Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

26755 questions
2
votes
2 answers

Dividing polynomials such that we get the desired remainder?

Find $a,b,c$ such that the remainder of $$\frac{a(x^{11}-x^4+1)^{15}-x^2+bx-c}{x^3+x}$$ is equal to $x^2-4x+1$. I can solve it by writing $$a(x^{11}-x^4+1)^{15}-x^2+bx-c=(x^3+x)q(x)+x^2-4x+1$$ And solve the system of linear equations by…
Eod J.
  • 515
2
votes
2 answers

Polyomial function over ring GF(3)

$x^5 +2x^2 +1$ is a polynomial over ring $GF(3)$ and let $P(x)$ be its polynomial function ... Is there any other polynomial over the same ring that corresponds to the same polynomial function? I've read in the book that it exists, but I do not…
2
votes
3 answers

$z$ is a root of $F$ iff $\bar z$ is root of $F$

$F(x) \in R$ and $z \in C$. I need to prove that z is a root of $F$ iff $\bar z$ is root of $F$ I can't think of a way to prove that... will love some guidance.
baaa12
  • 754
2
votes
2 answers

Is this an irreducible polynomial?

I have this polynomial: $x^8+x^4+x^3+x+1$ and I would like to know if it is irreducible over $\mathbb{F}_q$ with $q=2^8$. My book gives me it is irreducible but matlab says it is not irreducible.
Mazzy
  • 281
2
votes
3 answers

Factorization of polynomial

I was just asked to factor $x^3+1$. I came to $(x^2-x+1)(x+1)$ after a while, and I was wondering, whether there is a good method to quicky factor such of polynomials.
user50222
  • 978
2
votes
1 answer

Finding real zeros of polynomial of third degree to solve inequality

\begin{align}{} & \dfrac{x^3+2 x^2}{2} < x+2 \\[18pt] & x^3 + 2x^2 < 2x+4 \\ & x^3 + 2x^2 -2x - 4 < 0 \\ \end{align} Let $p(x) = x^3 + 2x^2 -2x - 4$. Setting $p(x) = 0$ Cauchy's bound tells me the real zeros should be in the range of $[-5,…
2
votes
1 answer

$(x-a)^k|f'(x)$ implies $(x-a)|f(x)$ when all complex roots of polynomial $f(x)$ are real and where $k \geq 2$

suppose all complex roots of polynomial $f(x)$ are real. then $$(x-a)^k|f'(x)\Rightarrow (x-a)|f(x)$$where $k\geq2$
Laura
  • 4,689
2
votes
1 answer

Does $x_1^3+x_2^3+\dots+x_n^3+x_1+x_2+\dots+x_n=0$ imply $x_1+x_2+\dots+x_n=0$?

If $x_1,x_2,\dots,x_n \in \mathbb{R}$ can we claim that: $$x_1^3+x_2^3+\dots+x_n^3+x_1+x_2+\dots+x_n=0$$ implies $$x_1+x_2+\dots+x_n=0$$ ?
Laura
  • 4,689
2
votes
2 answers

$c>0$ and $3ax^2+4bx+c =0$ has no real roots, then?

If $c>0$ and the equation $3ax^2+4bx+c =0$ has no real roots, then: A)$ 2a+c>b $ B )$a+2c>b$ C) $3a+c>4b$ D)$a+3c
user373141
  • 2,503
2
votes
3 answers

Find new polynomial coefficients using Vieta's formulas

$p(x)=x^3+ax^2+bx+c$ has roots $x_1,x_2,x_3$. Find $a,b,c$ for $q(x)$ which has roots at $x_1+x_2$, $x_1+x_3$ and $x_2+x_3$. I know that I'm supposed to use Vieta's formulas where $$x_1+x_2+x_3=-a$$ $$x_1x_2+x_1x_3+x_2x_3=b$$ $$x_1x_2x_3=-c$$ but…
Oscar3
  • 73
  • 5
2
votes
3 answers

If a is a non real root of $x^7 = 1$, find the equation whose roots are $ a + a^6 , a^2 + a^5, a^3 + a^4$

If a is a non real root of $ x^7 = 1$, find the equation whose roots are $a + a^6 , a^2 + a^5, a^3 + a^4$. This is one of the questions I have encountered while preparing for pre rmo. I feel the question requires the concept of the nth roots of…
saisanjeev
  • 2,050
2
votes
2 answers

Polynomials factor Theorem

If a cubic polynomial $p(x)$ with leading co-efficient 1 is divided by $x-1$, $x-2$ and $x-3$ respectively it leaves $r(x)$ $1$, $4$ and $9$. What will be the remainder when it is divided by $x-4$? I've searched for this everywhere but I couldn't…
2
votes
1 answer

Polynomial remainder problem.

A polynomial $f(x)$ is such that upon division by $(x-3)$ it leaves a remainder of $15$ and upon division by $(x-1)^2$, it leaves a remainder of $2x+1$. What is the remainder when $f(x)$ is divided by $(x-3)(x-1)^2$?
2
votes
2 answers

Find all polynomials $Q(x)(x^2-6x+8) =Q(x-2)(x^2-6x)$ for $x\in \Bbb R$

Find all polynomials $Q(x)(x^2-6x+8) =Q(x-2)(x^2-6x)$ for $x\in \Bbb R$ I've tried different substitutions like put $Q(x)$ $=$ $k$ for some $k$ and getting the equation $k(x^2-6x+8)$ $=$ $(k-2)(x^2-6x)$ $<=>$ $k$=$(6x-x^2)/4$, but that doesn't…
2
votes
1 answer

Solving a 7th degree polynomial using De Moivre's theorem

Use De Moivre Theorem to show that $$\cos 7θ=64\cos^7θ-112\cos^5θ+56\cos^3θ-7\cosθ$$ *Done Hence obtain the roots of the equation $$128x^7-224x^5+112x^3-14x+1=0$$ in the form $\cos q\pi$ Attempt $$\cos7θ=-1/2$$ $$θ=2π/21,…
mathnoob123
  • 1,373