There are various ways of describing the parameters of the gamma, so you may have to modify the notation below.
If the gamma is described using the shape parameter $\alpha$ and the rate parameter $\beta$, then we have
$$E(X)=\frac{\alpha}{\beta}\quad\text{and}\quad \text{Var}(X)=\frac{\alpha}{\beta^2}.\tag{1}
$$
These are standard formulas that I assume you are not expected to prove.
Suppose that $E(X)$ is fixed. Then $\beta=\frac{\alpha}{E(X)}$ and therefore
$$\text{Var}(X)=\frac{(E(X))^2}{\alpha}.\tag{2}$$
It is immediate from (2) that as $\alpha$ increases the variance decreases.
The above formulas can be used to calculate the parameters of the gamma when expectation and variance are given. If your version of the gamma uses a scale parameter, use the fact that the scale parameter is the reciprocal of the rate parameter.