Questions tagged [power-series]

Questions about the properties of functions of the form $\sum_{n=0}^{\infty}a_n (x-c)^n$, where the $a_n$ are real or complex numbers, and $x$ is real or complex.

A series of the form $$\sum_{n=0}^{\infty} a_n (x-c)^n$$ is called a power series, and can be used to expand functions. The center $c$ is often $0$ and the radius of convergence $R$ is given by $R = \left(\limsup\limits_{n\to\infty}\sqrt[n]{|a_n|}\right)^{-1}$.

Power series for some common functions are: \begin{align} \frac{1}{1-x}&=\sum_{n=0}^\infty x^n\quad(|x|\lt1)\\\ \ln(1+x)&=\sum_{n=0}^\infty\frac{(-1)^nx^{n+1}}{n+1}\quad(|x|\leq 1, x\neq -1)\\\ \arctan(x)&=\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{2n+1}\quad(|x|\leq 1,x\neq \pm i)\\\ \tan(x)&=\sum_{n=1}^{\infty}\frac{|B_{2n}|(4^n-1)4^n }{(2n)!}x^{2n-1}\quad(|x|< \pi/2)\\\ \sin(x)&=\sum_{n=0}^\infty\frac{(-1)^n x^{2n+1}}{(2n+1)!}\\\ \cos(x)&=\sum_{n=0}^\infty \frac{(-1)^n x^{2n}}{(2n)!}\\\ e^x &= \sum_{n=0}^\infty\frac{x^n}{n!}\\\ \end{align}

If convergence is not an issue or if you are working over a different domain than $\mathbb{R}$ or $\mathbb{C}$, consider using the tag instead.

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Where does it come $\left[\sum_{n=0}^{\infty}x^n\right]' = \sum_{n=0}^{\infty}(n+1)x^n$

Where does it come $$\left[\sum_{n=0}^{\infty}x^n\right]' = \sum_{n=0}^{\infty}(n+1)x^n$$?
Andrej
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Can the radius of convergence be equal to $1$?

Suppose $a \in \mathbb{R}$ Can the function $ \ (1+x)^a=\sum_{n=0}^{\infty} \binom{a}{n} x^n=\sum_{n=0}^{\infty} \frac{a(a-1)(a-2) \cdots (a-n+1)}{n!}x^n$ have radius of convergence $ \ 1$ ? Answer: Let $R$ be the radius of convergence, then by…
MAS
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Isolate $x$ on finite geometric sum

How can I isolate $x$ in terms of $n$, considering the following restriction? $$1 = x + x^2 + x^3 + x^4 + … + x^n$$ For example $f(n=3) = 0.544$ Other hints: Only positive values of $x$ are accepted Approximated results are also valid
Evandro
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Sum of the First n Natural Numbers Power n

How would I estimate the sum of a series of numbers like this: $$1^n+2^n+\cdots+n^n$$
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Power series Convergence, same Coefficients, different Powers

If $g(z) = \sum_{n \in \mathbb{N}} a_n \cdot (z-z_0)^n$ converges absolutely, how can I formally prove that $f(z) = \sum_{n \in \mathbb{N}} a_n \cdot (z-z_0)^{n-1}$ also converges absolutely? I know that the $\frac{d}{dz} g(z) = \sum_{n \in…
Friedrich
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Define the concepts of a convergent series and an absolutely convergent series.

Define the concepts of a convergent series and an absolutely convergent series. For which $a ∈ \mathbb R$ number $$\sum_{n=1}^{\infty}{\frac{(-1)^{n}}{n^a}}$$ on is convergent, and for which it converges absolutely? I want to use d'Alebert for…
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Can someone explain graphically Taylor Remainder Theorem?

Taylor Remainder Theorem is $$|R_n| = \frac{M}{n+1}|x-a|^{n+1}$$ Well, can someone explain this to me more graphically? If $M$ is some number slightly bigger than the $(n+1)^{th}$ order of derivative of original function, well, it seem very close…
강승태
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What does in Taylor series, what does "Taylor polynomial of f at a" actually mean?

For example, I thought Taylor polynomial of cosine centered at $\frac{\pi}{2}$ meant $\cos (x-\frac{\pi}{2})$. But when expanded with $(x-\frac{\pi}{2})^n$, of which $T_3$ becomes $-(x-\frac{\pi}{2}) + \frac{1}{3!}(x-\frac{\pi}{2})^3$, it is closer…
강승태
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Taylor polynomial remainder theorem, why is $R_n^{n+1}(x) = f^{n+1}(x)$?

I am trying to grasp the concept of Taylor remainder. Online lecture taught me that in equation $R_n^{(n+1)}(x) = f^{(n+1)}(x) + T_n^{(n+1)}(x)$, $T_n^{(n+1)}(x)$ becomes zero because in general nth polynomial when taken derivative n+1 times becomes…
강승태
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Series that vanish for infintely many values

How to prove that if i got a series $f \in \mathbb{R}[X,Y]$ that vanishes for all $X,Y \in [-1,1]$ then all his coefficients must be $0$ ? Thank you for your answers.
user383659
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Series reversion with constant term

Suppose we have $y=k+ax+bx^2+cx^3...$ as an infinite series. In order to reverse this I have been taught that we can assume $y-k=z$ Let's suppose $x=Az+Bz^2+Cz^3...$ Where $A,B,C...$ are determined by their usual formulas. By substituting $y-k=z$…
user385287
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Find $i$ by formula ${F \over A}={{(1+i)^n-1}\over{i}}$

(Uniform Series Compound Amount - Annuity Converts a uniform amount (annuity) - to a future value) Find $i$ by formula ${F \over A}={{(1+i)^n-1}\over{i}}$ where $F$ = future value $A$ = uniform amount per period $i$ = interest rate $n$ = numbers…
Dima
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Radius of convergence of $\Sigma_{n=1}^{\infty} \frac{(n!)^2}{(2n)!} (x+8)^n$

The series is: $\Sigma_{n=1}^{\infty} \frac{(n!)^2}{(2n)!} (x+8)^n$ My attempt: let $a_n = \frac{(n!)^2}{(2n)!}$. Then $\rho = \lim_{n\rightarrow \infty} \vert \frac{a_{n+1}}{a_n} \vert = \frac{1}{4}$. Then the radius of convergence is $(-12,-4)$. I…
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Radius of Convergence of $\sum\frac{(n!)^3}{(3n)!}z^{3n}$

$$\sum_{n\ge 1}\frac{(n!)^3}{(3n)!}z^{3n}=\sum_{k=3n, n\ge 1}\frac{((k/3)!)^3}{k!}z^k.$$ The ratio test seems like a better option than the root test here, but $\frac{a_{k+1}}{a_{k}}$ is either $0$ or undefined. So the radius (the limsup) is taken…
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For which value of $ \ x \in \mathbb{R} \ $ the series $ \ \sum_{n=1}^{\infty} (-1)^n \frac{1}{x^2-n^2} \ $ converges?

For which value of $ \ x \in \mathbb{R} \ $ the series $ \ \sum_{n=1}^{\infty} (-1)^n \frac{1}{x^2-n^2} \ $ converges ? Answer: The series is $ \ \sum_{n=1}^{\infty} (-1)^n \frac{1}{x^2-n^2} \ $. It can be written as $ \ \sum_{n=1}^{\infty}…
MAS
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