Questions tagged [modules]

For questions about modules over rings, concerning either their properties in general or regarding specific cases.

Modules are abelian groups with an added notion of multiplication by elements in a ring. They generalize abelian groups, which are modules over the integers, and vector spaces, which are modules over a field.

Rigorously, a left $R$-module is defined as an abelian group $M$ paired with a ring $R$ with a binary operation from $\cdot\;\colon R\times M\rightarrow M$ satisfying the following axioms for all $m,n\in M$ and $r,s\in R$:

  1. $r\cdot(m+n)=r\cdot m+r\cdot n$

  2. $(r+s)\cdot m=r\cdot m+s\cdot m$

  3. $(rs)\cdot m=r\cdot(s\cdot m)$

If $R$ is a unital ring, we often also require that $1\cdot m=m$.

A right module is defined similarly by rewriting the axioms with the ring elements acting on the right side.

Modules often arise in the study of commutative rings and in algebraic geometry, but may appear in any investigation of the structure of a ring as a result of the Yoneda embedding which sends a ring to the category of left modules over that ring.

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The induced map $\overline{\pi}: \operatorname{Hom}(Z_2,Z) \to\operatorname{Hom}(Z_2,Z_2)$?

Let $\pi: Z \rightarrow Z_2$ be the canonical epimorphism. The induced map $$ \overline{\pi}:\operatorname{Hom}(Z_2,Z)\to \operatorname{Hom}(Z_2,Z_2) $$ is the zero map. Since $\operatorname{Hom}(Z_2,Z_2) \neq 0 $ (since $\operatorname{Hom}(Z_2,Z_2)…
NotaChoice
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Motivation behind definition of equivalence of towers of modules

I saw the following definitions in the book 'Module Theory - An approach to linear algebra' by T.S. Blyth: Let $R$ be a unitary ring and let $M$ be an $R$ module. The author defines a tower of $R$-submodules of $M$ as a finite decreasing(strictly)…
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Module homomorphisms

Let $A$ be a $k$-algebra ($k$ is a field), and let $M$ be an (right) $A$-module. Let $L\leq M$, is it true that $\exists \phi\in\operatorname{Hom}_k(M,k)$ s.t $\phi(x)=0\iff x\in L$? If not, why (here in the answer) there is a bijection between the…
Or Shahar
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Every $C2$-module is a $C3$-module

Let $R$ be a ring. Recall that an $R$-module $M$ is said to be $C2$-module if it satisfies the following property: Whenever $A,B$ are submodules of $M$ such that $A$ is isomorphic to $B$, and $B$ is a direct summand of $M$, then $A$ is a direct…
Hussein Eid
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Invariant factors of a matrix/module

B. Hartley and T.O. Hawkes define the invariant factors of a matrix over a PID, and they also give an algorithm for computing the aforementioned factors. So far so good, but they also define the invariant factors of a finitely generated module over…
goblin GONE
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If $A$ is an associative k-algebra, where $k$ is a field of characteristic zero, then why $A\bigotimes _{k} k[[t]]\cong A[[t]]$ as a $k[[t]]$ module?

Here $k[[t]]$ is the $k$-algebra of formal power series and $A[[t]]$ is a $k[[t]]$-module of formal power series.
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Wrong Answer for $m=40$ with Shor's Algorithm

I am using Shor's Algorithm to find the prime factors for $m=40$. Here is my shot. Step $1$: Choose a random $1< a <40$. So I chose $a=9$. Step $2$: Find $r$ = order$(9,40)$. This results in $r=2$. (confirmed my answer here) Step $3$: Make sure $r$…
NimaJan
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Relation between R[X] and R[X,Y] as R-modules

In my lecture notes it was left as an exercise to show that for any $R$ $R[X,Y]\simeq R[X]$ as R-modules. To show this you need a bijective function $\phi$ such that $\phi (x+y)=\phi(x)+\phi(y)$ and $\phi(rx)=r\phi(x)$. I don't know how to do this…
Erik
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Show the given map is injective

Let $E$ be finitely generated. Then $E/E_{\text{tor}}$ is free. There exists a free submodule $F$ of $E$ such that $E$ is a direct sum $E = E_{\text{tor}}\oplus F$. The dimension of such a submodule $F$ is uniquely determined. In the proof of this…
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Does every mon-small submodule contain a nonzero supplement submodule of the module.

Definition: Let $M$ be an $R$-module. Then A submodule $N$ is called small (in $M$) if $N+K=M\implies K=M,\forall K\leq M$. A submodule $N$ is called a supplement of a submodule $K$ (in $M$) if $N$ is minimal with respect to the property $N+K=M$. A…
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Torsion of $X$ in $\frac{ \mathbb{Z}[X] }{(X^2,2X)} $ as a $\mathbb{Z}$-module

Let $M = \frac{ \mathbb{Z}[X] }{(X^2,2X)} $ et $A = \mathbb{Z} $ $M$ is an $A$-module that is finitely generated because $M$ is generated by $\overline{2}$ and $\overline{X}$. In addition, the torsion of $2$ is $\left\{ 0 \right\} $ I want to show…
Tohiea
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A question on diagram chasing

I got an exercise from my introduction to Modules class, so the image is a commutative diagram where each row forms an exact sequence and every object is an $R-$mod, the question is to prove that if $h_2$ is surjective and $h_3$ is injective then…
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$M ⊗_B U$ is fnitely generated projective as a right $A$-module

Let $A, B$ be $k$-algebras. $M$ is $A$-$B$-bimodule that is finitely generated projective as a left $A$-module and as a right $B$-module, $N, U$ are $B$-$A$-bimodules that is finitely generated projective as a left $B$-module and as a right…
scsnm
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natural isomorphism of $kG$-modules

Let $G$ be a fnite group and $H$ a subgroup of $G$. Let $U$ be a $kG$-module and $V$ a $kH$-module. There is a natural isomorphism of $kG$-modules: $U \otimes_k (Ind_H^G(V) ) \cong Ind_H^G(Res_H^G(U) \otimes_k V)$ sending $u \otimes (x\otimes v)$ to…
scsnm
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If $M,N$ are $R$-modules and $f:Μ\rightarrow N$ , $g:N\rightarrow M$ are $R$-module homomorphisms s.t. $g\circ f=1_M$ Prove: $N=Im(f)\oplus \ker(g)$

Question: If $M,N$ are $R$-modules and $f:Μ\rightarrow N$ , $g:N\rightarrow M$ are $R$-module homomorphisms s.t. $g\circ f=1_M$ Prove: $N=Im(f)\oplus \ker(g)$ My attempt: Since $\forall n\in Im(f)$ we get $g(n)=1_M\neq 0_M$ $\implies Im(f)\cap…