Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

26755 questions
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Finding a polynomial $F$ such that $F(P,Q) = 0$, where $P$ and $Q$ are polynomials.

I am a bit struggling with this at the moment : Let $K$ be a field and let $P, Q \in K[X]$. Is there always a (minimal?) polynomial $F \in K[Y,Z]$ such that $F(P,Q) = 0$? And if/when the answer is positive, how to find such a polynomial? For…
Lochran
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seeking sufficient conditions for polynomials to have no positive roots

I encountered several polynomials as below: $$f(x)=7 + 91 x - 385 x^2 + 1659 x^3 - 1379 x^4 + 553 x^5 - 35 x^6 + x^7$$ $$g(x)=33 + 110 x + 495 x^2 - 252 x^3 + 335 x^4 - 18 x^5 + x^6$$ $$h(x)=71 + 237 x + 126 x^2 + 210 x^3 - 5 x^4 + x^5$$ When I…
mike
  • 5,604
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How to solve $(z^1+z^2+z^3+z^4)^3$ using Pascals Triangle?

In an exercise it seems I must use Pascal's triangle to solve this $(z^1+z^2+z^3+z^4)^3$. The result would be $z^3 + 3z^4 + 6z^5 + 10z^ 6 + 12z^ 7 + 12z^ 8 + 10z^ 9 + 6z^ {10} + 3z^ {11} + z^{12}$. But how do I use the triangle to get to that…
user251701
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Find parameter m if equation admits three distinct real solutions

$2x^3+3x^2-x+5-m=0$ I know for the above equation there is the following condition for the case when all the three roots must be distinct and real: $D = -4b^3d + b^2c^2 - 4 ac^3 + 18abcd - 27a^2d^2 > 0 $ So, we calculate $D$ and then we find out…
Florin M.
  • 635
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Find all $a \in\Bbb C$ such that $F(X)$ has a multiple root

Let $$ F(X)=X^6+aX^3+1 $$ Find all $a \in\Bbb C$ such that $F(X)$ has a multiple root. I had this exercise in an exam, and I know I got the wrong answer but I don't know why my method didn't work. What I think I should've…
YoTengoUnLCD
  • 13,384
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Finding a polynomial by divisibility

Let $f(x)$ be a polynomial with integer coefficients. If $f(x)$ is divisible by $x^2+1$ and $f(x)+1$ by $x^3+x^2+1$, what is $f(x)$? My guess is that the only answer is $f(x)=-x^4-x^3-x-1$, but how can I prove it?
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Polynomial division simple

I am trying to divide polynomials but i am ending up with different outcomes. Let's assume i have : $\dfrac{s^4+3s^3+4s^2+4s+1}{2s^3+2s^2+3s+1}$ Can anyone solve this step by step (long or synthetic division doesn't really matter, but i would prefer…
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Finding value of a quadratic

The polynomial \begin{equation*} p(x)= ax^2+bx+c \end{equation*} has $1+\sqrt{3}$ as one of it's roots and also $p(2)=-2$. Is there any way to know the value of $a$, $b$ and $c$? I tried but I can form only $2$ equations how can I figure out value…
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Division by zero factoring problem

Given the fact that the function: $$f(x) = \dfrac{2x-4}{x-2} = \dfrac{2(x-2)}{x-2} = f(x) = 2$$ Shouldn't $f(x)$ be equal to $2$ in every case, even when $x=2$?
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Number of roots of a polynomial of non-integer degree

How many roots does a polynomial-like function of degree $n$ have if $n$ is a rational or an irrational number?
Pranab
  • 31
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Critical Values of multivariate polynomials are closed.

Consider a multivariate polynomial map $F:\mathbb{R}^n \rightarrow \mathbb{R}^n.$ Is it always true that the set $C$ in $\mathbb{R}^n$ of critical values is closed? More specifically, the Sard's theorem tell us that measure of critical values is…
Suresh
  • 373
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Working out a polynomial from it's solutions when set equal to zero

If I have a polynomial of degree $n$ with leading coefficient $1$, that when set equal to zero has as its only solution $x=0$, how do I prove that this polynomial can only be $x^n$?
Snickett
  • 273
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Fitting a polynomial with arbitrary derivative values

Given two points $(x_1, y_1)$ and $(x_2, y_2)$ with $x_2 > x_1$ and $y_2 < y_1$, I can obviously fit a line (order $1$ polynomial) to them. But if I want to fit a quadratic function by specifying real, finite values of the derivatives at the two…
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About a polynomial with complex coefficients taking integer values for sufficiently large integers

Let $f(x)$ be a polynomial with complex coefficients such that $\exists n_0 \in \mathbb Z^+$ such that $f(n) \in \mathbb Z , \forall n \ge n_0$, then is it true that $f(n) \in \mathbb Z , \forall n \in \mathbb Z$ ?
user228168
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Two Polynomials and Them subtracted by 1 Has Same Roots

For any complex polynomial $P(X)$ we denote by $Z_0(P)$ the set of zeroes of $P$ and by $Z_1(P)$ the set of zeroes of $P(X)-1$. Prove that if $Z_0(P)=Z_0(Q)$ and $Z_1(P)=Z_1(Q)$ then $P=Q$. Assume that P(X) and Q(X) are nonconstant. I am trying to…
user198454