Mathematics Stack Exchange
Mathematics Stack Exchange

Questions tagged [roots]

Questions about the set of values at which a given function evaluates to zero. For questions about "square roots", "cube roots" and such, consider using the (radicals) and the (arithmetic) tag. For questions about roots of Lie algebras, use the (lie-algebra) tag instead.

Questions regarding values $x$, such that a function $f$ evaluates to zero at $x$. For questions about "square roots", "cube roots" and such, consider using the and the tag. For questions about roots of Lie algebras, use the tag instead.

6663 questions
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Can numbers as well as having roots in the Imaginary-Real plane also be said to have roots as quaternions or higher complex forms? If so how?

enter image description here This is an argand Diagram to show 2d Imaginary-real plane solutions to a said root of a number jut there to illustrate the normal complex solutions.
Rosco
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2 answers

Question about logs

For what values of $k$ will $kx^2 = \log(x)$ have exactly $1$ solution? Received this question from a friend who was asked this in an interview. I thought the answer was $k=0$ but this was wrong.
user534507
  • 13
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Mathematics Radical Numbers Problem

If, $$\frac{\sqrt 5+1}{\sqrt 2-1} = x $$ then, $$\frac{\sqrt 5-1}{\sqrt 2+1} = ? $$
abi
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1 answer

What is the nth root of a number

Given $$x = y^\frac{1}{ln y}$$ $$x = ?$$ Is x is the approximation of e ?
rome101
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2 answers

Find the root for the function $2+x^{2}-x^{3}$

How do we prove that the root for $$2+x^{2}-x^{3}$$ exits in the interval $[2,3]$??
onelessproblem
  • 383
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1 answer

Range of roots of the equation $e^{x}-ax-b=0$

The equation $e^{x}-ax-b=0$ (A) one real root if $a\le0$ (B) one real root if $b > 0, a\le0$ (C) two real roots if $a > 0, a log_ea ≥a-b$ (D) no real root if $a > 0, a log_ea
Samar Imam Zaidi
  • 8,800
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3 answers

False answer from an equation

If you have the equation $$ \left(\frac{1}{x}\right) + 1 = 0, $$ and you solve it like this $$ \left(\frac{1}{x}\right) + 1 = 0 $$ $$ \left(\frac{1}{x}\right) = -1 $$ $$ -x = 1 $$ $$ x = -1, $$ everything's good. But if you do it like…
user265554
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