Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

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Taylor polynomial help

About Taylor polynomials: I have $$f(x)=(x-4)^9$$ And I need to find the 10th order taylor polynomial about $x=4$ Now, I tried solving it: All but the last term is equal to $0$ since for example $$f''(a)\frac{(x-a)^2}{2!}= (4-4)\frac{x-4}2=0$$ So…
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Justify $\gcd$ of $f(x) = x^3 - 6x^2 + x + 4$ and $g(x) = x^5 - 6x +1$

Let $f(x) = x^3 - 6x^2 + x + 4$ and $g(x) = x^5 - 6x +1$. Using Euclidean algorithm I find $\gcd[f(x), g(x)] = 1$. How could I JUSTIFY that $h(x) = 1$ is the ACTUAL $\gcd$ of $f(x)$ and $g(x)$? Thanks.
Natalie
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Polynomials that DON'T have certain roots

How many degree $\leq$ $d$ mod($p$) polynomials are there such that $P(a_1),...,P(a_k) \neq 0$ for $k < d$ and $0 < a_1 <...< a_k < p$, all integers? I considered subtracting out elements from the the set of all polynomials of degree less than or…
user82004
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Finding polynomial $f(x)$ from $f(1)$ and $f(f(1))$

Let $f(x)=a_0+a_1x+a_2x^2+\dots+a_nx^n$, where $a_i\ge0$ Given $f(1)=p$ and $f(f(1))=q$, we have to find $a_0$, $a_1$, $a_2$, $a_3$, $\dots$, $a_n$, where such $f(x)$ exists. Or we have to confirm if such $f(x)$ exists or if the polynomial is…
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Multivariate polynomial with univariate factor

Suppose $f \in \mathbb{Q}[x_1,x_2,\dotsc,x_i]$. How do I prove the following: There exists $x_1 \in \mathbb{C}$ such that for all $x_2,\dotsc,x_i \in \mathbb{C}$, $$f(x_1,x_2,\dots,x_i) = 0$$ if and only if $f$ is divisible by some $g \in…
user98041
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Smart way to check a root

Let $\alpha$ be a root of $x^3+3x+5$. Let $\omega:=\frac{1+\alpha+\alpha^2}{3}$. Verify that $\omega$ is a root of $y^3+y^2+2y-1$. Is there some trick to do this computation quickly?
bateman
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$\frac{p^3}{27}<-\frac{q^2}{4}$ implies $x^3+px+q$ has 3 distinct real roots

This is my first homework in Galois Theory, and my professor seems to be going for a style that is pretty concrete; for example on the first day he derived Cardano's Formula for cubics, he spent a couple hours justifying Viete's Formula, and he only…
Eric Stucky
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Having a irreducible polynomial factor?

I have a problem which could not be solve by using Eisenstein's criterion. Let $f(x)=\sum_{i=0}^n a_i x^i(a_n\neq 0, n\geq 2010)$. Suppose there exists a prime $p$ such that (1) $p\nmid a_n$; (2) $p\mid a_i, i=0,1,\cdots,2008$; (3) $p^2\nmid…
XLDD
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Finding value of $(a+b)^5$ using $2$ cubic equation in $a$ and $b$

If $a,b\in\mathbb{R}$ and $\displaystyle \frac{a^3+4a}{3a^2+5}=-1.$ and $\displaystyle \frac{b^3+4b}{3b^2+5}=1$. Then $(a+b)^5=$ What I try : From the above data, we have $\displaystyle a^3+3a^2+4a+5=0\cdots (1)$ $\displaystyle…
jacky
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How to solve the equation $3a^4=8a^3-16$?

How to solve the equation $3a^4=8a^3-16$?, where a is a positive number I have tried using the quadric formula, but got to nothing useful. I know the solution is $2$, but I don't know how to solve it. This is a part of a problem and I need it to…
IONELA BUCIU
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Non-graph way to reason about a polynomial question

Question $P(x)$ is a fourth-degree polynomial with real coefficients. Given that, $$ \forall x \in \mathbb{R}, P(x) \ge x $$ and that, $$ P(1)=1, P(2)=4, P(3)=3 $$ What is $P(4)$? Answer There is a beautiful solution with the help of the…
blackened
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Need help understanding a proof of the remainder theorem

Proof. $p(x) = (x-a)q(x) + r(x)$ Rearranging, $r(x) = p(x) - (x-a)q(x)$ Plug $x=a$, $r(a) = p(a) - (a-a)q(x)$ $r(a) = p(a)$ To me this seems like it only proves that $r(a) = p(a)$ for the specific instance where $x=a$. The textbook that I am using…
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Proof of Buchberger's criterion in Dummit & Foote, 3rd edition.

I am stuck on the part in the proof, where they say that $S(h_{i-1}'g_{i-1},h_{i}'g_{i})$ is just $S(g_{i-1},g_{i})$ multiplied by the monomial of multidegree $\alpha - \beta_{i-1,i}$. One finds that…
Ben123
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How does root cause analysis work for polinomial equations?

Imagine you have a function $$f(A,B) =A \cdot B$$ where $A=g(t)$ and $B=h(t)$ and $g$ and $h$ are unknown. You measure $f(A,B)$ at $t_0$ and $t_1$ and you see a difference (either positive or negative). This implies there was a variation in $A$…
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elementary symmetric polynomial non-zero newton identities

I've been reading up on Newton's Identities on wikipedia (https://en.wikipedia.org/wiki/Newton's_identities) where the section 'Mathematical Statement' first defines $p_k(x_1,\ldots,x_n)=\sum_{i=1}^n x_i^k = x_1^k+\cdots+x_n^k$ and the elementary…