Questions tagged [power-series]

Questions about the properties of functions of the form $\sum_{n=0}^{\infty}a_n (x-c)^n$, where the $a_n$ are real or complex numbers, and $x$ is real or complex.

A series of the form $$\sum_{n=0}^{\infty} a_n (x-c)^n$$ is called a power series, and can be used to expand functions. The center $c$ is often $0$ and the radius of convergence $R$ is given by $R = \left(\limsup\limits_{n\to\infty}\sqrt[n]{|a_n|}\right)^{-1}$.

Power series for some common functions are: \begin{align} \frac{1}{1-x}&=\sum_{n=0}^\infty x^n\quad(|x|\lt1)\\\ \ln(1+x)&=\sum_{n=0}^\infty\frac{(-1)^nx^{n+1}}{n+1}\quad(|x|\leq 1, x\neq -1)\\\ \arctan(x)&=\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{2n+1}\quad(|x|\leq 1,x\neq \pm i)\\\ \tan(x)&=\sum_{n=1}^{\infty}\frac{|B_{2n}|(4^n-1)4^n }{(2n)!}x^{2n-1}\quad(|x|< \pi/2)\\\ \sin(x)&=\sum_{n=0}^\infty\frac{(-1)^n x^{2n+1}}{(2n+1)!}\\\ \cos(x)&=\sum_{n=0}^\infty \frac{(-1)^n x^{2n}}{(2n)!}\\\ e^x &= \sum_{n=0}^\infty\frac{x^n}{n!}\\\ \end{align}

If convergence is not an issue or if you are working over a different domain than $\mathbb{R}$ or $\mathbb{C}$, consider using the tag instead.

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Find the expression for the sum of this power series: $\sum_{n=0}^{\infty} \frac{x^{n}}{(n+3)!} $

I'm a bit stuck on this problem. I supposed to find an expression for the sum of this power series $$\sum_{n=0}^{\infty} \frac{x^{n}}{(n+3)!} $$ I know I should use $$e^x=\sum_{n=0}^{\infty}\frac{x^n}{n!} $$ But then I get confused, and I don't how…
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How to find the radius of convergence of the power series $f(x)$

This power series $f(x)$ centered at $x=0$, and thats mean $\sum {a_n x^n }$ $$ f(x) = \frac{{x - 1}}{{x^2 - 2x + 5}}. $$ I found that the radius of convergence for this power series is: $R=\sqrt{5}$.
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Power Series Convergence from Terms

My homework wants me to find the interval of convergence and the radius of the power series, but it does not give the function, instead it gives the first 4 terms of the series. The terms are $-x^{9} + \frac{x^{11}}{8} - \frac{x^{13}}{27} +…
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I can't find similar worked questions anywhere, can someone help me with this Power Series Method for Differential Equations Question?

I am trying to figure out the Power Series Method for DE's with Initial Value Problems. In my Textbook, all of the Worked Examples have the form: y'' + p(x)y' + g(x)y = 0; y(0) = c1, y'(0) = c2 (just an example) The Questions I am struggling with…
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How to simplify this series?

I have the series $$ P_i = 1 = \bigg[1 + \frac{q}{p} + \bigg(\frac{q}{p}\bigg)^2 + \bigg(\frac{q}{p}\bigg)^3 + \cdots + \bigg(\frac{q}{p}\bigg)^{i-1} \bigg]P_1 $$ We have the boundary condition $$ P_N=1 $$ Apparently, if we assume $p\neq q$, we…
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Finding radius of convergence to a power series.

Given a power series $\sum_{n=0}^{\infty} a_nx^n$ satisfies: $$\ a_{n+2}+ ( n^2 -\alpha^2 )a_n = 0 $$ For all $\ n\geq 2 $ Assume $\ \alpha $ is an integer. What is the radius of convergence ofthe power series? I tried using the ratio test to…
Oscar
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Show that there exists $K > 0$ such that $|a_n y^n| \leq K$ for all $n \in \mathbb{N}$.

Let $f(x) = \sum^∞_{n=0}{a_n x^n}$ be a real power series for some sequence $(a_n)^∞_{n=0}$ of real coefficients. Suppose that for some $y ∈ R$, the series $f(y)$ is convergent. Show that there exists $K > 0$ such that $|a_n y^n| \leq K$ for all $n…
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roots of series $\sum_{n=1}^{\infty}a_nx^n$

I think if we have series $\sum_{n=1}^{\infty}a_nx^n$ and exist $a_n\neq0$ then series can have not more then countable number of roots, is it right? What theorem can proof it?
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Determine the interval of convergence for $\sum_{i=0}^\infty\frac{1+2^n}{1+3^n}x^n.$

Determine the interval of convergence: $$\sum_{i=0}^\infty \frac{1+2^n}{1+3^n}x^n$$ Using Ratio test I found: $$-\frac{3}{2}
Dani Che
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Rearrange Complex Power Series

How do I rearrange this power series: $$\sum_{n=1}^\infty\frac{e^{in}}{n^3}{(z^n-z^{-n})}$$ so that it can be expressed in the form of $$\sum_{n=0}^\infty\ a_n{(z-z_0)}^n $$
PTSONIC
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Find Taylor coefficients for complex function

Let $f\colon G\rightarrow\mathbb{C}$ be a complex valued function given by $f(z)=\exp(\frac{z}{1-z})$. Prove that the Taylor series' coefficients of $f$ at $0$ are $$a_0=1 \qquad \qquad a_n=\sum_{s=1}^n \frac{1}{s!} \binom{n-1}{s-1}$$ Thoughts: My…
CruZ
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What interval does this series converge for?

$$\sum_{n=2}^\infty \frac{x^n}{\frac{n}{\ln n}^\frac{n}{\ln n}}$$ What values of $x$ does this series converge for? And is there another formula for this series that can be used to make an analytic continuation of it?
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power series expansion and closed solution

given the series $$ \sum_{n=0}^{\infty} \frac{x^{n}}{an+b}=f(x) $$ so for any postive integer $ an+b $ is never 0 how could i get $ f(x) $ from this Taylor series ??
Jose Garcia
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Peculiar similarity

I am an experimental physicist and have a math question. There are two functions, one being $-1/\log(x)$ the other $\sqrt{x}/(1-x)$ which are remarkably similar in the domain ]0,1[. Does anybody have an idea why?