Questions tagged [metric-spaces]

Metric spaces are sets on which a metric is defined. A metric is a generalization of the concept of "distance" in the Euclidean sense. Metric spaces arise as a special case of the more general notion of a topological space. For questions about Riemannian metrics use the tag (riemannian-geometry) instead.

A function $d: M\times M\to \mathbb R$ is called a metric if for all $x,y,z \in M$ we have

  1. $d(x,y)=0\iff x=y$
  2. $d(x,y)\geq 0$
  3. $d(x,y)=d(y,x)$
  4. $d(x,y)+d(y,z)\geq d(x,z)$.

It is a generalisation of "distance". A metric space is now defined as an ordered pair $(M,d)$, where $M$ is a set and $d:M\times M\to R$ is a metric.

An $\varepsilon$-neighbourhood of $x$ is defined as the set $$B_\epsilon(x):=\{y\in M\mid d(x,y)<\varepsilon\}.$$ $B_\varepsilon(x)$ is commonly also known as the open ball of radius $\varepsilon$ around $x$. All open balls form a base for a topology on $M$. Although all metric spaces are topological spaces, the converse is generally not true.

Some different types of metric space include

  1. Complete metric spaces (every Cauchy sequence converges)

  2. Bounded metric spaces (every metric is bounded by a finite value)

  3. Compact metric spaces (every sequence has a convergent subsequence)

  4. Locally compact metric spaces (every point has a compact neighbourhood)

  5. Separable metric spaces (it possesses a countable dense subset).

15788 questions
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Show that if Y is open in X and U is open in Y, then U is open in X

I need help proving the following: Let $(X, d)$ be a metric space and $Y\subseteq X$ be a subspace. Show that if Y is open in X and U is open in Y, then U is open in X. I know that if Y is open in X then ($\forall$$x$$\in$ Y) ($\exists$$r$>0)…
TanEma
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$X$ complete. If $M \subset X$ closed then $(M,d)$ is complete.

Here is what I came up with. Since $M$ is closed it follows that $U=X \backslash M$ is open. Then $(X \backslash M, d)$ can not be complete, because if $(X\backslash M, d)$ is complete this would implie that $X \backslash M$ is closed, which is not…
Olba12
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A hint on how to prove that if $(M,d)$ is complete then $M$ is closed.

I would like to recieve a hint on how to get started with a proof on $M \subset X$ and $(M,d)$ is complete then $M$ is closed I highly believe that there are alot of proofs regarding the above, but I'm afraid that if I google it I will be exposed…
Olba12
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Difference between open set and nbd

Plz clearly explain me difference between neighborhood of set and open set because according to me both definition are same.
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Where does this inequality come from? I don't see how is relevant.

I understand it, but I don't know how I would find my way to it by myself, I've made some sketches to try to understand. But still i feel like missing something. Hope you understand me. $|d(x,y)-d(z,t)|\leq d(x,z)+d(y,t)$ I understand that the…
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Open sets in Y where Y is a subspace of the metric space (X,d) with the induced metric

I want to prove the following: Let $Y\subset X$, where $(X,d)$ is a metric space and $d_Y$ is the induced metric on Y. Show that: $U\subset Y$ is open in Y if and only if there exists $V\subset X)$ such that $U=V\cap Y$. Quite frankly, I have no…
Joogs
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Distance and open sets in a metric

I am hoping to prove the following: $A \subset X$ is such that if for any $x ∈ X$ and $\epsilon > 0$ there exists $y ∈ A$ such that $d(x, y) < \epsilon$ is equivalent to saying for any $B \subset X, B$ nonempty and open, then $B \cap A$ is…
Johner
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Proving union of infinitely many closed sets need not be closed

let $B(p_0,r)$ be a open ball entered at $p_o$ with a radius of $r$. This ball could be written as union of infinitely many closed balls. Therefore union of closed balls can generate an open ball. How can I improve my proof here? Am I on the right…
user346936
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In a Hilbert space $H$, $\exists! b \in F \subseteq H$ such that $d(a,b) = d(a,F)$

I'm trying to do the following exercise: Let $H$ a Hilbert space (Vector space complete with inner product), $F \subseteq H$ a closed convex set and $a \in H$. Show that $\exists! b \in F \subseteq H$ such that $d(a,b) = d(a,F)$ My teacher gave a…
user286485
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Why does finite diameter imply boundedness of a set

Let $S$ be a subset of $\mathbb{R}$. If the diameter of $S$ is finite, that is, $\forall x, y \in S$, if $|x-y| \leq M$ for some non-negative real number $M$, why does it imply that $\forall x \in S, |x| \leq K$ for some $K \in \mathbb{R}$? Help me…
user233467
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How to relate interior points to a discrete metric space?

I am trying to grasp the concept of metric spaces, particularly, discrete metric spaces. I would like to provide an example of interior points in a discrete metric space, but am not sure what this entails. If anyone could provide an example of…
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problem regarding completeness of metric spaces

is the following true: if (X,d) is a complete metric space.let $A\subset$X .If (A,d) is also complete,then (A,$d_1$) is complete iff $d_1$ is equivalent to d or is the above claim true in only the direction that (A,$d_1$) is complete if $d_1$ is…
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Show the following: A subset $F$ of $Y$ is closed in $Y$ if and only if $F=Y\cap H$, for some closed subset $H$ of $X$

I was looking at this answer, because I need to answer the same question: Show that $F\subset Y$ is closed in $Y$ iff $F=Y\;\cap\;H$ where $H\subset X$ is closed in $X$. The second answer (given by @egreg) states: Let $x\in F$; then $x\notin…
Lorkus
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Implication of open subset in metric subspace

Let $Y \subset X$ be a subset of the metric space $(X,d)$ and let $d_y$ be the restriction to $Y \times Y$. Show the following: A subset $U \subset Y$ is open in $Y$ if and only if there exists an open subset $V \subset X$ so that $U = V \cap…
Lorkus
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