Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

26755 questions
1
vote
2 answers

Is this valid? Show that $(x-2)\mid x^{3} - 4x$

Is this valid? Here $\textsf{R}(x)$ stands for the remainder. Show that $(x-2)\mid x^{3} - 4x$ I know that I can simply do this: Let $p(x) = x^{3} - 4x$ then if $(x-2)\mid x^{3} - 4x$ it follows that $p(2) = 0$. So we have $2^{3} - 4(2) = 0$.…
1
vote
5 answers

Finding an unknown coefficient of a polynomial given a factor

Q:Find the value of $a$ given that $x^2+1$ is a factor of $x^4-3x^3+3x^2+ax+2$ No idea where to start, I was going to use the factor theorem but it didn't work out. Question from year 10 Cambridge maths textbook
kjhg
  • 691
1
vote
1 answer

If $x_1+ \cdots + x_n - 1$ divides a homogeneous polynomial $f$, then is $f$ necessarily the zero polynomial?

Let $f \in \mathbb{R}[x_1,\ldots, x_n]$ be a homogeneous real polynomial. Suppose that there exists a polynomial $h\in \mathbb{R}[x_1,\ldots, x_n]$ such that $$f = h \cdot (x_1 + \cdots + x_n - 1).$$ Is it true that $f = 0 $? Motivation. Suppose…
user17982
1
vote
1 answer

3rd degree polynomial in $\mathbb{Z}[X]$ that has no roots in $\mathbb{Z}$, but reducible in $\mathbb{Z}[X]$

I want to find a 3rd degree polynomial in $\mathbb{Z}[X]$ that has no roots in $\mathbb{Z}$, but reducible in $\mathbb{Z}[X]$. Tried to construct one as a product of two or three lower degree irreducible polynomials, but this won't work because one…
Xena
  • 3,853
1
vote
1 answer

Maximum degree of a polynomial $\sum\limits_{i=0}^n a_i x^{n-i}$ such that $a_i = \pm 1$ for every $i$, with only real zeroes

What is the maximum degree of a polynomial of the form $\sum\limits_{i=0}^n a_i x^{n-i}$ with $a_i = \pm 1$ for $0 \leq i \leq n$, such that all the zeros are real? How would I manipulate that scary sigma? I'm stuck. Solutions are greatly…
Yuna Kun
  • 1,221
1
vote
1 answer

Is $x^{-2x^2}$ a polynomial function

This might seem like a stupid question, but can $$x^{-2x^2}$$ be called a polynomial function? Thanks!
asdf
  • 177
1
vote
2 answers

Using the graph $g(x)$ to find intervals.

I am having a bit of a struggle with my one math question. https://i.stack.imgur.com/DE6OG.jpg I was able to find a) b) c) but now that it asks for g'(x) I am running into a wall. Could somebody help please. Thanks!
Franky
  • 47
1
vote
2 answers

Show that the polynomial $P(x)=(x^4+x^3-3x^2+x+2)^n$ has negative coefficients

Show that for any positive integer $n$, the polynomial $$P(x)=(x^4+x^3-3x^2+x+2)^n$$ has negative coefficients. For $n=1$ it is clear and for $n=2$ it's true because $$p(x)=x^8+2x^7-5x^6-4x^5+\cdots$$ which also have negative coefficients. But for…
math110
  • 93,304
1
vote
3 answers

Solving equation in three variables

please help me understand how the following equation with 3 variables and power of 2 is solved and what solution approach is the quickest. $$3y^2 - 3 = 0$$ $$4x - 3z^2 = 0$$ $$-6xz+ 6z = 0 $$
HGO HGO
  • 57
1
vote
2 answers

Coefficients of Product of Non-Constant Binomials

Let $a_k$ and $b_k$ be sequences of length $n$. Is there a closed form expression for the coefficients $c_k$ of $x^k$ for $k=0,...,n$ where, $\displaystyle\prod_{k=1}^n(a_kx+b_k)=\displaystyle\sum_{j=0}^n c_jx^j$ I realize that the term "sequences"…
1
vote
1 answer

Solving a cubic equation

I have a math problem in front of me, and after struggling three days with it, I cannot find the solution. I need to find the roots of this polynomial equation: $x^3+x^2+1=0$. Anyone have a solution to this? Any help is appreciated..
speci
  • 11
1
vote
9 answers

$ax^3+8x^2+bx+6$ is exactly divisible by $x^2-2x-3$, find the values of $a$ and $b$

Find the values of $a$ and $b$ for which the polynomial $ax^3+8x^2+bx+6$ is divisible by $x^2-2x-3$.
1
vote
0 answers

Does this function increase with $p$?

Let $\mathbf{a}\triangleq(a_k)_{k=1,2,\ldots,K}$, where $0
Dave
  • 576
1
vote
1 answer

Remainder theorem for polynomials

Trying to help my son out with a homework problem and not sure where I'm going awry. The question is What must be added to the polynomial f(x)= x^5 + x^4 + 3x^3 - 6x^2 - 4x + 8 so that the resulting polynomial is exactly divisible by g(x) = x -…
jerH
  • 145
1
vote
1 answer

$P(x)=\frac{x}{x+1}$ for $x=1,2,...,n$, find the value of $P(n+1)$.

I've recently come across this question and have no idea how to do it. Let $P(x)$ be a 11-degree polynomial such that $P(x)=\frac{1}{x+1}$ for $x=0,1,2,...11$ Find $P(12)$. I've tried using the general form of a polynomial but it's turning to long.…
R.D.
  • 93