Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

26755 questions
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$p(x,y)\in\mathbb{R}[x,y]$ and $\forall x,y\in\mathbb{R}$ we have $p(x-1,y-2x+1)=p(x,y)$. prove $\exists f\in\mathbb{R}[x]$ so that $p(x,y)=f(y-x^2)$

hint only $p(x,y)\in\mathbb{R}[x,y]$ and $\forall$ $x,y\in\mathbb{R}$ we have $p(x-1,y-2x+1)=p(x,y)$. prove $\exists$ $f\in\mathbb{R}[x]$ so that $p(x,y)=f(y-x^2)$ my attempt : if $p(x,y)=f(y-x^2)$ then $p(x,x^2)=f(0)=c$ (this should be…
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Cyclic polynomial proof 2.

So here's my second question for the day, Q. Manipulate the given equality $$a^2b^2(bc-a^2)+b^2c^2(ca-b^2)+c^2a^2(ab-c^2)$$$$ = a^2b^2(b^2-ac)+b^2c^2(c^2-ab)+c^2a^2(a^2-bc)$$ to obtain the…
Ghost
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Not able to understand the solution given about solving an equation

Let $a>2$ be a real number. Solve the equation $$ x^3-2 a x^2+\left(a^2+1\right) x+2-2 a=0 $$ The solution given in the book goes like this: The trick is to view this as an equation in $a$. The discriminant is $\Delta=4(x-1)^2$, and we…
Ellie_Wong
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Find the polynomial: $x P(x-1)=(x+1)P(x)$

Find all polynomials $P(x) \in \mathbb R\left[x\right]$, satisfying: $$xP(x-1) = (x+1)P(x)$$ I tried, but I am getting something like this: $$P(x)=\ldots(x-3)(x-2)(x-1)(x)(x+1)(x+2)(x+3)\ldots$$ (My teacher gave me this math question and I need help…
ady
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About writing an expanded formula for a simple polynomial expression

Let $\boldsymbol{x} = \left(x_1, x_2, \dots x_{D}\right)^{T}$ and consider the expression $$P\left(\boldsymbol{x}\right) = \prod_{k=1}^{D}\left(x_k + \alpha\right)$$ where $\alpha$ is a fixed given real number. We see that for $D =…
Atmos
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Prove that $ \prod_{k=1}^6\left(x_k^2+1\right)=(2 a-c)^2 $

Consider the polynomial with real coefficients $P(x)=x^6+a x^5+b x^4+c x^3+b x^2+a x+1$, and let $x_1, x_2, \ldots, x_6$ be its zeros. Prove that $$ \prod_{k=1}^6\left(x_k^2+1\right)=(2 a-c)^2 $$ By vieta, we know that $$-a=\sum_{cyc} x_1$$ and…
Ellie_Wong
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Graph being a parabola

Determine the polynomial $P\in \mathbb{R}[x]$ for which there exists $n\in \mathbb{Z}_{>0}$ such that for all $x\in \mathbb{Q}$ we have: $$P\left(x+\frac1n\right)+P\left(x-\frac1n\right)=2P(x)$$ The solution given in the book says: If there is…
Ellie_Wong
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Finding possible values of $|a| + |b| + |c|$ for solutions of $x^3 - 2019x + m = 0$

There is an integer $m$ in the polynomial $x^3 - 2019x + m = 0$ so that the polynomial has three solutions namely $a$, $b$, and $c$, where $a$ and $b$ are positive integers and $c$ is an integer only (can be positive, negative or 0). Determine the…
ishakfm
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prove: $\left(\frac{f(x)}{(f(x),g(x))},\frac{g(x)}{(f(x),g(x))}\right)=1$

$f(x)$ and $g(x)$ are not all zeros. Prove: $$\begin{align*}\left(\frac{f(x)}{(f(x),g(x))},\frac{g(x)}{(f(x),g(x))}\right)=1\end{align*}$$ prove: we have $u(x)f(x)+v(x)g(x)=(f(x),g(x))$, and then divides $(f(x),g(x))$ in both sides,…
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Remainder , product of two factors

Polynomial function $P(x)$ satisfies that $P(x) = (x+1)^3 Q_1 (x) + 2x^2 +1$ $P(x) = (x-1)^3 Q_2 (x) + 24x^2 -32x +19$ $P(1) = 11, P(-1)=3$ $P(x) = (x+1)^3 (x-1)^3 Q_3 (x) + R(x) $ Find $R(x)$ . I thought of comparing the next two…
Snupi
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Need help finding mistakes in my proof about Dickson polynomials

I've been working on a proof involving Dickson polynomials, and I'm having trouble finding any mistakes and completing this proof. We have the equality \begin{equation} D_n(x, a)=\sum_{i=0}^{\lfloor \frac{n}{2}\rfloor}d_{n,i}x^{n-2i} \ \text{,…
pawelK
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Consider the identity $(1+x)(10+x)\left(10^{2}+x\right) \cdots\left(10^{10}+x\right)=10^{a}+10^{b} x+a_{2} x^{2}+\cdots+a_{11} x^{11}.$ Comment on $a$

Consider the identity $(1+x)(10+x)\left(10^{2}+x\right) \cdots\left(10^{10}+x\right)=10^{a}+10^{b} x+a_{2} x^{2}+\cdots+a_{11} x^{11}.$ We denote the largest integer lesser than ot equal to $z$ as $[x].$ What can you say about $a,b,[a],[b].$…
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Prove: If a monic quartic with rational coefficients has one real root, then the root is rational

The polynomial $p(x)=x^4+a x^3+b x^2+c x+d$ has exactly one real number $r$ such that $p(r)=0$. Show that if $a, b, c, d$ are rational, $r$ is also rational. As it's a 4 degree polynomial with only one real root $r$, we know it's a double root.…
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Does an invariant polynomial imply $f(X\hspace{1mm} Y)=f(YX)$?

Let $f:\mathfrak{gl}(n;\mathbb{R})\to \mathbb{R}$ be a polynomial (here, $\mathfrak{gl}(n;\mathbb{R})$ is the lie algebra of $GL(n;\mathbb{R})$ and hence is simply the set of $n\times n$ real matrices). $f$ is said to be invariant if…
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Solve factored polynomial equal to nonzero constant

I have a polynomial $P(x)$ that is already factored: $P(x) = (x+a_1)(x+a_2)...$. Is there a way to solve $P(x)=c$ where $c \neq 0$ ? Here the $a_i$ are all real. I'm guessing there isn't a general solution, but I'm hoping for a surprise.