Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

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Polynomial identity

Let $x_0,x_1,x_2, ...,x_{99}$ be 100 distinct real numbers. Show that $$\sum_{j=0}^{99}x_j^{99}\prod_{0 \le k \le 99}^{k \neq j} \frac{x-x_k}{x_j-x_k}=x^{99}$$ I found that the left side of the equation has the form of Lagrange Interpolation with…
Bowen
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$f$ is irreducible, $f$ and $g$ share a root, then $f$ divides $g$.

I think I may be missing something obvious here. Say $f,g \in \mathbb{Q}[t]$ , and $f$ is an irreducible element of $\mathbb{Q}[t]$. If $\alpha \in \mathbb{C}$ is such that $f(\alpha) = 0$ and $g(\alpha) = 0$ is it true that $f$ divides $g$? Thanks
Wooster
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Exploring 3-cycle points for quadratic iterations

How do you factorise $z^8 +4cz^ 6 + (6c^2 +2c)z^4 + (4c^3 +4c^2 )z^2 - z+ (c^4 +2c^3 +c^2 +c)$? I want to find the 3-cycle points for the quadratic iteration $z \rightarrow z^2 + c$. In order to find it I have to solve the above polynomial. I have…
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If $(1 + 2i)$ and $(3 - 2i)$ are two roots of $x^5 + ax^4 + bx^3 + cx^2 + dx + 4$, then $a$ =?

Consider the polynomial $x^5 + ax^4 + bx^3 + cx^2 + dx + 4$ where $a, b, c, d$ are real numbers. If $(1 + 2i)$ and $(3 - 2i)$ are two roots of this polynomial then what is the value of a? Well, I know only the 4 roots, which are obvious from what…
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Comparing real roots of $P(x)$ and $P'(x)$

Let $a$ be a real number and $P(x)$ be a polynomial with real coefficients. 1) Prove that $P'(x)$ doesn't have more non real roots than $P(x).$ 2) $aP(x)+P'(x)$ doesn't have more non real zeroes than the polynomial $P(x)$ itself. I tried it like…
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Find the roots of the following polynomial equation..

how would you solve this exercise: Find the solutions of the following equation knowing that one of these solutions belongs to $R$: $$x^3+(3i-2)x^2-(1+4i)x+2+i=0$$ I used the condition set in the problem and got four values of that real solution,…
wonderingdev
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finding the equation of a polynomial given its graph

I have a graph of polynomial and I would like to know how to determine its equation. Please, this isn't homework. What I'd like to do is actually reproduce this graph. Thanks.
Jay
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Find the value of $k$ such that $p(x)= kx^3 + 4x^2 + 3x - 4$ and $q(x)= x^3 - 4x + k$ , leave the same remainder when divided by $(x – 3)$.

$p(x)= kx^3 + 4x^2 + 3x - 4$ and $q(x)= x^3 - 4x + k$ , leave the same remainder when divided by $(x – 3)$. (a) -1 (b) 1 (c) 2 (d) -2 I am getting the value of k: $-17/29$ after equating the remainders. $p(x)= kx^3 + 4x^2 + 3x - 4/(x – 3)$:…
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Roots for quintic equations

I have been pondering over this question for a few months now. Why exactly do quintic equations have no closed general expression for their roots? Looking at graphs and reading about it hasn't really convinced me.…
Artemisia
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Using the discriminant find the real solutions?

I have an equation: $$x^4+ax^3−b^2$$ for which the discriminant is $$−b^4(256b^2+27a^4)$$ If $$b≠0$$ what are the 2 real solutions to the equation? For these two solutions, what is a=?
John
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Factorising $X^n+...+X+1$ in $\mathbb{R}$

How can factorize this polynom in $\mathbb{R}$: $X^n+...+X+1$ I already try to factorize it in $\mathbb{C}$ but I couldn't find a way to turn to $\mathbb{R}$
pourjour
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How to know whether a polynomial has factors?

It's clear that $a^2 - b^2$ has, and that $a^2 + b^2$ doesn't have. But when a polynomial gets longer and longer, do you have any sort of rule, like you have with natural numbers (when they end in $2$ are even, in $5$ are divisible by $5$, and so…
Quora Feans
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Polynomial Problem, $P(x+1)P(x-1)=P(x^2+1)$

$P(x)$ is a real polynomial such that $P(x+1)P(x-1)=P(x^2+1)$. Find $P(x)$. I have no idea how to start on this problem. The only things I could do was finding things like $P(2)P(0)=P(2)$ or differentiating $P(x+1)P(x-1)=P(x^2+1)$ and substituting…
user127151
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Two relatively prime polynomials

show that two polynomials f,g in K[x] are relatively prime if and only if 1 is in I(f,g). I(f,g) being the linear combinations of the two polynomials. I dont know how to start this since shouldnt 1 have to be in there in order for them to be…
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A question about polynomials.

My book says If a rational number $m/n$, for $(m,n)=1$, is a root of the polynomial $a_rx^r+a_{r-1}x^{r-1}+\dots+a_0$, where $a_0,a_1,\dots,a_r\in\Bbb{Z}$, then $n|a_r$ and $m|a_0$. I was under the impression that such a polynomial with integer…