if the odds of seeing at least one shooting star in an hour is 90% - what is the probability of seeing at least one shooting star in 20 minutes
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Could you perhaps add what you think the obvious answer would be and why you think it's wrong to the post? That would make this a much better question. – Milo Brandt Nov 04 '14 at 02:49
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Consider three consecutive $20$ minute periods. Let $A$ be the event we see at least one shooting star in the first $20$ minute period, $B$ the event we see at least one in the second period, and $C$ the event we see at least one in the third period.
It is reasonable to suppose that $A,B,C$ are independent and equally likely. Let $p$ be the probability of $A$. Then the probability of not seeing a shooting star in the one hour period is $(1-p)^3$.
We are told that the probability of not seeing a shooting star in one hour is $0.10$, Thus $(1-p)^3=0.10$, and therefore $$p=1-(0.10)^{1/3}.$$
André Nicolas
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