Can anyone think of an expression that is equal to its dual ? I've been trying to solve this for the past 2 hours, but nothing comes to mind.
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According to Wiki : Boolean algebra : Duality principle : $(x∧y) ∨ (y∧z) ∨ (z∧x)$. I think that it needs quite a lot of patience to check it... – Mauro ALLEGRANZA Nov 10 '14 at 13:31