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Problem: ABCD is a square, E and F are points on BC and CD respectively such that AE cuts the diagonal BD at G and FG is perpendicular to AE.

K is a point on FG such that AK=EF.

Find the measure of the angle EKF.

Progress

So far, I found that AG=FG, and that the angle EKF is an obtuse angle.

2 Answers2

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enter image description here

as i was unable to draw the picture i uploaded the whole solution

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Hint: Show that $\triangle AKG$ and $\triangle FEK$ are congruent. What is $\angle GKE$?

Quang Hoang
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