Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

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Calculate the number of real numbers $k$ such that $f(k) = 2$ if $f(x) = x^4 − 3x^3 − 9x^2 + 4$.

Calculate the number of real numbers $k$ such that $f(k) = 2$ if $f(x) = x^4 − 3x^3 − 9x^2 + 4$. How do I calculate the number of values for $k$? I can't seem to understand. Please help me solve this problem.
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How can we determine the sign of a polynomial

Given a polynomial along with the information that it has no real roots, then how can we say then whether it is greater or less than zero?
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Error in Polynomial Factoring

From Ramanujan's Notebooks IV: Let $\alpha,\beta$ and $\gamma$ be the roots of$$x^3-ax^2+bx-1=0\tag1$$Now, choose cube roots such that $(\alpha\beta\gamma)^{1/3}=1$ and then let$$z^3-\theta z^2+\varphi z-1=0\tag2$$Denote the cubic polynomial with…
Crescendo
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How to find the least degree of the polynomial satisfying the given conditions?

let $p(x) = a_0 + a_1x + ....+a_nx^n. If\; p(-2) = -15, \ p(1) = 9, \ p(-1) = 1,\ p(0) = 7, \ p(2) = 13\; and\; p(3) = 25$ then the smallest possible value of $n$. what I tried is that $p(0) = 7\,, a_0 = 7$, $p(1) = a_0 + a_1 + a_2 +.....+a_n =…
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If $4x^{10}-x^9-3x^8+5x^7+kx^6+2x^5-x^3+kx^2+5x-5 $ when divided by $(x+1)$ gives a remainder of -14, then the value of k equals?

If $4x^{10}-x^9-3x^8+5x^7+kx^6+2x^5-x^3+kx^2+5x-5 $ when divided by $(x+1)$ gives a remainder of -14, then the value of k equals? I got this and similar type of question in a book and I don't really know how to exactly solve it. Any help will be…
Iti Shree
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Finding roots of this polynomial

I try to compute the roots of $$p_4 = x^4 - 4 x^ 3 + 8 x^2 - 8 x + 4$$ Now Wolfram Alpha tells me this expression is the same as $$p_4=((x - 2) x + 2)^2$$ How do I see this? Is there any way to obtain this? Edit: I know it is $p_4=(x^2 - 2 x +…
MarcE
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finding the remainder of $f(x)$ when divided by $(x-1)(x-2)$

$f(x)\in \mathbb{R}[x]$ is a function that has a remainder of 2 when divided by $(x-1)$, and a remainder of 1 when divided by $(x-2)$. I know that the remainder of $f(x)$ when divided by $(x-1)(x-2)=x^2-3x+2$ needs to be $-x+3$ but I just don't know…
nono
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Check if polynomial has double root and find $\sum _{k=1}^{4024}\:\frac{1}{x_k}$

Consider the polynomial $P \in \mathbb R[X[, \: P(x) = (X^2 + X -1)^n - X, \: n\in \mathbb N, n\ge 2$ 1)Which is the number of values of $n$ so that $P$ has double roots ? I have found that $(X^2 -1) \:| \:P$ for $n = 2k +1, k \in \mathbb N^*$ if…
Liviu
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Polynomials with four distinct common rational roots

Let $P(x) = x^5 + a_1x^4 + a_2x^3+ a_3x^2+ a_4x + 14$ and $Q(x) = x^5 + b_1x^4 + b_2x^3+ b_3x^2+ b_4x + 42$ be polynomials with integral coefficients. If $P(x)$ and $Q(x)$ have four distinct common rational roots. Find all possible $Q(x)$. Please…
user403160
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The variable line $y=3x+b$ with gradient $3$ meets the circle $x^2+y^2=16$ at A and B. Find the locus of the midpoint M of AB.

The variable line $y=3x+b$ with gradient $3$ meets the circle $x^2+y^2=16$ at A and B. Find the locus of the midpoint M of AB. So far I have tried to solve the equation simultaneously $10x^2+6bx+(b^2-16)$ and I have found $x=\frac{-3b}{10}$ using…
kjhg
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The number of polynomial of form $x^3+ax^2+bx+c$ which are divisible by $x^2+1$ and where a,b,c belongs to {1,2,...10}, is?

How exactly should I approach this problem? There could be many possible values a, b and c from the set is there any simple method?
Iti Shree
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Factor $ab^3-ac^3+bc^3-ba^3+ca^3-cb^3$

a) Use the remainder theorem to prove that $(a+b+c)$ is a factor of $(a^3+b^3+c^3-3abc)$ . Then find the other factor. b) Hence factor $(ab^3-ac^3+bc^3-ba^3+ca^3-cb^3)$ So far I have managed to find the other remainder being…
kjhg
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Polynomial problems

First problem: Let $P \in \mathbb R[X], P(x) = x^3 + ax^2 + bx + c$ a polynomial with the roots $x_1, x_2, x_3, \:\:x_1 \neq x_2 \neq x_3$. For $Q \in \mathbb R[X]$ a first degree polynomial, the sum…
Liviu
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How to do junior math Olympiad question

Let $a$ and $b$ be such that $0
vishnu
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Finding remainder on division of polynomial

Let $P(x)$ be a polynomial which when divided by $x-3$ and $x-5$ leaves remainders $10$ and $6$ respectively. If $P(x)$ is divided by $(x-3)(x-5)$ then remainder is: I assumed $P(x)=Q(x)\cdot (x-3)+10=R(x)\cdot (x-5)+6$ but it hasn't worked. Any…