geq \varepsilon$ for every $b \in X \setminus A$

I want to prove the following result: Let $(X, d)$ be a metric space. Then $$\mathring E = \{x \in X \mid d(x, X \setminus E) > 0\}$$ where $d(x, A) = \inf\limits_{y \in A} d(x, y)$. This is a part of my proof. But I'm not sure about a…
rubik
  • 9,344
1
vote
2 answers

$d(a,X) = 0 \iff X\cap U\neq \emptyset$ (distance from set equals 0 iff is adherent point)

I need to prove that: $$d(a,X) = 0 \iff X\cap U \neq \emptyset$$ for all open set $U$ that contains $a$ My idea is that if $d(a,X) = 0$, then there is a point $b\in X$ such that $d(a,b)=0$. In some way, I should be able to construct a ball that…
1
vote
1 answer

How can i prove those metrics are the equivalent?

We got 2 metric spaces in $\mathbb{R}$, and these metrics: $d_1(x,y):= |x-y|$ and $d_2(x,y):= |x^3-y^3|$. I'm asked to prove this by proving that the identity which goes from one metric space to the other is an homeomorphism. I'm not sure what…
1
vote
0 answers

Can anyone tell me what is the difference between strong and weak contraction (metric spaces)?

In my assignment a question was given on strong contraction. I could understand the meaning and searched in wikipedia and also in books but I could find the definition of it. Can anyone give the definition of strong contraction and how it is…
1
vote
2 answers

Metric space extension

Is single point extension of a metric space possible? Let $(X,d)$ be a metric space and $\overline{X}=X\cup \{\overline{x}\}$. Is it possible to find a metric $\overline{d}$ for which $(\overline{X},\overline{d})$ is a metric space and…
bc78
  • 466
1
vote
1 answer

If $C$ is the Cantor set, then $C = \text{bd}(C)$?

Let $C$ bethe Cantor set, then is it true that $C = \text{bd}(C)$? I know that the $C$ is closed since it the intersection of closed intervals, which is always closed. This means that $C$ contains $\text{bd}(C)$. To show that $C = \text{bd}(C)$ I…
fosho
  • 6,334
1
vote
0 answers

Showing that If $A$ and $B$ are closed disjoint subsets of a metric space then there exists disjoint open sets containing $A$ and $B$.

Suppose $A,B$ are closed subsets of a metric space $(X,d)$. I am trying to show that there exist disjoint open sets $U,V$ such that $U$ contains $A$ and $V$ contains $B$. I managed to find an open set $U$ that contains $A$ as follows: Recall that…
fosho
  • 6,334
1
vote
1 answer

Pick $b\notin B[a,r]$ show that there exists $s>0$ such that $B[a,r]\cap B[b,s]$ is empty

I need to solve this question: Pick $b\notin B[a,r]$ show that there exists $s>0$ such that $B[a,r]\cap B[b,s]$ is empty My idea is to suppose a point $p$ in the intersection. Then $$d(a,b)\le d(a,p)+d(p,b)$$ Note that $d(a,p) = r$ and $d(p,b)…
1
vote
1 answer

How to show this property for the diameter of a set

Let $(M, d)$ be a metric space and $A\subset M$ such that $$\mathrm{diam}(A)=\sup_{a,b\in A}d(a,b)=D<\infty.$$ How can I prove that for any $\varepsilon> 0$ there is $x\in A$ such that $A\subset\{y\in M: d(x,y)<(\varepsilon +D)\}$?
John
  • 11
1
vote
3 answers

In a complement of a closed set find a point that is closest to any point in the closed set

Is it true that for $U$ closed and nonempty in a metric space $X$, let $a\in X\setminus U$, then there exists a $b\in U$ such that $d(a,b)\leq d(a,x) \forall x\in U$? I think it is correct because it asks for a "boundary" of a closed set. But how…
verticese
  • 695
1
vote
0 answers

Does a mapping from one metric space to another metric space preserve star-likeness of regions?

Let $X$ be a vector space, let $M_1 = \left(X, d_1\right)$ be a metric space and let $M_2 = \left(X, d_2\right)$ be another one. $f : M_1 \to M_2$ is continuous and the origin is a fixed point. $f$ preserves distances in the following…
Axoren
  • 2,303
1
vote
2 answers

If $|X|<\infty$ then T metrisable $\rightarrow$ T discrete topology.

If $|X|<\infty$ then T metrisable $\rightarrow$ T discrete topology. I said let $d$ be a metric and let $x \in X$. I want to show that $\{x\}$ is open. How do I show this?
Paul
  • 11
  • 1
1
vote
1 answer

Proving that a set is closed with respect to a defined metric

Let $M = [0,1]^{[0,1]}$ Prove that the set of increasing functions $$ J := \{f \in M : \forall \space a,b \in [0,1], a \leq b : f(b) − f(a) \geq 0 \} $$ is a $d$-closed subset of $M$ where $d = d_∞ \colon M \times M \to \mathbb{R}^+_0$ is…
Gregory Peck
  • 1,717
1
vote
1 answer

In a complete metric space with no isolated points , show that the intersection of open and dense sets with a countable set is non-empty.

Let $(X,d)$ be a complete metric space with no isolated points. I want to prove that for every $(Gn)$ sequence of open and dense subsets of $X$ and for every countable set $A$$\subseteq$$X$ we have that…
Stef M
  • 111
1
vote
0 answers

Which of the following is true for a metric space?

Let $(X,d)$ be a metric space. Which of the following is possible? $X$ has exactly 3 dense subsets. $X$ has exactly 4 dense subsets. $X$ has exactly 5 dense subsets. $X$ has exactly 6 dense subsets. I've absolutely no clue as to how to tackle…
Mathronaut
  • 5,120