Questions tagged [power-series]

Questions about the properties of functions of the form $\sum_{n=0}^{\infty}a_n (x-c)^n$, where the $a_n$ are real or complex numbers, and $x$ is real or complex.

A series of the form $$\sum_{n=0}^{\infty} a_n (x-c)^n$$ is called a power series, and can be used to expand functions. The center $c$ is often $0$ and the radius of convergence $R$ is given by $R = \left(\limsup\limits_{n\to\infty}\sqrt[n]{|a_n|}\right)^{-1}$.

Power series for some common functions are: \begin{align} \frac{1}{1-x}&=\sum_{n=0}^\infty x^n\quad(|x|\lt1)\\\ \ln(1+x)&=\sum_{n=0}^\infty\frac{(-1)^nx^{n+1}}{n+1}\quad(|x|\leq 1, x\neq -1)\\\ \arctan(x)&=\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{2n+1}\quad(|x|\leq 1,x\neq \pm i)\\\ \tan(x)&=\sum_{n=1}^{\infty}\frac{|B_{2n}|(4^n-1)4^n }{(2n)!}x^{2n-1}\quad(|x|< \pi/2)\\\ \sin(x)&=\sum_{n=0}^\infty\frac{(-1)^n x^{2n+1}}{(2n+1)!}\\\ \cos(x)&=\sum_{n=0}^\infty \frac{(-1)^n x^{2n}}{(2n)!}\\\ e^x &= \sum_{n=0}^\infty\frac{x^n}{n!}\\\ \end{align}

If convergence is not an issue or if you are working over a different domain than $\mathbb{R}$ or $\mathbb{C}$, consider using the tag instead.

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How do I find a power series for this function?

Given the function: $$f(x) =\frac{(11+x)}{(1-x)}$$ how would I find a power series representation? I started by rewriting the function as $$(11+x)\frac{(1)}{(1-x)}$$ and then arrived at $$(11+x)\sum_{i=0}^\infty x^n$$ But I am not sure how I would…
Derek
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Find a power series. centered at $x=-1$

I'm trying to find a power series, centered at $x=-1$ What do I have to do for next step? $f(x)=\frac{1}{2x-3} = \frac{1}{2(x+1)-2-3} = \frac{1}{5}[\frac{1}{\frac{2}{5}(x+1)-1}]$
devDNA
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Find a power series.

Find a power series for the function. $f(x) = \frac {6+x}{1-x} = (6+x)*\sum_{n=0}^{\infty}x^n=6\sum_{n=0}^{\infty}x^n + \sum_{n=0}^{\infty}x^{n+1}$ What do I have to do for the next step? Thank you.
devDNA
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Really Cool Power Series Coefficient Problem

Hi everyone :) We learnt what a power series is in class, but that coefficient thing is new. How do we find coefficients of power series using that equation? What do we do? If someone can help me with any hints on (a), that would be great. I'll do…
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Obtain power series expansion of $\frac{1}{(1+x)(1-2x)}$

Obtain power series expansion of $\frac{1}{(1+x)(1-2x)}$ and give the general term and radius of convergence.
user2250537
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Fining the radius of convergence of $\sum_{k=1} ^{\infty} \frac{2^k*z^{2k}}{k^2+k}$

I have been trying to get the radius of convergence of this expression $\sum_{k=1} ^{\infty} \frac{2^k*z^{2k}}{k^2+k}$ by using the ratio test. However I keep getting $\frac{1}{2}$ and the answers say the solution is $\frac{1}{\sqrt{2}}$, could…
urpi
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Write $\sum_{n=1}^\infty a_nx^{n-1} = 1+x+2x^2+3x^3+5x^4+8x^5+13x^6+21x^7+34x^8+55x^9+89x^{10}+... $ as a power series

Let $\sum_{n=1}^\infty a_nx^{n-1} = 1+x+2x^2+3x^3+5x^4+8x^5+13x^6+21x^7+34x^8+55x^9+89x^{10}+\ldots $ Use the ratio test to prove that f(x) converges if |x|< $\frac{1}{2}$ . Edit: $a_n$ in this case is a Fibonacci sequence
BB8
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Calculating $\sum_{n \geq 0} n^2 x^n$

My attempt so far: $$\sum_{n \geq 0} n^2 x^n = x \sum_{n \geq 0} n^2 x^{n-1} = x \sum_{n \geq 0} n (x^n)'$$ And now I've got stuck. How can I continue from now?
dash
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how to prove this statement related to radius of convergence

Suppose that the power series $$\sum b_nx^n$$ converges for $|x|$ less than or equal to $1$. Suppose that for some $s$ greater than $0$, $p(x)=0$ for all $|x|$ less than $s$. How to show that $b_n=0$ for all $n$ greater than equal to $1$?
kapil
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How To Determine The Radius of This Power Series

$$ \sum_{n\ge 0} (3+\cos n)x^n ; a_n = (3+\cos n) $$ I used d'Alembert : $$\lim_{n\to\infty}\frac{a_{n+1}}{a_n} = \lim_{n\to\infty} \frac{3+\cos(n+1)}{3+\cos n} $$ Nw I'm stuck With How To get Rid Of "cosine" functions which Doesn't have limits at…
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How to calculate sum of power series?

I'm trying to work out sum of this series $$1 + \frac{2}{2} + \frac{3}{2^2} + \frac{4}{2^3} + \ldots$$ I know one method is to do substitutions and getting the series into a form of a known series. So far I've converted the series into $$ 1 +…
Csbk
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Standard technique for fiddling with power series

I will try a standard technique for fiddling with power series. If $g(t) =\sqrt{f(t)} $, then, differentiating, $g'(t) =\frac {f'(t)}{2\sqrt{f(t)}} =\frac {f'(t)}{2g(t)} $ so $2g'(t)g(t) = f'(t) $. If $f(t) =\sum_{n \ge 0} a_n…
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The radius of convergence of a power series.

If I have a power series $$\sum_{j = 1}^{\infty}a_jx^{2j+1} = x\sum_{j = 1}^{\infty}a_jx^{2j} $$ Given that I have the radius of convergence $R$ of $$\sum_{j = 1}^{\infty}a_jz^{j}$$ where $z = x^2$ What can I say about the original series? This…
user197848
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Finding a region of convergence of a power series - two questions

1) $$ \Sigma _0 ^ \infty \frac{(-1)^n 3^n x^{2n} }{\sqrt{n^2+4}} $$ 2) $$ \Sigma_0 ^{\infty} \frac{(-1)^n (x+1)^{n+3} }{2^{2n}+n^5} $$ In the first one, I have tried using the Quotient test and obtained 1/3 as the limit. I am having trouble…
georgia
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