Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

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$P(x) = x^4 + ax^3 +bx^2 +cx+d$

Let $P(x) = x^4 + ax^3 +bx^2 +cx+d$ where $a, b, c, d$ are integers. $P(x)$ is divided by $x-2012, x-2013, x-2014, x-2015, x-2016$ and has the remainders $24, -6, 4, -6, 24$ respectively. What is the remainder when $P(x)$ is divided by $x-2017$…
user403160
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How can I solve the equation $x^3-x-1 = 0$?

Can someone give me a hint on how can I solve the equation $$x^3 - x - 1 =0?$$ Thank you!
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Generator polynomial

I need to compute a generator polynomial for a binary cyclic code of length 12 and dimension 5. I know that factorization of $(x^{12}+1)$ over $GF(2)$ is $(x+1)^4(x^2+x+1)^4$. What will be next step? Thanks for any advice.
James
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Polynomial reversal

For a polynomial $a = {a_0} + {a_1}x + \ldots + {a_{n - 1}}{x^{n - 1}} + {a_n}{x^n} \in R[x]$ of degree at most $n \in {\mathbb{Z}_{ \geqslant 0}}$ over a ring $R$, let the $n$-reversal of $a$ be the polynomial ${\text{re}}{{\text{v}}_n}a = {a_n}…
user1812
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What number should be subtracted from

What number should be subtracted from $4x^3+5x+3$ so that the resulting polynomial leaves remainder $-80$ when divided by $2x+5$?. Let the required number to be subtracted be $K$. let: $$P(x)=4x^3+5x+3-k$$ $$g(x)=2x+5=2(x+5/2)$$ Comparing $g(x)$…
Aryabhatta
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Without using actual division method, find the quotient

without using actual division method, find the quotient and remainder when $x^6-2x^4+x^2+5$ is divided by $x^2-2$. Using Remainder Theorem I got the remainder as $7$ but how do I get the quotient..
Aryabhatta
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Factorize polynomial

I am trying to factorize $-6x^5+15x^4-30x^2+30x-13$ for hours:( Could someone help me? I tried making a system of equations from $(Ax^3 + Bx^2 + Cx + D) (Ex^2 + Fx + G)$ but it is a nightmare:( In case you are interested, the system is: $AE =…
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Find all Polynomials P(x) with real coefficients

Find all Polynomials P(x) with real coefficients so that $2P(2x) = P(3x) + P(x)$. I tried to substitute first degree, second and third, bit couldn't get an equality. Thank you for your responses!
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Coefficients of the product of two special polynomials

Let $A_n(z)=1+az+a^2z^2+\dots+a^nz^n$ and $B_n(z)=1+bz+b^2z^2+\dots+b^nz^n$, where $a,b \in \mathbb Z$. And let $C_{n,n}(z)=A_n(z)\cdot B_n(z)=1+c_1z+c_2z^2+\dots+c_{2n}z^{2n}$. Is it possible that $c_k=c^{k+1}$ for some $c \in \mathbb Z$ and some…
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Proving that a polynomial is an even function given limited information

The polynomial $f(x)$ has degree $10$. We know also that $f(a)=f(-a)$ for $a\in \{1,2,3,4,5\}$. Prove that $f(r)=f(-r)$ for all $r\in \mathbb R$ (i.e. that the polynomial is even) Note: this is a radical edit which I hope captures the sense of the…
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What are the benefits of converting a polynomial to a symmetric multiaffine function (blossom/polar form)?

In an answer to the question Modifying and Generalizing the De Casteljau Algorithm, I found out that you can convert a polynomial into a polar form, aka make it into a symmetric multiaffine function. For example, if $f(t)=(1−t)^3$, then…
Alan Wolfe
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Show that the algebraic curve $x^{\frac{2}{3}}+y^{\frac{2}{3}}=1$ can be given by a polynomial of degree $6$?

I imagine that this should be done in the following way: There is a polynomial $P$ such that: $$P(x^{\frac{2}{3}}+y^{\frac{2}{3}})=P$$ My first guess (obvious observation?) is that it can't be a polynomial in one variable, otherwise one of the…
Red Banana
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Does an equality in $K(t_1,...,t_m)[x_1,...,x_n]$ hold under $(t_1,...,t_m)\to(a_1,...,a_m)\in K^m$?

Let $K(t_1,...,t_m)[x_1,...,x_n]$ denote a polynomial ring where $K(t_1,...,t_m)$ is a field of rational functions. Given an equality $f=\sum_{i=1}^sA_jg_j$ in $K(t_1,...,t_m)[x_1,...,x_n]$ and let $a=(a_1,...,a_m)\in K^m$ such that no denominators…
KarlEL
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Is this composition of polynomial correct?

Suppose $p(x)=x^2+5x+3$ and $q(x)=3x^3-3x+7$. Write the expression $(q \circ p)(x)$ as a sum of terms, each which is a constant times the power of $x$. Here is my work for the problem: $(q\circ p)(x)=3(x^2+5x+3)^3-3(x^2+5x+3)+7$ $(q\circ…
Kot
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Polynomial integer division

I have a polynomial $p$ with integer coefficients, which might have roots of multiplicity higher than one. I would like to obtain each root just once so I calculate $g = \gcd(p, p')$ and divide $q = p/g$. I know $g$ has integer coefficients, too, so…