For homework a question related to Venn diagrams is 'Are the probabilities of having not used a spinner and not tossed a coin in the game mutually exclusive' Don't know what is meant by it so can't answer it with out your help
3 Answers
Two things ("events") are mutually exclusive if it is impossible for both to happen at the same time. For example, turning left and turning right are mutually exclusive.
A more probability-oriented example (with dice!) would be rolling a 6 and rolling an odd number. These are mutually exclusive. However, rolling a 6 and rolling an even number are not mutually exclusive.
As you are talking about Venn Diagrams, you might be thinking about "sample spaces" for events. For example,
the sample space of even numbers (obtainable from rolling a die) is $E_{\text{even}}=\{2, 4, 6\}$, and $E_{\text{even}}\cap\{6\}=\{6\}$: The intersection of the sample spaces is non-empty. This means that the events are not mutually exclusive.
the sample space of odd numbers (obtainable from rolling a die) is $E_{\text{odd}}=\{1, 3, 5\}$, and $E_{\text{odd}}\cap\{6\}=\emptyset$: The intersection of the sample spaces is empty. This means that the events are mutually exclusive.
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Hint: two events are mutually exclusive if the occurrence of any one of them implies the non-occurrence of the other, or more formally if their intersection is empty. How can this concept be applied to the probabilities of having not used a spinner and not tossed a coin?
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Two events, say $A$ and $B$, are mutually exclusive if and only if their intersection is empty: $A \cap B = \{\}$. This can be expressed alternatively as $|A \cap B| = 0$, or, in the language of a probabilist, $P (A \cap B) = 0$.