Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

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Polynomial equation, cannot solve for $x$

$$3x^2-4x-4+x^3=x^3+2x+2$$ This boils down to (I think): $$3x^2 - 6x - 6 = 0$$ I'm trying to solve for $x$ using the polynomial equation: $$\begin{align} x &= \frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ a &= 3 \\[0.2ex] b &= -6 \\ c &= -6 \end{align}$$ My…
Doug Fir
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non-positive roots of a polynomial

Consider the even polynomial $$ \Phi(z)=a_6z^6+a_4z^4+a_2z^2+a_0=0\;, $$ where $a_i\in\mathbb{R}$. Given that $a_0<0$ and $a_6>0$, does there exist conditions to guarantee that $\Phi$ has no positive real roots? This seems impossible, but maybe I'm…
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division of polynomials of same degree

I am solving a differential equation which requires solving and integrating $(4y^3 + 10y^2 + 5y + 2) / (2y^3 + 3y^2 + 3y + 1)$. I am thinking synthetic division to reduce it but am not sure where to start as both polynomials are of the same degree.
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Consider a sequence of polynomials with real coefficients defined by

Consider a sequence of polynomials with real coefficients defined by: $$p_0=(x^2 +1)(x^2 +2).....(x^2 +1009)$$ with subsequent polynomials defined by $$p_{k+1} (x) :=p_k (x+1) - p_k (x) $$ for $x>0$. Find the least n such that $$p_n (1)=p_n…
jayant98
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Problem about real coefficient polynomial

Let $p(x)$ be a real coefficient polynomial. Assume that there exits $a\in \mathbb{R}$ s.t. $p(a)\neq 0$ but $p'(a) = p''(a) = 0$. Show that $p(x)$ has at least one non-real root. This is a problem from today's exam, and actually, I already have…
Seewoo Lee
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How can I show that these two polynomials are coprime?

Let $n , m \in \mathbb{N}$ and let $k = \gcd(n , m)$. Then there exist $p , q \in \mathbb{N}$ coprime such that $n = p k$ and $m = q k$. And it is easy to see that $$ \frac{X^n - 1}{X^k - 1} = \sum_{i = 0}^{p - 1} X^{k i} = f(X) \qquad \mbox{ and }…
joseabp91
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Is this True? Question about polynomials degree and their product

Is it true that every polynomial of degree 4 and real coefficients can be expressed as the product of two polynomials of degree two and of real coefficients? In case of an affirmatively answer prove it and in case of answering negatively give a…
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Find the quotient and remainder

Find the quotient and remainder when $x^6+x^3+1$ is divided by $x+1$ Let $f(x)=x^6+x^3+1$ Now $f(x)=(x+1).q(x) +R $ where r is remainder Now putting $x=-1$ we get $R=f(-1)$ i.e $R=1-1+1=1$ Now $q(x)=(x^6+x^3)/(x+1)$ But what I want to know if…
John757
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Defining a polynomial that always has one $x$-value for a given $y$-value

Introduction This question is heavily connected with the related programming aspect around it (link), while the question might be better suited for this stack. However, if it is not suited for this stack just let me know and I will remove…
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Find all polynomials $P(x)$ with the property that $P(x)$ is a multiple of $P''(x).$

Find all polynomials $P(x)$ with the property that $P(x)$ is a multiple of $P''(x).$ So we have that $$P(x) = Q(x) P''(x).$$ Now I know that if $(x-\alpha)^r$ is a root of $P(x)$ then it is also a root $P''(x)$ is $r\geq 2.$ But I don't understand…
Student
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Deciding whether a given polynomial is globally positive

In general, is there any efficient approach to determine if a polynomial over $\mathbb{R}$ is positive? The only constraint here is that the polynomial can only have a maximum of 5 or 10 variables. If so, there is an available tool to use, maybe…
XRow
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Division of $f(x):= x^6+x^4+x^3-x^2-1$ by $g(x):=x^4+x^3-1$ seems not so correct

Let's say $f(x):= x^6+x^4+x^3-x^2-1$ and $g(x):=x^4+x^3-1$. Given that degree $(f(x))$ $>$ degree $(g(x))$, we can divide $f$ by $g$. The issue here is, continuous division of polynomial (starting from the higher powers) we have learnt in junior…
Mathejunior
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System of inequalities in multivariate polynomials

Suppose there are $k$ non-zero homogeneous polynomials $P^1(.),\cdots, P^k(.)$, each of degree $r$ in $n$ variables, such that $P^j(x_1,\cdots,x_n) \geq 0$ for all $(x_1,\cdots,x_n) \geq 0$, for all $j \in [k]$. Under what conditions (on the…
Canine360
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Equivalent conditions for a polynomial to be divisible by $(x-1)^{k+1}$

I could prove the following assertions: Let P be a polynomial of degree n in $\Bbb R$[X]: a) P is divisible by $(x-1)^{k+1}$ is equivalent to P' divisible by $(x-1)^k$ and P(1) = 0. b) Let P(1) = 0. P is divisible by $(x-1)^{k+1}$ is equivalent to…
Matfi
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Help in getting the Quadratic Equation

I'm starting a chapter on Functions and they had the steps shown to reach the p-q equation. $$ x_{1,2} = -\frac{p}{2} \pm\sqrt{\left(\frac{p}{2}\right)^2 - q}$$ So I wanted to do the same with the Quadratic Equation. I'm using the base linear…
IAE
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